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| Section | Objectives |
|---|---|
| Browser and DOM Interaction | - Browser APIs (fetch, storage, timers) - Event handling and propagation - DOM manipulation and traversal |
| Testing and Debugging | - Debugging techniques and tools - Unit testing principles |
| Asynchronous JavaScript | - Promises and async/await - Event loop and concurrency model - Error handling in async workflows |
| JavaScript Language Fundamentals | - ES6+ syntax and features - Functions, scope, and closures - Data types, variables, and operators |
| Salesforce Platform Integration | - Calling Apex methods from JavaScript - Lightning Web Components (LWC) JavaScript usage - Security considerations in Salesforce JavaScript |
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NEW QUESTION # 74
A class was written to represent regular items and sale items. Code:
01 let regItem = new Item( ' Scarf ' , 55);
02 let saleItem = new SaleItem( ' Shirt ' , 80, .1);
03 Item.prototype.description = function() { return ' This is a ' + this.name; }
04 console.log(regItem.description());
05 console.log(saleItem.description());
06
07 SaleItem.prototype.description = function() { return ' This is a discounted ' + this.name; }
08 console.log(regItem.description());
09 console.log(saleItem.description());
What is the output?
Answer: A
Explanation:
* At line 03, the developer assigns:
Item.prototype.description = function() { return ' This is a ' + this.name; } This affects all objects whose prototype chain includes Item.prototype .
* regItem inherits from Item # gets this method.
* saleItem, as an instance of SaleItem, also inherits Item.prototype (since SaleItem uses prototype inheritance from Item), so it also has this method at this moment.
Outputs at lines 04 and 05:
* regItem.description() # " This is a Scarf "
* saleItem.description() # " This is a Shirt "
* At line 07, the developer overrides the method on SaleItem.prototype :
SaleItem.prototype.description = function() {
return ' This is a discounted ' + this.name;
}
From this point:
* regItem still uses the Item.prototype version
* saleItem uses the overridden SaleItem.prototype version
Outputs at lines 08 and 09:
* regItem.description() # " This is a Scarf "
* saleItem.description() # " This is a discounted Shirt "
Combining all results:
This is a Scarf
This is a Shirt
This is a Scarf
This is a discounted Shirt
This matches option B .
JavaScript Knowledge References (text-only)
* Objects created from constructor functions use prototype chaining.
* Overriding a subclass prototype method does not affect the parent class prototype.
* Instances inherit the most specific version of the method on their prototype chain.
NEW QUESTION # 75
Refer to the code below:
Const searchTest = 'Yay! Salesforce is amazing!" ;
Let result1 = searchText.search(/sales/i);
Let result 21 = searchText.search(/sales/i);
console.log(result1);
console.log(result2);
After running this code, which result is displayed on the console?
Answer: B
Explanation:
NEW QUESTION # 76
At Universal Containers, every team has its own way of copying JavaScript objects. The code snippet shows an implementation from one team:
What is the output of the code execution?
Answer: D
NEW QUESTION # 77
Given the following code:
01 let x = null;
02 console.log(typeof x);
What is the output of line 02?
Answer: A
Explanation:
This question focuses on the typeof operator and how JavaScript represents the type of the value null.
* Declaration on line 1:
let x = null;
Here:
* x is explicitly assigned the value null.
* In JavaScript, null is a special primitive value that represents "no value" or "empty value".
* Line 2:
console.log(typeof x);
The typeof operator returns a string indicating the type of the operand. For example:
* typeof 1 returns " number "
* typeof " hello " returns " string "
* typeof true returns " boolean "
* typeof undefined returns " undefined "
* typeof {} returns " object "
* typeof [] returns " object " (arrays are objects)
* typeof function() {} returns " function "
For null, due to an early design decision in JavaScript, the result is:
typeof null === " object "
This is a known historical quirk of the language:
* Although null is a primitive and conceptually means "no object", typeof null returns the string " object "
.
Therefore, typeof x when x is null evaluates to " object " .
So on line 2, the value printed is:
" object "
This matches option A.
The incorrect options are:
* B. " undefined " : would be typeof x if x were undefined, not null.
* C. " x " : typeof returns a string describing the type of the value, not the variable name.
* D. " null " : although intuitive, JavaScript does not return " null " for typeof null; it returns " object " instead.
Therefore, the correct answer is:
The answer: A
JavaScript knowledge / study guide reference concepts:
* typeof operator and its return values
* Primitive types in JavaScript (null, undefined, number, string, boolean, symbol, bigint)
* Historical behavior: typeof null returning " object "
* Difference between null and undefined in JavaScript
NEW QUESTION # 78
A developer wrote a fizzbuzz function that when passed in a number, returns the
following:
● 'Fizz' if the number is divisible by 3.
● 'Buzz' if the number is divisible by 5.
● 'Fizzbuzz' if the number is divisible by both 3 and 5.
● Empty string if the number is divisible by neither 3 or 5.
Which two test cases will properly test scenarios for the fizzbuzz function?
Choose 2 answers
Answer: A,C,D
NEW QUESTION # 79
......
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