Applied-Algebra Reliable Test Answers, Applied-Algebra Test Braindumps

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WGU Applied-Algebra Exam Syllabus Topics:

SectionWeightObjectives
Systems of Equations and Inequalities15%- Graphical solutions
- Solving by substitution and elimination
- Applications of systems
Graphing and Functions25%- Linear functions and their graphs
- Slope and equations of lines
- Function notation and evaluation
- Coordinate plane and plotting points
Linear Equations and Inequalities25%- Solving and graphing inequalities
- Solving single-variable equations
- Real-world applications
Algebraic Expressions and Operations20%- Order of operations
- Variables, constants, and coefficients
- Operations with polynomials
- Simplifying and evaluating expressions
Exponents, Radicals, and Quadratic Relationships15%- Solving quadratic equations
- Simplifying radical expressions
- Properties of exponents
- Basic quadratic graphs

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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q57-Q62):

NEW QUESTION # 57
The spread of two viruses within a single population is modeled using the functions in the graph.

What is a correct conclusion based on the graph?

Answer: A

Explanation:
The graph compares the spread of two viruses over time.
The horizontal axis represents:
" time in months "
The vertical axis represents:
" percent of the population affected "
The graph shows:
Virus A as the solid blue curve.
Virus B as the dashed blue curve.
To determine which statement is correct, compare when each virus reaches the same population percentage.
At 20%, Virus A reaches that level earlier than Virus B. The solid curve is already at 20%before the dashed curve reaches 20%.
However, for higher percentages like 70%and 80%, Virus B reaches those levels before Virus A because the dashed curve becomes steeper and rises above the solid curve after about 50%.
So the correct conclusion is:
" Virus A affects " 20% " of the population before virus B does. "
Therefore, the correct answer is:
# ( " A " )


NEW QUESTION # 58
The graphed function v(t) represents the number of vehicles, v, stopped at a toll booth t hours after 6:00 a.m.
The coordinates of points A and B are (1,49.4) and (4,45.8), respectively.

What is the average rate of change of the number of vehicles from point A to point B?

Answer: D

Explanation:
The average rate of change measures how much the output changes per one unit of input. Here, the input is time in hours after 6:00 a.m., and the output is the number of vehicles stopped at the toll booth. The two given points are A=(1,49.4) and B=(4,45.8). Use the average rate of change formula: (y
2
#y
1
)/(x
2
#x
1
). Substituting the coordinates gives (45.8#49.4)/(4#1). The numerator is #3.6, and the denominator is 3, so the average rate of change is #1.2. The negative sign means the number of vehicles decreased over the interval.


NEW QUESTION # 59
The graph shows the estimated wait time, in minutes, based on the number of hours after 7:00 a.m.
What is the average rate of change of the wait time from point Ato point B?

Answer: B


NEW QUESTION # 60
The populations, in thousands, of two towns are shown in the graph, where the horizontal axis measures the time in years.

Which town's population is growing at a faster rate?

Answer: C

Explanation:
To determine which town's population is growing faster, compare the slopes of the two lines. In a linear population model, the slope represents the growth rate, while the starting value represents the initial population. The graph shows that Town A and Town B both increase over time, but Town B has the larger slope. Town B grows at about 1.3 thousand people per year, while Town A grows at about 1.1 thousand people per year. Since 1.3 > 1.1, Town B's population is increasing at a faster rate. The values 6.5 and 5.5 describe starting population amounts, not growth rates. Therefore, the correct answer is A.


NEW QUESTION # 61
The number of wild horses in a federal park is represented by the logistic function f(x), whose graph is shown, where xrepresents the number of years since the park was established and f(x)represents the wild horse population in a given year.

How does the number of wild horses change as time progresses from year 1 to year 9?

Answer: C

Explanation:
The graph is a logistic growth function.
A logistic function often has an S-shape. It begins by increasing slowly, then increases faster and faster, and later levels off as it approaches a maximum carrying capacity.
From year 1 to year 9, the graph is rising and becoming steeper.
That means:
" the wild horse population is increasing "
and the slope is getting larger, so:
" the population is increasing faster and faster "
Therefore, the correct answer is:
# ( " A " )


NEW QUESTION # 62
......

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