Oracle 1z1-071시험대비최신버전자료 - 1z1-071최신업데이트버전덤프공부

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Oracle 1z1-071 Exam Syllabus Topics:

Section	Weight	Objectives
Topic 1: Working with Time Zones and Date/Time Data		- Time zone conversion functions - TIMESTAMP, INTERVAL data types
Topic 2: Aggregating Data Using Group Functions	10%	- GROUP BY and HAVING clauses - Handling NULLs in group functions - SUM, AVG, COUNT, MAX, MIN functions
Topic 3: Using Subqueries to Solve Queries		- Correlated subqueries for update/delete - Single-row and multi-row subqueries
Topic 4: Controlling User Access		- System and object privileges - Roles, granting and revoking privileges
Topic 5: Managing Views		- Updatable and read-only views - Create, modify and drop views
Topic 6: Restricting and Sorting Data	15%	- WHERE clause and filtering conditions - Substitution variables, DEFINE and VERIFY commands - ORDER BY clause and sorting rules - Operator precedence
Topic 7: Manipulating Data and Managing Transactions		- Multi-table inserts - Transaction control: COMMIT, ROLLBACK, SAVEPOINT - INSERT, UPDATE, DELETE, MERGE statements
Topic 8: Using SET Operators		- UNION, UNION ALL, INTERSECT, MINUS operators - Ordering results with set operations
Topic 9: Managing Tables and Constraints		- Temporary and external tables - Data types, creating/altering/dropping tables - Constraints: primary key, foreign key, unique, check, not null
Topic 10: Retrieving Data Using SQL SELECT Statement	20%	- SELECT statement syntax and usage - Column aliases, concatenation, literals and DISTINCT - Arithmetic operations and NULL handling
Topic 11: Managing Indexes, Synonyms and Sequences		- Create and use synonyms - Create and maintain indexes - Create and use sequences
Topic 12: Relational Database Concepts	10%	- Relationship between database and SQL - ERD and SQL statement mapping - Theoretical and physical aspects of relational databases
Topic 13: Conversion Functions and Conditional Expressions	10%	- Implicit and explicit data type conversion - TO_CHAR, TO_NUMBER, TO_DATE functions - NVL, NULLIF, COALESCE and CASE expressions
Topic 14: Displaying Data from Multiple Tables	15%	- Self-joins and outer joins - Equijoins and non-equijoins - Cartesian products
Topic 15: Using Single-Row Functions to Customize Output	20%	- Character, number, and date functions - Nested functions usage
Topic 16: Using Data Dictionary Views		- Retrieve metadata and object information

>> Oracle 1z1-071시험대비 최신버전 자료 <<

1z1-071최신 업데이트버전 덤프공부 - 1z1-071최신 업데이트 덤프

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최신 Oracle PL/SQL Developer Certified Associate 1z1-071 무료샘플문제 (Q11-Q16):

질문 # 11
Which statements are correct regarding indexes? (Choose all that apply.)

A. When a table is dropped, the corresponding indexes are automatically dropped.
B. Indexes should be created on columns that are frequently referenced as part of any expression.
C. A non-deferrable PRIMARY KEYor UNIQUE KEYconstraint in a table automatically creates a unique index.
D. For each DML operation performed, the corresponding indexes are automatically updated.

정답：A,C,D

설명：
Explanation/Reference:
References:
http://viralpatel.net/blogs/understanding-primary-keypk-constraint-in-oracle/

질문 # 12
The SALES table has columns PROD_IDand QUANTITY_SOLDof data type NUMBER.
Which two queries execute successfully? (Choose two.)
SELECT prod_id FROM sales WHERE quantity_sold > 55000 GROUP BY prod_id HAVING

A. SELECT prod_id FROM sales WHERE quantity_sold > 55000 AND COUNT(*) > 10 GROUP
B.
C. BY COUNT(*) > 10;
SELECT COUNT(prod_id) FROM sales GROUP BY prod_id WHERE quantity_sold > 55000;
D. COUNT(*) > 10;
SELECT prod_id FROM sales WHERE quantity_sold > 55000 AND COUNT(*) > 10 GROUP
E. BY prod_id HAVING COUNT(*) > 10;
SELECT COUNT(prod_id) FROM sales WHERE quantity_sold > 55000 GROUP BY prod_id;

정답：A,D

질문 # 13
View the Exhibit and examine the structure of the ORDERS table. The ORDER_ID column is the PRIMARY KEY in the ORDERS table.
Evaluate the following CREATE TABLE command:
CREATE TABLE new_orders(ord_id, ord_date DEFAULT SYSDATE, cus_id)
AS
SELECT order_id.order_date,customer_id
FROM orders;
Which statement is true regarding the above command?

A. The NEW_IDRDERS table would not get created because the column names in the CREATE TABLE command and the SELECT clause do not match.
B. The NEW_IDRDERS table would not get created because the DEFAULT value cannot be specified in the column definition.
C. The NEW_IDRDERS table would get created and only the NOT NULL constraint defined on the specified columns would be passed to the new table.
D. The NEW_IDRDERS table would get created and all the constraints defined on the specified columns in the ORDERS table would be passed to the new table.

정답：C

질문 # 14
View the exhibit and examine the description for the SALESand CHANNELStables.

You issued this SQL statement:

Which statement is true regarding the result?

A. The statement will execute and a new row will be inserted in the SALEStable.
B. The statement will fail because the VALUESclause is not required with a subquery.
C. The statement will fail because a subquery cannot be used in a VALUESclause.
D. The statement will fail because the subquery in the VALUESclause is not enclosed within single quotation marks.

정답：A

질문 # 15
Examine the description of the EMPLOYEES table

You write this failing statement:
SELECT dept_no AS department_id, MAX (salary) As max_sal
FROM employees
WHERE salary >10000
GROUP BY department_id
ORDER BY max_sal;
Which clause causes the error?

A. SELECT
B. ORDER BY
C. WHERE
D. GROUP BY

정답：D

설명：
In the SQL statement provided, the error is caused by the GROUP BY clause. In Oracle SQL, when using GROUP BY, the expression in the GROUP BY clause must match exactly the expression in the SELECT list. The GROUP BY clause should reference the column name dept_no as mentioned in the SELECT list, not the alias department_id which is defined within the same SELECT statement.
The corrected SQL statement should be:
SELECT dept_no AS department_id, MAX(salary) As max_sal FROM employees WHERE salary > 10000 GROUP BY dept_no -- Changed from 'department_id' to 'dept_no' ORDER BY max_sal; References:
* Oracle Documentation on GROUP BY clause: GROUP BY Clause

질문 # 16
......

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