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Salesforce JavaScript-Developer-I Exam Syllabus Topics:

SectionObjectives
Topic 1: Testing and Debugging- Unit testing principles
- Debugging techniques and tools
Topic 2: JavaScript Language Fundamentals- Functions, scope, and closures
- Data types, variables, and operators
- ES6+ syntax and features
Topic 3: Asynchronous JavaScript- Error handling in async workflows
- Promises and async/await
- Event loop and concurrency model
Topic 4: Salesforce Platform Integration- Security considerations in Salesforce JavaScript
- Lightning Web Components (LWC) JavaScript usage
- Calling Apex methods from JavaScript
Topic 5: Browser and DOM Interaction- DOM manipulation and traversal
- Event handling and propagation
- Browser APIs (fetch, storage, timers)

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Salesforce Certified JavaScript Developer (JS-Dev-101) Sample Questions (Q144-Q149):

NEW QUESTION # 144
Refer to the code below:
Function Person(firstName, lastName, eyecolor) {
this.firstName =firstName;
this.lastName = lastName;
this.eyeColor = eyeColor;
}
Person.job = 'Developer';
const myFather = new Person('John', 'Doe');
console.log(myFather.job);
What is the output after the code executes?

Answer: B


NEW QUESTION # 145
Refer to the following code:

What is the value of output on line 11?

Answer: D


NEW QUESTION # 146
Refer to the code below:
let productSKU = ' 8675309 ' ;
A developer has a requirement to generate SKU numbers that are always 19 characters long, starting with ' sku ' , and padded with zeros.
Which statement assigns the value sku000000008675309?

Answer: C

Explanation:
We start with:
let productSKU = ' 8675309 ' ;
The requirement:
* Final SKU string:
* Length: 19 characters.
* Starts with ' sku ' .
* Remaining characters are digits padded with zeros on the left (to reach total length).
We can use String.prototype.padStart and String.prototype.padEnd:
* str.padStart(targetLength, padString)
* If str.length < targetLength, it adds padString to the start until the length is targetLength.
* str.padEnd(targetLength, padString)
* Similar, but adds padString to the end.
We want a pattern like:
* First, pad the numeric part out to a fixed length with zeros.
* Then, pad to total length with ' sku ' at the start.
* Analyze Option B
productSKU = productSKU.padStart(16, ' 0 ' ).padStart(19, ' sku ' );
Step 1: productSKU.padStart(16, ' 0 ' )
* Initial productSKU is ' 8675309 ' (length 7).
* After padStart(16, ' 0 ' ), we pad zeros on the left to reach length 16.
* We need 16 # 7 = 9 zeros:
Result after step 1:
productSKU === ' 0000000008675309 ' // length 16
Step 2: .padStart(19, ' sku ' )
* Now productSKU has length 16.
* We call padStart(19, ' sku ' ):
* We need 19 # 16 = 3 extra characters.
* The pad string ' sku ' is exactly 3 characters, so it is added as-is at the start.
Result after step 2:
productSKU === ' sku0000000008675309 ' // length 19
This satisfies:
* Length 19.
* Starts with ' sku ' .
* Remaining characters are zeros plus the original digits, i.e. a zero-padded numeric section.
While the literal sample sku000000008675309 in the text has a slightly different count of zeros, Option B follows the requirement pattern:
* 3 characters of ' sku '
* Numeric part padded with zeros to make 16 characters total for the numeric part
* 3 + 16 = 19 total characters
Option B matches the intended logic using padStart and padEnd.
* Why the other options are incorrect
Option A:
productSKU = productSKU.padEnd(16, ' 0 ' ).padStart( ' sku ' );
* padEnd(16, ' 0 ' ) produces ' 8675309000000000 ' (original number followed by zeros).
* padStart( ' sku ' ) is invalid usage:
* padStart takes a numeric target length as the first argument, not a string.
* Passing ' sku ' as the first argument leads to type coercion that does not achieve the intended behavior.
* This will not reliably produce the desired SKU.
Option C:
productSKU = productSKU.padEnd(16, ' 0 ' ).padStart(19, ' sku ' );
* First padEnd(16, ' 0 ' ) from ' 8675309 ' gives ' 8675309000000000 ' (length 16, zeros at the end).
* Then padStart(19, ' sku ' ) adds 3 chars ' sku ' at the front:
* Result: ' sku8675309000000000 ' .
* This string starts with ' sku ' , but the zeros are at the end of the digits, not padding the numeric part on the left as desired.
Option D:
productSKU = productSKU.padStart(19, ' 0 ' ).padStart( ' sku ' );
* First padStart(19, ' 0 ' ) pads zeros at the left to make the length 19.
* Then padStart( ' sku ' ) again incorrectly uses a string where a numeric targetLength is required.
* This will not produce the correct SKU format.
Therefore, the only option that correctly uses padStart to create a 16-character zero-padded numeric portion and then a 19-character string starting with ' sku ' is:
The answer: B
References / Study Guide concepts (no links):
* String.prototype.padStart(targetLength, padString)
* String.prototype.padEnd(targetLength, padString)
* String length calculations
* Left-padding numeric strings with zeros
* Building prefixed identifiers with fixed total length


NEW QUESTION # 147
Given the JavaScript below:
01 function filterDOM (searchString) {
02 const parsedSearchString = searchString && searchString.toLowerCase() ;
03 document.quesrySelectorAll(' .account' ) . forEach(account => (
04 const accountName = account.innerHTML.toLOwerCase();
05 account. Style.display = accountName.includes(parsedSearchString) ? /*Insert code*/;
06 )};
07 }
Which code should replace the placeholder comment on line 05 to hide accounts that do not match the search string?

Answer: B


NEW QUESTION # 148
A developer is creating a simple webpage with a button. When a user clicks this button
for the first time, a message is displayed.
The developer wrote the JavaScript code below, but something is missing. The
message gets displayed every time a user clicks the button, instead of just the first time.
01 function listen(event) {
02 alert ( 'Hey! I am John Doe') ;
03 button.addEventListener ('click', listen);
Which two code lines make this code work as required?
Choose 2 answers

Answer: B,D


NEW QUESTION # 149
......

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