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Huawei H12-811_V2.0 Exam Overview:

Certification Vendor:Huawei
Exam Name:HCIA-Datacom V2.0
Exam Number:H12-811_V2.0-ENU
Exam Duration:90 minutes
Real Exam Qty:60
Certificate Validity Period:3 years
Related Certifications:HCIA-Datacom
Exam Format:Multiple-response, Simulation, Drag-and-drop, Multiple-choice
Passing Score:600/1000
Exam Price:$200 USD
Available Languages:Chinese, English
Sample Questions:Huawei H12-811_V2.0 Sample Questions
Exam Way:Available at Pearson VUE test centers (offline) or online proctored exam.
Pre Condition:No prerequisites required; candidates can register directly.
Official Syllabus URL:https://e.huawei.com/en/talent/cert/#/cert/Details/68381b0d8e534a6a9339761047279030

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Huawei H12-811_V2.0 Exam Syllabus Topics:

TopicDetails
Topic 1
  • IP Technology Basics: Covers IPv4
  • IPv6 addressing, subnetting, routing fundamentals, and common routing protocols such as OSPF, RIP, and static routing.
Topic 2
  • WLAN Technology Basics: Covers wireless LAN standards, components such as APs and ACs, WLAN architecture, and basic configuration principles.
Topic 3
  • Ethernet Technology Basics: Covers Ethernet standards, switching principles, VLANs, and Layer 2 protocols used in enterprise network environments.
Topic 4
  • Data Center Network Basics: Covers the architecture and key technologies used in modern data center networks including virtualization and high-availability design concepts.

Huawei HCIA-Datacom V2.0 Sample Questions (Q109-Q114):

NEW QUESTION # 109
Assume that PC1 and PC2 can communicate with each other. When R1 forwards a data packet sent from PC1 to PC2, which of the following statements are true?

Answer: C,D

Explanation:
This question tests the difference between Layer 3 addressing and Layer 2 encapsulation during routing. The IP packet originated by PC1 keeps PC1 ' s IP address as its source IP and PC2 ' s IP address as its destination IP as it traverses the routers. Ethernet MAC addresses, however, are rewritten at every routed hop. When R1 forwards the packet across the link toward R2, R1 builds a new Ethernet frame on its outgoing interface.
According to the exhibit, R1 ' s outgoing interface on the R1-R2 link uses MAC_C, so MAC_C is the source MAC address. The next-hop device on that link is R2, whose receiving interface uses MAC_D, so MAC_D is the destination MAC address. MAC_A belongs to PC1 and was relevant only on the first local Ethernet segment. MAC_F belongs to PC2 and is used on the final Ethernet segment from R2 to PC2, not on the R1- R2 link. Therefore the correct statements are B and D. The uploaded key B, C is incorrect.


NEW QUESTION # 110
On the network shown in the figure, if sent by Host A, data frames with which of the following destination MAC addresses can be received by Host B and Host C at the same time?

Answer: B,C

Explanation:
The destination address FF-FF-FF-FF-FF-FF is the Ethernet broadcast address. A switch floods a broadcast frame through the other eligible ports in the same VLAN, so both Host B and Host C can receive the frame.
Option C, 53-80-C2-00-00-01, is a multicast MAC address because the individual/group bit, which is the least significant bit of the first octet, is 1. The first octet 0x53 has a binary least significant bit of 1, identifying a group address. Multicast frames may therefore be delivered to multiple receivers in the same Layer 2 domain, depending on multicast handling and membership behavior. By contrast, the first octets in options B and D,
0x98 and 0x34, have a least significant bit of 0 and are unicast addresses. A unicast frame is intended for a single MAC destination and is not normally delivered simultaneously to both hosts. Therefore A and C are the correct choices. This classification is fundamental when predicting whether a switched Ethernet frame is delivered to one station or replicated to multiple receivers simultaneously.


NEW QUESTION # 111
In an IPv6 address, two or more consecutive groups of 0s can be compressed using a double colon (::), reducing the overall length of the address. For example, 2001:DBFF:130F:0:0:0:0:130B can be compressed to
2001:DBFF:130F::130B.

Answer: A

Explanation:
IPv6 text representation permits zero compression to make long addresses easier to read and write. One or more consecutive 16-bit groups containing only zeros can be replaced by a double colon, subject to the rule that the double-colon compression is used only once in a single IPv6 address; otherwise the number of omitted groups would be ambiguous. In the address 2001:DBFF:130F:0:0:0:0:130B, four consecutive zero groups appear between 130F and 130B. Replacing that run with :: produces 2001:DBFF:130F::130B, which expands back unambiguously to the original eight groups. Leading zeros within an individual 16-bit group can also be omitted, but that is a separate abbreviation rule. The example in the question follows valid IPv6 notation and does not alter the numeric address. Consequently, the statement that the address can be compressed in the manner shown is TRUE. The correct answer is A. The compression changes only the written representation of the IPv6 address; it does not change the underlying 128-bit address value itself in any way.


NEW QUESTION # 112
R1 has the following configurations:
[R1] nat server for_telnet protocol tcp global 100.0.23.2 telnet inside 192.168.1.1 telnet When a public network user and 100.0.23.2 are reachable, the public network user can run the telnet
192.168.1.1 command to log in to 192.168.1.1.

Answer: B

Explanation:
The nat server configuration creates a static mapping so that an internal Telnet server at private address
192.168.1.1 can be reached from the public network using global address 100.0.23.2 on the Telnet TCP port.
The purpose of NAT Server is to expose an internal service through a reachable public address and translate incoming packets to the inside host. A public user therefore initiates the connection to the configured global address, for example telnet 100.0.23.2, assuming routing and security policies allow the session. The user does not normally issue telnet 192.168.1.1 from the public network because that is the private inside address and is not the destination on which the public-side NAT mapping is matched. After the packet reaches R1 addressed to 100.0.23.2, R1 translates the destination to 192.168.1.1 and forwards it internally. Thus the configuration can make the private server reachable, but the command stated in the question uses the wrong destination address. The statement is FALSE, option B.


NEW QUESTION # 113
Which of the following commands can an administrator run to specify the configuration file for the next startup?

Answer: B

Explanation:
On Huawei VRP, the startup saved-configuration command specifies the configuration file that the device will load at the next restart. This is distinct from selecting the system software image. The startup system- software command identifies the software package used for the next boot, whereas startup saved- configuration identifies the saved configuration that should be restored after the software starts. The reset saved-configuration command clears the saved startup configuration rather than selecting one, and reset factory-configuration is used to restore factory-related settings on platforms that support it. In normal operations, an administrator first saves or uploads a valid configuration file to local storage and then uses startup saved-configuration to nominate that file for the next startup. The selected file must be in a format supported by the device and accessible in its file system. Therefore, when the requirement is specifically to define which configuration file is used after the next reboot, option B is the correct Huawei VRP command.


NEW QUESTION # 114
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