Exam Applied-Algebra Questions Fee | Applied-Algebra Valid Exam Dumps

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WGU Applied-Algebra Exam Syllabus Topics:

Section	Objectives
Foundations of Algebra	- Equations and Inequalities 1. Linear equations in one variable 2. Inequalities and interval notation - Algebraic Expressions 1. Order of operations 2. Evaluating expressions 3. Simplifying expressions
Linear Functions and Systems	- Linear Equations 1. Slope-intercept form 2. Point-slope form - Systems of Equations 1. Substitution method 2. Elimination method
Functions and Graphs	- Function Concepts 1. Domain and range 2. Function notation - Graphing Functions 1. Transformations of graphs 2. Coordinate plane interpretation
Exponential and Logarithmic Concepts	- Logarithmic Basics 1. Conversion between exponential and logarithmic form 2. Logarithm properties - Exponential Functions 1. Growth and decay models 2. Exponential equations
Polynomial and Rational Expressions	- Polynomials 1. Factoring techniques 2. Operations with polynomials - Rational Expressions 1. Restrictions on variables 2. Simplification

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Applied-Algebra Valid Exam Dumps & Applied-Algebra Exam Course

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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q137-Q142):

NEW QUESTION # 137
Through a local marketplace, a person makes livestock feeders to sell. The graph shows the functions modeling the cost and revenue.

What is the minimum number of livestock feeders that must be sold in order for the revenue to cover the costs?

A. 0
B. 1
C. 2
D. 3

Answer: C

Explanation:
This question asks for the break-even point, which is the point where:
Revenue=Cost
On the graph:
The solid blue line represents revenue.
The dashed blue line represents cost.
The revenue line starts below the cost line, meaning the person is not yet covering costs. The revenue line eventually crosses the cost line at a little more than 4 units.
Since the question asks for the minimum number of livestock feeders that must be sold, we need a whole number of feeders.
The graph shows the intersection occurs between:
4 and 5
So selling 4 feeders is not enough, but selling 5 feeders is enough for revenue to cover the costs.
Therefore, the correct answer is:
C

NEW QUESTION # 138
The number of daily raffle tickets sold, R(d), for a fundraiser is represented by the graph, with the number of days since the beginning of the month along the horizontal axis and the number of raffle tickets sold for the day along the vertical axis.

How can the concavity be described from d=0to d=4.4?

A. The number of raffle tickets increases slower and slower and then decreases faster and faster.
B. The number of raffle tickets decreases slower and slower and then increases faster and faster.
C. The number of raffle tickets decreases slower and slower and then decreases faster and faster.
D. The number of raffle tickets decreases faster and faster and then decreases slower and slower.

Answer: B

Explanation:
From d=0to about d=2, the graph is decreasing, but it is flattening as it approaches a minimum. This means the number of raffle tickets sold is decreasing at a slower rate:
" decreases slower and slower "
After the minimum, from about d=2to d=4.4, the graph increases and becomes steeper. This means the number of raffle tickets sold is increasing at a faster rate:
" increases faster and faster "
So the correct description is:
" The number of raffle tickets decreases slower and slower and then increases faster and faster. "

NEW QUESTION # 139
The function P(t)represents the weekly profit, in thousands of dollars, for a rental store since opening. The graph of P(t)is shown.

When did the store have its maximum weekly profit?

A. Approximately 5.5 years after the store opened
B. Approximately 17 years after the store opened
C. Approximately 7 years after the store opened
D. Approximately 3 years after the store opened

Answer: A

Explanation:
The graph shows:
P(t)= " weekly profit in thousands of dollars "
where:
t= " years since opening "
The graph is a downward-opening curve, so it has a maximum value at its highest point. In Applied Algebra, the highest point of this kind of polynomial graph is called the vertex.
To answer the question, we need the t-value of the vertex because the question asks when the store had its maximum weekly profit.
From the graph, the highest point occurs between:
t=5
and
t=6
More specifically, it is approximately:
t=5.5
So the store had its maximum weekly profit approximately:
5.5 " years after opening "

NEW QUESTION # 140
The traffic flow on a roadway after 8:00 a.m. is modeled by the graphed exponential function.

Which conclusion is valid, based on the horizontal asymptote?

A. The traffic flow changes the most after the first 4 hours.
B. The traffic flow will change by a constant rate over time.
C. The rate of traffic flow changes by a constant rate over time.
D. The traffic flow will not decrease to 0 vehicles per hour.

Answer: D

Explanation:
The graph shows an exponential decay model for traffic flow. A horizontal asymptote represents the long- term value the function approaches. In this case, the graph decreases but levels off above zero. Because the horizontal asymptote is above the horizontal axis, the model predicts that the traffic flow approaches a positive number rather than decreasing all the way to zero. Exponential functions do not change by a constant additive rate; that is a property of linear functions. Instead, exponential models change by a constant factor.
Therefore, statements about constant rate are not valid here. The valid conclusion based on the asymptote is that the traffic flow will not decrease to 0 vehicles per hour. The correct answer is B.

NEW QUESTION # 141
The graph shows the weekly profit in hundreds of dollars for a coffee shop. The horizontal axis represents the number of years since the coffee shop opened.

What is the correct interpretation of the minimum value?

A. Approximately 6 years after opening, a minimum weekly profit of approximately $4,630was earned.
B. Approximately 13 years after opening, a minimum weekly profit of approximately $990was earned.
C. Approximately 13 years after opening, a minimum weekly profit of approximately $4,630was earned.
D. Approximately 6 years after opening, a minimum weekly profit of approximately $990was earned.

Answer: D

Explanation:
The graph shows weekly profit as a function of time.
The horizontal axis represents:
" years since opening "
The vertical axis represents:
" weekly profit in hundreds of dollars "
The graph is an upward-opening curve, so its minimum value occurs at the lowest point, called the vertex.
From the graph, the lowest point occurs at approximately:
t=6
So the minimum weekly profit happened approximately:
6 " years after opening "
The vertical value at this point is approximately:
9.9
Since the profit is measured in hundreds of dollars:
9.9×100=990
So the minimum weekly profit was approximately:
$990
Therefore, the correct answer is:
# ( " A " )

NEW QUESTION # 142
......

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