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WGU Applied-Probability-and-Statistics Exam Syllabus Topics:

SectionWeightObjectives
Topic 1: Probability Concepts20%- Probability rules, independent and dependent events
- Conditional probability and Venn diagrams
- Discrete and continuous probability distributions
- Normal distribution and empirical rule
Topic 2: Inferential Statistics & Study Design20%- Observational studies vs experiments
- Hypothesis testing framework and interpretation
- Confidence intervals for means/proportions
- Sampling methods and bias
Topic 3: Correlation & Regression20%- Correlation coefficient and interpretation
- Predictions and limitations of regression
- Simple linear regression models
- Interpreting slope, intercept, and R-squared
Topic 4: Descriptive Statistics25%- Measures of spread: range, IQR, variance, standard deviation
- Graphical displays: histograms, boxplots, scatterplots
- Measures of center: mean, median, mode
- Types of data: categorical, discrete, continuous
Topic 5: Basic Numeracy & Algebra15%- Exponents, roots, and basic formulas
- Arithmetic operations, fractions, decimals, percentages
- Linear equations, inequalities, graphing functions

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WGU Applied Probability and Statistics (FZO1 C955) Sample Questions (Q143-Q148):

NEW QUESTION # 143
Two independent events: P(A and B) = ?

Answer: C

Explanation:
For independent events, the probability that both events occur is the product of their individual probabilities.
The rule is P(A and B) = P(A) × P(B). Independence means that the occurrence of one event does not change the probability of the other. For example, if a coin is tossed and a die is rolled, the probability of heads and rolling a 4 is 1/2 × 1/6 = 1/12. Option B is an addition expression used in "or" problems, not "and" problems.
Option C applies to mutually exclusive events, not independent events. Option D would mean both events are certain to occur together, which is not generally true. The word "and" signals intersection, and independence allows the intersection to be calculated by multiplication. Study Guide references/topics: independent events, multiplication rule, joint probability, compound probability.


NEW QUESTION # 144
In a game, a coin is tossed, and a spinner with 8 equal spaces numbered 1 through 8 is spun.
What is the probability of getting heads on the coin and a number less than 3 on the spinner?

Answer: D

Explanation:
This experiment has two independent stages: tossing a coin and spinning a numbered spinner. The probability of getting heads on a fair coin is 1/2. The spinner has 8 equally likely outcomes numbered 1 through 8. A number less than 3 means either 1 or 2, so there are 2 favorable spinner outcomes out of 8 total outcomes.
Thus, P(number less than 3) = 2/8 = 1/4. Since the coin result does not affect the spinner result, the events are independent. For independent events connected by "and," multiply the probabilities: 1/2 × 1/4 = 1/8.
Equivalently, the combined sample space has 2 coin outcomes times 8 spinner outcomes, or 16 total equally likely outcomes. The favorable outcomes are heads with 1 and heads with 2, giving 2/16 = 1/8. References
/topics from the Study Guide: independent events, sample spaces, multiplication rule, theoretical probability.


NEW QUESTION # 145
Poisson distribution mean = ?

Answer: B

Explanation:
For a Poisson distribution, the mean is #, pronounced "lambda." The parameter # represents the expected number of events occurring in a fixed interval, such as calls per hour, defects per batch, or arrivals per minute.
A defining feature of the Poisson distribution is that both the mean and variance are equal to #. Therefore, if X follows a Poisson distribution with # = 4, then the expected value, or mean, is 4, and the variance is also 4.
Option B and option C are only correct in special cases where # happens to equal 0 or 1, not generally. Option D is conceptually related because the Poisson variance equals #, but the question asks for the mean, and the parameter name is #. The Poisson distribution is used for discrete counts of events over a fixed interval under a constant average rate. Study Guide references/topics: Poisson distribution, expected value, variance, # parameter.


NEW QUESTION # 146
A standard deck of 52 playing cards, 13 with hearts, 13 with diamonds, 13 with clovers, and 13 with spades, is shuffled, and one card is drawn at random.
What is the probability of drawing a heart?

Answer: C

Explanation:
The probability of a simple event is calculated by dividing the number of favorable outcomes by the total number of equally likely outcomes. A standard deck contains 52 cards. The favorable outcomes are the hearts, and the question states that there are 13 hearts in the deck. Therefore, the probability of drawing a heart is 13
/52. This fraction simplifies by dividing both numerator and denominator by 13, giving 1/4. Option A, 1/13, would incorrectly treat one card as favorable out of 13 rather than 13 favorable hearts out of 52 total cards.
Option B, 1/2, would imply that half the deck consists of hearts, which is false. Option D, 1/3, does not correspond to the four equally sized suits in a standard deck. Since the four suits are equally represented, each suit has probability one out of four. References/topics from the Study Guide: theoretical probability, equally likely outcomes, fractions, sample spaces.


NEW QUESTION # 147
A class of 25 students includes 10 who play soccer, 8 who play basketball, and 7 who play neither sport.
What is the probability of randomly selecting a student who does not play soccer?

Answer: A

Explanation:
The probability of selecting a student who does not play soccer is found by identifying the complement of the soccer group. There are 25 students in the class, and 10 students play soccer. Therefore, the number of students who do not play soccer is 25 # 10 = 15. The probability is then the number of favorable outcomes divided by the total number of possible outcomes: 15/25 = 0.60. The information about basketball and neither sport provides context, but the direct complement method is sufficient because the question asks only who does not play soccer. Option B, .40, represents the probability of selecting a student who does play soccer, since 10/25 = .40. Option A, .30, is associated with neither sport if interpreted approximately from 7/25, but it is not the requested event. Option C, .50, does not match the count structure. References/topics from the Study Guide: probability, complements, favorable outcomes, relative frequency.


NEW QUESTION # 148
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