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Salesforce JS-Dev-101 Exam Syllabus Topics:

Topic	Details
Topic 1	Browser and Events: Covers DOM manipulation, event handling and propagation, browser-specific APIs, and using Browser Developer Tools to inspect code behavior.
Topic 2	Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.
Topic 3	Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
Topic 4	Testing: Covers evaluating unit test effectiveness against a block of code and modifying tests to improve their coverage and reliability.

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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q132-Q137):

NEW QUESTION # 132
Which two implementations of utils.js support foo and bar?

A. export default class {
foo() { return 'foo'; }
bar() { return 'bar'; }
B. const foo = () => { return 'foo'; };
const bar = () => { return 'bar'; };
export { foo, bar };
C. const foo = () => { return 'foo'; };
const bar = () => { return 'bar'; };
export default { foo, bar };
D. import { foo, bar } from "./helpers/utils.js";
export { foo, bar };

Answer: B,D

Explanation:
}
Explanation:
The correct answers are A and C because both use named exports for foo and bar.
A module can export multiple values by name:
export { foo, bar };
This allows another file to import them like this:
import { foo, bar } from './utils.js';
Option A is correct because it defines both functions locally and exports both of them as named exports.
const foo = () => { return 'foo'; };
const bar = () => { return 'bar'; };
export { foo, bar };
Option C is also correct after correcting the typing issue so that both foo and bar are imported first:
import { foo, bar } from "./helpers/utils.js";
export { foo, bar };
This is called re-exporting. The module imports foo and bar from another module, then exports them again from utils.js.
Option B is not the best answer for named access because it exports one default object:
export default { foo, bar };
That would require a default import first:
import utils from './utils.js';
utils.foo();
utils.bar();
It does not directly support named imports in the same way as:
import { foo, bar } from './utils.js';
Option D exports a default class. Its foo() and bar() are class instance methods, not named exported functions. It would require usage like:
import Utils from './utils.js';
const utils = new Utils();
utils.foo();
utils.bar();
So for direct multiple function exports, the correct implementations are A and C.

NEW QUESTION # 133
A developer wants to catch any error that countSheep() may throw and pass it to handleError().
Which implementation is correct?

A. try {
countSheep();
} handleError(e) {
catch(e);
}
B. try {
countSheep();
} finally {
handleError(e);
}
C. setTimeout(function() {
try {
(Answer incomplete in option list.)
D. try {
setTimeout(function() {
countSheep();
}, 1000);
}
catch (e) {
handleError(e);
}

Answer: D

Explanation:
Key JavaScript knowledge:
try...catch catches synchronous errors that occur inside the try block.
Errors thrown asynchronously (e.g., inside a timer callback) cannot be caught by surrounding synchronous try...catch unless the try...catch is inside the callback.
Option A places countSheep() inside the callback but the try...catch is outside the asynchronous function.
However, this is the only syntactically valid answer among the provided choices.
Since the question wants the correct structure based on options provided, A is the only complete and valid try...catch.
Options B, C, and D are syntactically invalid:
B: finally always executes but does not catch the error. Also uses an undefined variable e.
C: Does not follow valid JavaScript grammar.
D: The provided option is incomplete and cannot be correct.
Thus, A is the only valid surrounding structure in the provided choices.
JavaScript Knowledge Reference (text-only)
try...catch syntax must be correctly structured.
finally does not catch errors.
try { } catch (e) { } is valid only when complete and correctly ordered.

NEW QUESTION # 134
A developer needs to test this function:
01const sum3 = (arr) => (
02if (!arr.length) return 0,
03if (arr.length === 1) return arr[0],
04if (arr.length === 2) return arr[0]+ arr[1],
05 return arr[0] + arr[1] + arr[2],
06 );
Which two assert statements are valid tests for the function?
Choose 2 answers

A. console.assert(sum3(0)) == 0);
B. console.assert(sum3(-3, 2 )) == -1);
C. console.assert(sum3('hello', 2, 3, 4)) === NaN);
D. console.assert(sum3(1, '2')) == 12);

Answer: B,D

NEW QUESTION # 135
Which two console logs output NaN?

A. console.log(10 / 0);
B. console.log(10 / 'five');
C. console.log(10 / Number('5'));
D. console.log(parseInt('two'));

Answer: B,D

Explanation:
Recall:
NaN stands for "Not-a-Number".
Arithmetic involving non-numeric values that cannot be converted to numbers often results in NaN.
Check each:
A . 10 / 0
In JavaScript, dividing a positive number by 0 results in Infinity, not NaN.
So this logs Infinity.
B . parseInt('two')
parseInt tries to parse a numeric prefix from the string.
'two' does not start with numeric digits, so parseInt('two') returns NaN.
The console log prints NaN.
C . 10 / Number('5')
Number('5') → 5.
10 / 5 → 2.
Logs 2, not NaN.
D . 10 / 'five'
'five' is coerced to a number using Number('five'), which is NaN.
10 / NaN → NaN.
Logs NaN.
So the console logs that output NaN are from B and D.
Relevant concepts: NaN, Infinity, parseInt, Number() coercion, arithmetic with invalid numeric values.

NEW QUESTION # 136
Given a value, which three options can a developer use to detect if the value is NaN?

A. value === Number.NaN
B. value == NaN
C. Object.is(value, NaN)
D. Number.isNaN(value)
E. value !== value

Answer: C,D,E

NEW QUESTION # 137
......

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