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NEW QUESTION # 125
Refer to the code:
01 const exec = (item, delay) =>
02 new Promise(resolve => setTimeout(() => resolve(item), delay));
03
04 async function runParallel() {
05 const [result1, result2, result3] = await Promise.all(
06 [exec('x', '100'), exec('y', '500'), exec('z', '100')]
07 );
08 return `parallel is done: ${result1}${result2}${result3}`;
09 }
Which two statements correctly execute runParallel()?
Answer: A,C
Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge Facts about JavaScript Promises:
runParallel() is declared async, which means it always returns a Promise.
Promises are consumed using .then(), .catch(), and .finally().
There is no .done() method in native JavaScript Promises.
The async keyword cannot be placed before a function call (option A is invalid syntax).
Analysis of each option:
A . async runParallel().then(data);
Invalid syntax. async cannot prefix an expression.
B . Valid. Calls the function and attaches a .then() handler.
C . Invalid. .done() is not part of JavaScript Promise API.
D . Valid. Calls runParallel() and chains .then().
Therefore the correct answers are B and D.
________________________________________
JavaScript Knowledge Reference (text-only)
async functions return Promises.
Promises use .then() to retrieve resolved values.
.done() is not part of the standard Promise interface.
NEW QUESTION # 126
Refer to the code below:
const car = {
price:100,
getPrice:function(){
return this.price;
}
};
const customCar = Object.create(car);
customCar.price = 70;
delete customCar.price;const result = customCar.getPrice();
Whatis the value of result after the code executes?
Answer: C
NEW QUESTION # 127
A developer has two ways to write a function:
Option A:
01 function Monster() {
02 this.growl = () => {
03 console.log("Grr!");
04 }
05 }
Option B:
01 function Monster() {};
02 Monster.prototype.growl = () => {
03 console.log("Grr!");
04 }
After deciding on an option, the developer creates 1000 monster objects. How many growl methods are created with Option A and Option B?
Answer: A
Explanation:
Option A:
this.growl = () => { ... } inside the constructor creates a new function per instance.
For 1000 new Monster(), you get 1000 distinct growl functions, each stored on the instance itself.
Option B:
Monster.prototype.growl = () => { ... } attaches growl to the prototype.
All instances share the same single growl function via the prototype chain.
For 1000 instances, only 1 growl method exists in memory.
So: Option A โ 1000; Option B โ 1.
NEW QUESTION # 128
Given the JavaScript below:
01 function filterDOM(searchString){
02 const parsedSearchString = searchString && searchString.toLowerCase();
03 document.querySelectorAll('.account').forEach(account => {
04 const accountName = account.innerHTML.toLowerCase();
05 account.style.display = accountName.includes(parsedSearchString) ? /* Insert code here */;
06 });
07 }
Which code should replace the placeholder comment on line 05 to hide accounts that do not match the search string?
Answer: A
Explanation:
We have a ternary:
account.style.display = accountName.includes(parsedSearchString)
? /* if true */
/* if false */;
Requirement:
If the account matches the search string โ show it.
If it does not match โ hide it.
For display:
Show: 'block' (or similar visible value).
Hide: 'none'.
So we want:
account.style.display = accountName.includes(parsedSearchString)
? 'block'
'none';
That corresponds to option A.
Why others are wrong:
B, C use values suitable for visibility, not display.
D ('none' : 'block') inverts the logic, hiding matches and showing non-matches.
NEW QUESTION # 129
Refer to the following code:
01 let obj = {
02 foo: 1,
03 bar: 2
04 }
05 let output = []
06
07 for (let something of obj) {
08 output.push(something);
09 }
10
11 console.log(output);
What is the value of output on line 11?
Answer: C
Explanation:
The key line is:
for (let something of obj) {
In JavaScript:
for...of is used to iterate over iterable objects, such as:
Arrays
Strings
Maps
Sets
Other objects that implement a [Symbol.iterator] method.
Plain JavaScript objects created with object literal {} are not iterable by default. They do not have [Symbol.iterator], so using for...of directly on them causes a runtime error.
Specifically:
for (let something of obj) { ... }
will throw a TypeError similar to:
obj is not iterable
Therefore, the loop body never executes, and console.log(output); is never reached without an error.
Why other options are incorrect:
B . [1, 2]
To get [1, 2], you could use Object.values(obj) and iterate that array.
But here, for...of obj never yields values because it throws an error.
C . ["foo", "bar"]
To get property names, you could use Object.keys(obj) with for...of.
Again, the code does not do that; it incorrectly tries to iterate the object directly.
D . ["foo:1", "bar:2"]
You would need both keys and values, combining them manually.
The given code does not implement such logic and fails before pushing anything into output.
Hence, the correct answer is:
Answe r: A
Study Guide / Concept Reference (no links):
Difference between for...of and for...in
Iterables in JavaScript and [Symbol.iterator]
Plain objects {} are not iterable by default
Correct patterns to iterate object keys/values (Object.keys, Object.values, Object.entries)
NEW QUESTION # 130
......
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