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MongoDB Certified DBA Associate Exam (C100DBA) is a certification exam designed for database administrators who work with MongoDB 4.4. C100DBA exam focuses on evaluating the knowledge and skills of candidates related to designing, deploying, maintaining, and securing MongoDB databases. C100DBA Exam is conducted online and consists of 60 multiple-choice questions that need to be answered within 90 minutes. C100DBA exam is available in English and costs $150.

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Free PDF MongoDB - C100DBA - Efficient MongoDB Certified DBA Associate Exam (Based on MongoDB 4.4) Test Objectives Pdf

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MongoDB C100DBA certification exam is an online, proctored exam that can be taken from anywhere in the world. It consists of 60 multiple-choice questions that must be completed within 90 minutes. To pass the exam, candidates must score at least 65%. C100DBA Exam Fee is $150 USD and includes one free retake if a candidate does not pass on their first attempt.

MongoDB Certified DBA Associate Exam (Based on MongoDB 4.4) Sample Questions (Q65-Q70):

NEW QUESTION # 65
You perform the following query on the sayings collection, which has the index
{ quote : "text" }:
Assuming the documents below are in the collection, which ones will the following query return? Check all that apply.
db.sayings.find( { $text : { $search : "fact find" } } )

A. { _id : 3, quote : "Nobody will ever catch me." }
B. { _id : 2, quote : "Find out if that fact is correct." }
C. { _id : 1, quote : "That's a fact, Jack." }

Answer: B,C

NEW QUESTION # 66
Which of the tags in a replica set configuration specify the operations to be read from the node with the least network latency?

A. primaryPreferred
B. netLatency
C. secondaryPreferred
D. nearest

Answer: D

NEW QUESTION # 67
What is the maximum size of a MongoDB document

A. 2 MB
B. 12 MB
C. 16 MB
D. There is no maximum size. It depends on the RAM.

Answer: C

NEW QUESTION # 68
Consider a contacts collection that contains these documents:
{ " _id " : 1, " name " : " Poppy " , " birthday " : " 03-09-1984 " }
{ " _id " : 2, " name " : " Ashley " , " birthday " : " 08-12-1990 " }
{ " _id " : 3, " name " : " Cleo " , " birthday " : " 11-02-1976 " }
What query returns the document where the field name is " Poppy " ?

A. db.contacts.find({ " Poppy " : 1 })
B. db.contacts.find({ " name " : " poppy " })
C. db.contacts.find({ " name " : " Poppy " })
D. db.contacts.find({ " name.Poppy " : 1 })

Answer: C

Explanation:
MongoDB equality filters use the form { field: value }. To return the document whose name field contains the exact string " Poppy " , the query therefore uses { name: " Poppy " }, as shown in option D. This shorthand equality syntax is equivalent to explicitly using $eq. Option B uses the correct field but the value is lowercase
" poppy " . Normal MongoDB string equality is case-sensitive unless a suitable collation or another case- insensitive technique is deliberately configured, so it does not match the displayed " Poppy " value. Option A uses name.Poppy as a dot-notation path. Dot notation is for accessing a nested field inside an embedded document, but here name stores a scalar string and has no nested Poppy field. Option C searches for a field literally named Poppy, which the sample documents do not contain. This question tests the basic field/value predicate syntax used by find(). The correct command is db.contacts.find({ " name " : " Poppy " }), making option D correct.
Study Guide reference/topic:MongoDB Architecture and Core Operations - find(), equality predicates, string matching, and dot notation.

NEW QUESTION # 69
Consider that you have a collection called population which has fields state and city. Which of the following query will calculate the population grouped by state and city?

A. db.population.aggregate( [{ $group: { _id: { city: "$city" },pop: { $sum: "$pop" } } }] )Multi Document Transaction is not supported by MongoDB
B. db.population.aggregate( [{ $group: { _id: { state: Estate", city: "$city" },pop: { $sum: "$pop" } } }] )
C. db.population.aggregate( [{ $group: { _id: { state: Estate", city: "$city" },pop: { $sum: 1 > > >] )
D. db.population.aggregate( [{ $group: { _id: { state: "$state", city: "$city" },pop: { $pop: 1 } } }] )

Answer: B

NEW QUESTION # 70
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