Updated Salesforce - JavaScript-Developer-I - Valid Salesforce Certified JavaScript Developer (JS-Dev-101) Test Labs
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Achieving the Salesforce Certified JavaScript Developer I certification is a great way to demonstrate your expertise in JavaScript and your ability to build custom applications that can be integrated with Salesforce. Salesforce Certified JavaScript Developer (JS-Dev-101) certification can help you stand out from other developers and can open up new career opportunities in the Salesforce ecosystem.
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Upon passing the Salesforce JavaScript-Developer-I Exam, candidates will be awarded the Salesforce Certified JavaScript Developer I certification. Salesforce Certified JavaScript Developer (JS-Dev-101) certification is a valuable asset for any developer who wants to showcase their expertise in Salesforce development and increase their chances of finding job opportunities in the field.
Salesforce Certified JavaScript Developer (JS-Dev-101) Sample Questions (Q34-Q39):
NEW QUESTION # 34
Given the HTML below:

Which statement adds the priority-account css class to the Applied Shipping row?
- A. document.querySelector('#row-as').classList.add('priority-account');
Answer: A
NEW QUESTION # 35
Refer to the following object:
const cat ={
firstName: 'Fancy',
lastName: ' Whiskers',
Get fullName() {
return this.firstName + ' ' + this.lastName;
}
};
How can a developer access the fullName property for cat?
- A. cat.get.fullName
- B. cat.fullName
- C. cat.fullName()
- D. cat.function.fullName()
Answer: B
NEW QUESTION # 36
A developer imports:
import printPrice from ' /path/PricePrettyPrint.js ' ;
What must be true about printPrice for this import to work?
- A. printPrice must be a named export
- B. printPrice must be a multi export
- C. printPrice must be the default export
- D. printPrice must be an all export
Answer: C
Explanation:
The syntax:
import printPrice from ' module ' ;
means the module must export its function as a default export :
export default function printPrice() { ... }
Why the others are wrong:
* Named exports require curly braces:
* import { printPrice } from ' module ' ;
* "all export" and "multi export" are not JavaScript terms.
Therefore, printPrice must be the default export .
JavaScript Knowledge References (text-only)
* Default imports use: import name from ' module ' .
* Named imports require braces: import { name } from ' module ' .
NEW QUESTION # 37
let sampleText = " The quick brown fox jumps " ;
Which three expressions return true for a substring?
- A. sampleText.indexOf( ' fox ' ) !== -1;
- B. sampleText.indexOf( ' quick ' ) > -1;
- C. sampleText.includes( ' fox ' );
- D. sampleText.indexOf( ' Quick ' ) !== -1;
- E. sampleText.include( ' fox ' ) !== -1;
Answer: A,B,C
Explanation:
The correct answers are A, B, and C .
The original variable name appears to contain a typing error. The variable should be used consistently as sampleText:
let sampleText = " The quick brown fox jumps " ;
A is correct because includes() checks whether a string contains a specific substring and returns a Boolean value:
sampleText.includes( ' fox ' );
Since " fox " exists inside " The quick brown fox jumps " , this returns:
true
B is correct after correcting the typing error. The correct expression is:
sampleText.indexOf( ' quick ' ) > -1;
indexOf() returns the index position where the substring is found. If the substring is not found, it returns -1.
Since " quick " exists in the string, sampleText.indexOf( ' quick ' ) returns a value greater than -1, so the expression returns:
true
C is correct after correcting the missing quotation marks and adding a Boolean comparison:
sampleText.indexOf( ' fox ' ) !== -1;
The substring " fox " exists in the string, so indexOf( ' fox ' ) does not return -1. Therefore, the expression returns:
true
D is incorrect because the method name is typed incorrectly. JavaScript string has includes(), not include().
Incorrect:
sampleText.include( ' fox ' )
Correct:
sampleText.includes( ' fox ' )
E is incorrect because JavaScript string matching is case-sensitive:
sampleText.indexOf( ' Quick ' ) !== -1;
The string contains " quick " with a lowercase q, not " Quick " with an uppercase Q, so this returns:
false
Therefore, the verified answers are A, B, and C .
NEW QUESTION # 38
Refer to the following array:
Let arr1 = [ 1, 2, 3, 4, 5 ];

Which two lines of code result in a second array, arr2 being created such that arr2 is not a reference to arr1?
- A. Let arr2 = arr1.slice(0, 5);
- B. Let arr2 = arr1.sort();
- C. Let arr2 = arr1;
- D. Let arr2 = Array.from(arr1);
Answer: A,D
NEW QUESTION # 39
......
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