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Salesforce JS-Dev-101 Exam Overview:

Certification Vendor:Salesforce
Exam Name:Salesforce Certified JavaScript Developer I - Multiple Choice Exam (JS-Dev-101)
Exam Number:JS-Dev-101
Available Languages:English
Exam Duration:105 minutes
Related Certifications:Salesforce Platform Developer II
Salesforce Platform Developer I
Passing Score:65%
Real Exam Qty:60 (multiple choice)
Certificate Validity Period:1 year (maintenance required annually in Salesforce certification program)
Exam Price:$200 USD
Exam Format:Multiple Choice Questions, Multiple Select Questions
Recommended Training:MDN Web Docs - JavaScript Guide
Salesforce Trailhead - JavaScript Developer I
Exam Registration:Salesforce Certification Registration
Kryterion Webassessor (Exam Delivery)
Sample Questions:Salesforce JS-Dev-101 Sample Questions
Exam Way:Online proctored exam via Salesforce authorized testing platform (e.g., Webassessor)
Pre Condition:No formal prerequisites, but familiarity with JavaScript and web development is recommended.
Official Syllabus URL:https://trailhead.salesforce.com/credentials/javascriptdeveloper

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Salesforce JS-Dev-101 Exam Syllabus Topics:

TopicDetails
Topic 1
  • Testing: Covers evaluating unit test effectiveness against a block of code and modifying tests to improve their coverage and reliability.
Topic 2
  • Debugging and Error Handling: Covers proper error handling techniques and the use of the console and breakpoints to debug code.
Topic 3
  • Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
  • falsy evaluations.
Topic 4
  • Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.
Topic 5
  • Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.
Topic 6
  • Browser and Events: Covers DOM manipulation, event handling and propagation, browser-specific APIs, and using Browser Developer Tools to inspect code behavior.

Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q29-Q34):

NEW QUESTION # 29
Code:
01 let array = [1, 2, 3, 4, 4, 5, 4, 4];
02 for (let i = 0; i < array.length; i++) {
03 if (array[i] === 4) {
04 array.splice(i, 1);
05 i--;
06 }
07 }
What is the value of array after execution?

Answer: A

Explanation:
Initial array:
[1, 2, 3, 4, 4, 5, 4, 4]
The loop removes every value equal to 4:
array.splice(i, 1) removes the element at index i and shifts all later elements left.
i-- ensures the next index is checked correctly after the shift, preventing skipping elements.
Step-by-step removal:
Remove the first 4 → array becomes [1,2,3,4,5,4,4]
Remove next 4 → [1,2,3,5,4,4]
Remove next 4 → [1,2,3,5,4]
Remove last 4 → [1,2,3,5]
Final result:
[1,2,3,5]
Option B is correct.
JavaScript Knowledge Reference (text-only)
splice(index, deleteCount) removes elements and shifts remaining items.
Adjusting the loop index when deleting prevents skipping items.
Arrays update length dynamically after splice().


NEW QUESTION # 30
Given the JavaScript below:
01 function filterDOM(searchString){
02 const parsedSearchString = searchString && searchString.toLowerCase();
03 document.querySelectorAll('.account').forEach(account => {
04 const accountName = account.innerHTML.toLowerCase();
05 account.style.display = accountName.includes(parsedSearchString) ? /* Insert code here */;
06 });
07 }
Which code should replace the placeholder comment on line 05 to hide accounts that do not match the search string?

Answer: A

Explanation:
We have a ternary:
account.style.display = accountName.includes(parsedSearchString)
? /* if true */
: /* if false */;
Requirement:
If the account matches the search string → show it.
If it does not match → hide it.
For display:
Show: 'block' (or similar visible value).
Hide: 'none'.
So we want:
account.style.display = accountName.includes(parsedSearchString)
? 'block'
: 'none';
That corresponds to option A.
Why others are wrong:
B, C use values suitable for visibility, not display.
D ('none' : 'block') inverts the logic, hiding matches and showing non-matches.
________________________________________


NEW QUESTION # 31
Refer to the code below:

What is the output of this function when called with an empty array?

Answer: D


NEW QUESTION # 32
A class was written to represent items for purchase in an online store, and a second class representing items that are on sale at a discounted price. The constructor sets the name to the first value passed in. There is a new requirement for a developer to implement a description method that will return a brief description for Item and SaleItem.
01 let regItem = new Item('Scarf', 55);
02 let saleItem = new SaleItem('Shirt', 80, .1);
03 Item.prototype.description = function() { return 'This is a ' + this.name; }
04 console.log(regItem.description());
05 console.log(saleItem.description());
06
07 SaleItem.prototype.description = function() { return 'This is a discounted ' + this.name; } What is the output when executing the code above?

Answer: D

Explanation:
Comprehensive and Detailed
Assuming SaleItem inherits from Item via prototype (e.g. SaleItem.prototype = Object.create(Item.prototype)):
Lines 01-02: create regItem and saleItem.
Line 03: define Item.prototype.description.
Now both regItem and saleItem (via inheritance) have a description method from Item.prototype.
Line 04: regItem.description() → 'This is a Scarf'.
Line 05: saleItem.description() → 'This is a Shirt' (same method, but this.name is 'Shirt').
Line 07: SaleItem.prototype.description = ... overrides description only for SaleItem instances going forward.
If we imagine calling regItem.description() and saleItem.description() again after line 07:
regItem.description() still uses Item.prototype.description → 'This is a Scarf'.
saleItem.description() now uses SaleItem.prototype.description → 'This is a discounted Shirt'.
Those four lines correspond to option B.


NEW QUESTION # 33
Refer to the following array:
Let arr1 = [ 1,2, 3, 4, 5 ];

Which two lines of code result in a second array, arr2 being created such that arr2 is not a reference to arr1?

Answer: A,B


NEW QUESTION # 34
......

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