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Oracle 1z1-071 exam consists of 73 multiple-choice questions, and the time allotted for completion is two hours. 1z0-071 Exam covers a wide range of topics, including SQL data retrieval, manipulation, and reporting, as well as database objects and structures, data integrity, and transactions.

Oracle Database SQL Sample Questions (Q41-Q46):

NEW QUESTION # 41
In your session, the NLS._DAE_FORMAT is DD- MM- YYYY.There are 86400 seconds in a day.Examine this result:
DATE
02-JAN-2020
Which statement returns this?

A. SELECT-TO_CHAR(TO _DATE('29-10-2019'+ INTERVAL '2' MONTH+INTERVAL '4' DAYINTERVAL '120' SECOND, 'DD-MON-YY') AS "daTe" FROM DUAL;
B. SELECT TO_ CHAR(TO_ DATE('29-10-2019') +INTERVAL '2'; MONTH + INTERVAL '5'; DAY - INTERVAL '86410' SECOND, ' DD-MON-YYYY') AS "date" FROM DUAL;
C. SELECT TO_ CHAR(TO_ DATE('29-10-2019') + INTERVAL '3' MONTH + INTERVAL '7' DAY - INTERVAL '360' SECOND, ' DD-MON-YYYY') AS "date" FROM DUAL;
D. SELECT-TO_CHAR(TO _DATE('29-10-2019'+ INTERVAL '2' MONTH+INTERVAL '6' DAYINTERVAL '120' SECOND, 'DD-MON-YY') AS "daTe"FROM DUAL;
E. SELECT To CHAR(TO _DATE('29-10-2019') + INTERVAL '2' NONTH + INTERVAL '5' DAY INEERVAL '120' SECOND, ' DD-MON-YYY) AS "date" FROM DUAL;

Answer: E

NEW QUESTION # 42
Examine these statements and results:
SQL> SELECT COUNT(*) FROM emp
COUNT(*)
---------------------
14
sQL> CREATE GLOBAL TEMPORARY TABLE t emp As SELECT * FROM emp;
Table created
SQL> INSERT INTo temp SELECT * FROM emp;
14 rows created
SQL> COMMIT:
Commit complete*
SQL> INSERT INTo temp SELECT * EROM emp;
14. rows created
SQL> SELECT COUNT(*) FROM t emp
How many rows are retrieved by the last query?

A. 0
B. 1
C. 2
D. 3

Answer: C

Explanation:
Global temporary tables in Oracle Database are designed to hold temporary data for the duration of a session or a transaction.
Given that the global temporary table is created and then populated twice from the emp table without any mention of data deletion, one would initially think the count would be 28, since 14 rows are inserted twice. However, if the temporary table was created with the default ON COMMIT DELETE ROWS option, the rows are deleted at the end of the transaction, which is signified by the COMMIT operation.
Thus, after the first COMMIT, the temporary table would be empty. After the second INSERT, another 14 rows would be added. So, the last query would retrieve 14 rows unless a DELETE operation was committed.
Reference:
Oracle Documentation on Temporary Tables: https://docs.oracle.com/cd/B28359_01/server.111/b28310/tables003.htm#ADMIN11633 Please note that the actual number of rows retrieved by the last query could differ if there are any triggers, cascading deletes, or the table is defined differently than assumed in this context.

NEW QUESTION # 43
Which statement is true regarding the default behavior of the ORDER BY clause?

A. In a character sort, the values are case-sensitive.
B. NULLs are not included in the sort operation.
C. Numeric values are displayed in descending order if they have decimal positions.
D. Only columns that are specified in the SELECT list can be used in the ORDER BY clause.
E. Column aliases can be used in the ORDER BY clause.

Answer: A

Explanation:
Explanation
The ORDER BY clause performs case sensitive sorting with character values.

NEW QUESTION # 44
SCOTTis a user in the database.
Evaluate the commands issued by the DBA:

Which statement is true regarding the execution of the above commands?

A. Statement 3 would not execute because role and system privileges cannot be granted together in a single GRANTstatement.
B. Statement 1 would not execute because the WITH GRANToption is missing.
C. Statement 2 would not execute because system privileges and object privileges cannot be granted together in a single GRANTcommand.
D. Statement 1 would not execute because the IDENTIFIED BY <password>clause is missing.

Answer: C

NEW QUESTION # 45
Examine the structure of the members table:

Which query can be used to display the last names and city names only for members from the states MO and MI?

A. SELECT DISTINCT last_name, city FROM members WHERE state ='MO' OR state
='MI';
B. SELECT last_name, city FROM members WHERE state LIKE 'M%';
C. SELECT last_name, city FROM members WHERE state ='MO' AND state ='MI';
D. SELECT last_name, city FROM members WHERE state IN ('MO', 'MI');

Answer: D

NEW QUESTION # 46
......

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