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| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I |
| Exam Number: | JS-Dev-001 |
| Exam Duration: | 105 minutes |
| Passing Score: | 65% |
| Real Exam Qty: | 60 |
| Related Certifications: | Salesforce Certified Platform App Builder Salesforce Certified Platform Developer I Salesforce Certified JavaScript Developer I |
| Available Languages: | English |
| Exam Format: | Multiple Select, Multiple Choice |
| Certificate Validity Period: | 1 year (maintenance required via Salesforce certification maintenance modules) |
| Exam Price: | USD 200 (may vary by region/tax) |
| Recommended Training: | Salesforce Developer Learning Paths Salesforce Trailhead JavaScript Developer I Prep |
| Exam Registration: | Salesforce Credentials Page Salesforce Certification Registration (Webassessor) |
| Sample Questions: | Salesforce JavaScript-Developer-I Sample Questions |
| Exam Way: | Online proctored or onsite testing via Kryterion Webassessor |
| Pre Condition: | No formal prerequisites, but familiarity with JavaScript and Salesforce platform development is strongly recommended. |
| Official Syllabus URL: | https://trailhead.salesforce.com/credentials/javascriptdeveloper1 |
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NEW QUESTION # 62
At Universal Containers, every team has its own way of copying JavaScript objects. The code snippet shows an implementation from one team:
What is the output of the code execution?
Answer: B
NEW QUESTION # 63
Refer to the code below:
01 x = 3.14;
02
03 function myFunction() {
04 ' use strict ' ;
05 y = x;
06 }
07
08 z = x;
09 myFunction();
Considering the implications of ' use strict ' on line 04, which three statements describe the execution of the code?
Answer: A,B,D
Explanation:
* Behavior of non-strict global code The script does not begin with a ' use strict ' directive at the top level, so the global code (outside any function) runs in non-strict (sloppy) mode.
* Line 01: x = 3.14; In non-strict mode, assigning to an undeclared identifier (no var, let, or const) creates an implicit global variable. So after line 01, x exists and equals 3.14.
* Line 08: z = x; This also runs in non-strict mode. Since x is already defined (from line 01), z is set to
3.14. Therefore, statement B is correct: z is equal to 3.14.
* Scope of ' use strict ' inside a function The line:
' use strict ' ;
inside myFunction is a directive prologue for that function, not for the entire file. This means:
* Strict mode applies only within the body of myFunction , from the directive to the end of that function.
* It does not retroactively affect code before the function or code outside of it.
Therefore:
* Statement A is incorrect: ' use strict ' is not "hoisted" to affect the whole file. It only affects the function body.
* Statement C is incorrect: strict mode does not apply from line 04 to the end of the file; it only applies within myFunction, not to global lines like 01, 08, or 09.
* Execution of myFunction in strict mode When myFunction is called on line 09:
function myFunction() {
' use strict ' ;
y = x;
}
Within this function:
* Strict mode is active for its body.
* In strict mode, assigning to an undeclared variable (like y here) is not allowed and results in a ReferenceError at runtime.
So line 05:
y = x;
throws a ReferenceError because y is not declared with var, let, or const.
Therefore, statement E is correct: line 05 throws an error.
* Why statement D is considered correct Statement D says: ' use strict ' has an effect only on line 05.
In terms of execution in this specific code:
* The only executable statement in myFunction that is affected by strict mode is the assignment on line
05.
* The directive itself on line 04 is not a "normal" runtime operation; it is a directive that sets the mode.
* There are no other statements inside the function that behave differently under strict mode; only the line that assigns to the undeclared variable shows a strict-mode effect.
So, describing the practical execution behavior of this snippet, strict mode manifests its effect only on line 05, making statement D correct in this context.
Summary of each option:
* A: Incorrect - strict does not apply to all lines in the file.
* B: Correct - z becomes 3.14 in non-strict global code.
* C: Incorrect - strict does not affect code outside the function.
* D: Correct - in this code, the only behavioral effect of strict mode is on line 05.
* E: Correct - line 05 throws a ReferenceError due to assignment to undeclared y under strict mode.
