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Juniper JN0-351 Exam Syllabus Topics:

SectionObjectives
Topic 1: Layer 2 Security- Switch security features
  • 1. Storm control
    • 2. MAC limiting
      Topic 2: High Availability- Redundancy mechanisms
      • 1. VRRP
        • 2. BFD
          - Junos HA features
          • 1. GRES
            • 2. NSR / NSB
              • 3. Graceful restart
                Topic 3: Tunneling Technologies- IP tunneling
                • 1. GRE tunnels
                  • 2. IP-IP tunnels
                    Topic 4: Layer 2 Switching- Spanning Tree Protocol (STP/RSTP)
                    • 1. Loop prevention mechanisms
                      • 2. STP operations and convergence
                        - VLANs and trunking
                        • 1. VLAN configuration and verification
                          • 2. 802.1Q tagging
                            Topic 5: Layer 3 Routing Fundamentals- Routing concepts
                            • 1. Route preference and policy
                              • 2. Protocol-independent routing
                                - Routing protocols
                                • 1. BGP fundamentals
                                  • 2. IS-IS basics
                                    • 3. OSPF fundamentals and operations

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                                      Juniper Enterprise Routing and Switching, Specialist (JNCIS-ENT) Sample Questions (Q134-Q139):

                                      NEW QUESTION # 134
                                      In the exhibit, each IP subnet in the campus environment is associated with a unique VLAN ID.

                                      Which action will ensure that Host C will communicate with Host A and Host B?

                                      Answer: C


                                      NEW QUESTION # 135
                                      Exhibit

                                      Referring to the exhibit, which statement is correct?

                                      Answer: C

                                      Explanation:
                                      In a Rapid Spanning Tree Protocol (RSTP) topology, the root bridge is determined by the switch with the lowest bridge priority value 1 2 . If all switches have the same priority, then the root bridge is assigned to the switch whose MAC address's hex value is the lowest 2 . The default bridge priority value is 32768 3 2 .
                                      However, without the actual exhibit, it's difficult to definitively determine which device is the root bridge. But based on the options provided, if we assume that the local device has a lower bridge priority or a lower MAC address than other devices in the network, then it could be considered as the root bridge for this RSTP topology 4 5 .


                                      NEW QUESTION # 136
                                      You want to enable redundancy for the EBGP peering between the two routers shown in the exhibit.
                                      Which three actions will you perform in this scenario? (Choose three.)

                                      Answer: B,C,D

                                      Explanation:
                                      A is correct because you need to configure BGP multihop to enable redundancy for the EBGP peering between the two routers. BGP multihop is a feature that allows BGP peers to establish a session over multiple hops, instead of requiring them to be directly connected. By default, EBGP peers use a time-to-live (TTL) value of 1 for their packets, which means that they can only reach adjacent neighbors. However, if you configure BGP multihop with a higher TTL value, you can allow EBGP peers to communicate over multiple routers in between. This can provide redundancy in case of a link failure or a router failure between the EBGP peers.
                                      B is correct because you need to configure loopback interface peering to enable redundancy for the EBGP peering between the two routers. Loopback interface peering is a technique that uses loopback interfaces as the source and destination addresses for BGP sessions, instead of physical interfaces. Loopback interfaces are virtual interfaces that are always up and reachable as long as the router is operational. By using loopback interface peering, you can avoid the dependency on a single physical interface or link for the BGP session, and use multiple paths to reach the loopback address of the peer. This can provide redundancy and load balancing for the EBGP peering.
                                      C is correct because you need to configure routes for the peer loopback interface IP addresses to enable redundancy for the EBGP peering between the two routers. Routes for the peer loopback interface IP addresses are necessary to ensure that the routers can reach each other's loopback addresses over multiple hops. You can use static routes or dynamic routing protocols to advertise and learn the routes for the peer loopback interface IP addresses. Without these routes, the routers will not be able to establish or maintain the BGP session using their loopback interfaces.


                                      NEW QUESTION # 137
                                      You are asked to create a default route that will be advertised to your internal OSPF neighbors. You have three upstream connections to the Internet and you must ensure that when available, all traffic uses ISP1 as your primary connection and only uses ISP2 and ISP3 when ISP1 is not available.
                                      Which solution should you implement in this scenario?

                                      Answer: D

                                      Explanation:
                                      The solution that should be implemented in this scenario is to create a default generate route that includes an import policy to match BGP routes from ISP1 and assign a preference value of four or less. This way, the default route will be advertised to the internal OSPF neighbors only when there is a BGP route from ISP1 in the routing table, and it will have a higher preference than any other default route from ISP2 or ISP3. If ISP1 is not available, the default generate route will be withdrawn and the traffic will use the next available default route from ISP2 or ISP3.
                                      Option A is incorrect because creating a default static route with ISP1's address as the next hop while specifying the addresses for ISP2 and ISP3 as qualified next hops with a preference value of six or higher will not ensure that the default route is advertised to the internal OSPF neighbors only when ISP1 is available. The default static route will always be in the routing table regardless of the availability of ISP1, and it will have a lower preference than any other default route from ISP2 or ISP3.
                                      Option C is incorrect because creating a default static route with each neighbor address as the next hop will not ensure that all traffic uses ISP1 as the primary connection and only uses ISP2 and ISP3 when ISP1 is not available. The default static route will always be in the routing table regardless of the availability of ISP1, and it will load balance the traffic among the three ISPs.
                                      Option D is incorrect because creating a default aggregated route will not ensure that the default route is advertised to the internal OSPF neighbors only when ISP1 is available. The default aggregated route will always be in the routing table regardless of the availability of ISP1, and it will not have any preference value associated with it. References:
                                      * Enterprise Routing and Switching, Specialist (JNCIS-ENT) - Juniper Networks
                                      * Enterprise Routing and Switching, Specialist (JNCIS-ENT) - Juniper Networks


                                      NEW QUESTION # 138
                                      When electing a DIS in an IS-IS network, what is used to break a priority tie?

                                      Answer: B


                                      NEW QUESTION # 139
                                      ......

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