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Salesforce JavaScript-Developer-I certification exam is designed to test the knowledge of developers who use JavaScript on the Salesforce platform. JavaScript-Developer-I exam is intended for those who build custom applications and functionality using the Salesforce Lightning Component Framework and Apex. JavaScript-Developer-I exam is also suitable for those who have experience with web development and JavaScript and are looking to expand their credentials with Salesforce.
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NEW QUESTION # 131
Refer to the code below:
Const searchTest = 'Yay! Salesforce is amazing!" ;
Let result1 = searchText.search(/sales/i);
Let result 21 = searchText.search(/sales/i);
console.log(result1);
console.log(result2);
After running this code, which result is displayed on the console?
Answer: B
NEW QUESTION # 132
Given the JavaScript below:
01 function filterDOM(searchString){
02 const parsedSearchString = searchString & & searchString.toLowerCase();
03 document.querySelectorAll( ' .account ' ).forEach(account = > {
04 const accountName = account.innerHTML.toLowerCase();
05 account.style.display = accountName.includes(parsedSearchString) ? /* Insert code here */;
06 });
07 }
Which code should replace the placeholder comment on line 05 to hide accounts that do not match the search string?
Answer: D
Explanation:
We have a ternary:
account.style.display = accountName.includes(parsedSearchString)
? /* if true */
/* if false */;
Requirement:
* If the account matches the search string # show it.
* If it does not match # hide it.
For display:
* Show: ' block ' (or similar visible value).
* Hide: ' none ' .
So we want:
account.style.display = accountName.includes(parsedSearchString)
? ' block '
' none ' ;
That corresponds to option A.
Why others are wrong:
* B, C use values suitable for visibility, not display.
* D ( ' none ' : ' block ' ) inverts the logic, hiding matches and showing non-matches.
NEW QUESTION # 133
function myFunction() {
a = a + b;
var b = 1;
}
myFunction();
console.log(a);
console.log(b);
Which statement is correct?
Answer: C
Explanation:
The correct answer is A , not D.
Inside myFunction(), the declaration:
var b = 1;
is hoisted to the top of the function scope, but only the declaration is hoisted, not the assignment. So internally, JavaScript treats the function approximately like this:
function myFunction() {
var b;
a = a + b;
b = 1;
}
Now examine this line:
a = a + b;
Before JavaScript can assign a value to a, it must first evaluate the right-hand side:
a + b
At this point:
b
exists locally because var b was hoisted, so its value is:
undefined
However:
a
has not been declared anywhere. Reading an undeclared variable causes a:
ReferenceError
So this line throws an error before assignment happens:
a = a + b;
Because the error occurs on that line, the next line inside the function is never executed:
var b = 1;
Also, because the error is not handled with try...catch, the program stops before reaching:
console.log(a);
console.log(b);
Therefore, the accurate statement is:
Line 02 throws a reference error, therefore line 03 is never executed.
So the verified answer is A .
NEW QUESTION # 134
Given the following code:
Which replacement for the conditional statement on line 02 allows a developer to correctly determine that a button on the page is clicked?
Answer: A
NEW QUESTION # 135
Original code:
01 let requestPromise = client.getRequest;
03 requestPromise().then((response) = > {
04 handleResponse(response);
05 });
The developer wants to gracefully handle errors from a Promise-based GET request.
Which code modification is correct?
Answer: D
Explanation:
Key JavaScript Promise rule:
try...catch does not catch asynchronous errors that occur in Promise chains.
Therefore, the correct way to handle errors in a Promise is:
promise.then(...).catch(...);
Analysis of options:
* A and B: Both wrap asynchronous code in try...catch, which does not catch Promise rejections. try...
catch only catches errors thrown synchronously inside the block.
* C: Correct. A .catch() on the Promise chain handles any error from the Promise returned by requestPromise().
* D: .finally() executes regardless of success or failure, but it does not receive the error object , so it cannot handle the error.
Thus the only valid solution is option C .
JavaScript Knowledge References (text-only)
* Promise rejections must be handled with .catch().
* try...catch only handles synchronous code.
* .finally() does not receive a rejection reason.
NEW QUESTION # 136
......
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