JavaScript-Developer-I Exam Certification Cost - JavaScript-Developer-I Exam Brain Dumps

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Salesforce JavaScript-Developer-I Exam Overview:

Certification Vendor:Salesforce
Exam Name:Salesforce Certified JavaScript Developer I
Exam Number:JS-Dev-001
Real Exam Qty:60
Certificate Validity Period:1 year (maintenance required via Salesforce certification maintenance modules)
Available Languages:English
Exam Format:Multiple Select, Multiple Choice
Passing Score:65%
Related Certifications:Salesforce Certified Platform Developer I
Salesforce Certified Platform App Builder
Salesforce Certified JavaScript Developer I
Exam Price:USD 200 (may vary by region/tax)
Exam Duration:105 minutes
Recommended Training:Salesforce Developer Learning Paths
Salesforce Trailhead JavaScript Developer I Prep
Exam Registration:Salesforce Certification Registration (Webassessor)
Salesforce Credentials Page
Sample Questions:Salesforce JavaScript-Developer-I Sample Questions
Exam Way:Online proctored or onsite testing via Kryterion Webassessor
Pre Condition:No formal prerequisites, but familiarity with JavaScript and Salesforce platform development is strongly recommended.
Official Syllabus URL:https://trailhead.salesforce.com/credentials/javascriptdeveloper1

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Quiz 2026 JavaScript-Developer-I: Salesforce Certified JavaScript Developer (JS-Dev-101) Accurate Exam Certification Cost

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Salesforce JavaScript-Developer-I Certification Exam is designed to test an individual's knowledge of JavaScript and its implementation within the Salesforce platform. Salesforce Certified JavaScript Developer (JS-Dev-101) certification is ideal for developers who have experience with JavaScript and want to specialize in building custom applications on the Salesforce platform. JavaScript-Developer-I Exam consists of 60 multiple-choice questions and must be completed within 105 minutes.

Salesforce Certified JavaScript Developer (JS-Dev-101) Sample Questions (Q17-Q22):

NEW QUESTION # 17
A developer needs to test this function:
01 const sum3 = (arr) => (
02 if (!arr.length) return 0,
03 if (arr.length === 1) return arr[0],
04 if (arr.length === 2) return arr[0] + arr[1],
05 return arr[0] + arr[1] + arr[2],
06 );
Which two assert statements are valid tests for the function?
Choose 2 answers

Answer: A,D


NEW QUESTION # 18
A developer uses a parsed JSON string to work with user information as in the block below:
01 const userInformation = {
02 " id " : " user-01 " ,
03 " email " : " user01@universalcontainers.demo " ,
04 " age " : 25
05 };
Which two options access the email attribute in the object?

Answer: B,D

Explanation:
userInformation is a plain JavaScript object:
{
id: " user-01 " ,
email: " user01@universalcontainers.demo " ,
age: 25
}
You can access object properties in two standard ways:
* Dot notation : object.propertyName
* Bracket notation : object[ ' propertyName ' ]
Apply to each option:
* A. userInformation.email
* Correct dot notation; accesses " user01@universalcontainers.demo " .
* B. userInformation.get( " email " )
* .get() is a method on Map instances, not on plain objects.
* A regular object does not have a .get method; this would be TypeError.
* C. userInformation[ " email " ]
* Correct bracket notation; string " email " is used as the property key.
* Returns " user01@universalcontainers.demo " .
* D. userInformation[email]
* Here email is treated as a variable, not a string literal.
* Unless there is a variable named email defined with a value matching a property key, this will either:
* Throw a ReferenceError (if email is not defined), or
* Use the value of email as a computed key (not what is intended here).
* It is not the correct way to access the " email " property literal.
Therefore, the correct ways are:
The answer: A, C
Relevant concepts: object property access (. vs []), plain objects vs Map, literal property names vs computed property names.


NEW QUESTION # 19
Refer to the code below:
flag();
function flag() {
console.log( ' flag ' );
}
const anotherFlag = () = > {
console.log( ' another flag ' );
}
anotherFlag();
What is result of the code block?

Answer: A

Explanation:
Key points:
* Function declarations are hoisted (their definitions are available before the line where they appear).
* Function expressions assigned to const or let are not hoisted as callable functions, but here anotherFlag is only used after it is defined.
Step-by-step:
* flag(); at the top:
* flag is a function declaration defined later; due to hoisting, it is available.
* It logs ' flag ' .
* The declaration:
function flag() {
console.log( ' flag ' );
}
is already in effect (hoisted before execution).
* const anotherFlag = () = > { console.log( ' another flag ' ); } defines anotherFlag as an arrow function.
* anotherFlag(); is called after its definition; this is valid and logs ' another flag ' .
No errors occur. The console output is:
* flag
* another flag
So option D is correct.
Concepts: function hoisting, difference between function declarations and function expressions, execution order.


NEW QUESTION # 20
A developer wants to use a try...catch statement to catch any error that countSheep () may throw and pass it to a handleError () function.
What is the correct implementation of the try...catch?
A)

B)

C)

D)

Answer: D


NEW QUESTION # 21

Which code change should be done for the console to log the following when 'Click me!' is clicked'
> Row log
> Table log

Answer: D


NEW QUESTION # 22
......

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