JavaScript knowledge references (descriptive, no links):
* In non-strict (sloppy) mode, assigning to an undeclared identifier creates a global variable.
* ' use strict ' inside a function body enables strict mode for that function only.
* In strict mode, assigning to an undeclared variable results in a ReferenceError.
* Directive prologues ( ' use strict ' ) affect only their containing function or script, not other scopes.
NEW QUESTION # 64
Given a value, which three options can a developer use to detect if the value is NaN?
Answer: B,C,D
Explanation:
In JavaScript, NaN has some special properties:
* NaN is not equal to anything, including itself.
* Equality operators (==, ===) do not work for detecting NaN.
Check each option:
* A. value === Number.NaN
* Number.NaN is just NaN.
* But NaN === NaN is always false.
* So this expression is never true and cannot be used to detect NaN.
* B. value == NaN
* Same issue. NaN == NaN is always false.
* So this also never detects NaN.
* C. Object.is(value, NaN)
* Object.is is a more precise equality comparison method.
* It treats NaN as equal to NaN: Object.is(NaN, NaN) is true.
* So Object.is(value, NaN) is a valid way to detect NaN.
* D. value !== value
* Because NaN is the only JavaScript value that is not equal to itself , value !== value is true only when value is NaN.
* This is a classic trick for NaN detection.
* E. Number.isNaN(value)
* Number.isNaN is the recommended modern way to check if a value is NaN without coercion .
* It returns true only if value is actually the number NaN.
Therefore, the three correct ways are:
* Object.is(value, NaN)
* value !== value
* Number.isNaN(value)
NEW QUESTION # 65
A developer needs to debug a Node.js web server because a runtime error keeps occurring at one of the endpoints.
The developer wants to test the endpoint on a local machine and make the request against a local server to look at the behavior. In the source code, the server.js file will start the server. The developer wants to debug the Node.js server only using the terminal.
Which command can the developer use to open the CLI debugger in their current terminal window?
(With corrected typing errors: node_inspect # node inspect, node_start_inspect # node start inspect.)
Answer: C
Explanation:
Node.js includes a built-in command-line (CLI) debugger . To use it directly in the terminal, the standard command is:
node inspect server.js
This:
* Starts server.js under the Node.js inspector.
* Opens the CLI debugger right in the terminal window where you ran the command.
* Lets you interactively:
* Step through code
* Set breakpoints
* Inspect variables
* Continue execution, etc.
Why B is correct:
Option B (corrected to node inspect server.js) is exactly the standard Node.js command to run a script under the CLI debugger in the current terminal.
* It does not rely on any external GUI tools.
* You stay entirely in the terminal to debug.
Why the other options are incorrect:
* A. node start inspect server.js
* There is no start subcommand like this in standard Node.js CLI.
* This is not a valid Node.js debugging command.
* C. node server.js --inspect
* This starts Node.js with the Inspector protocol enabled and is typically used to connect external tools like Chrome DevTools or VS Code.
* It does not open the CLI debugger in the current terminal. Instead, it opens a debugging port that other tools attach to.
* The question specifically says "only using the terminal" and "open the CLI debugger in their current terminal window", which points to node inspect, not --inspect.
* D. node -i server.js
* -i starts Node in interactive REPL mode , optionally after running a script.
* This is for an interactive shell, not the Node debugger.
* It does not provide breakpoint/step/next/continue debugging features like the CLI debugger.
Therefore, the only option that opens the Node.js CLI debugger in the current terminal is:
The answer: B
JavaScript / Node.js knowledge / Study Guide references (concept names only, no links):
* Node.js CLI debugger: node inspect < script >
* Node.js inspector protocol: node --inspect
* Difference between CLI debugger and DevTools-based debugging
* Node.js command-line options and subcommands
NEW QUESTION # 66
Teams at Universal Containers (CU) work on multiple JavaScript projects at the same time. UC us thinking about reusability and how each team can benefit from the work of others.
Going open-source or public is not an option at this time.
Which option is available to UC with npm?
Answer: A
NEW QUESTION # 67
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