Applied-Probability-and-Statistics測試引擎,Applied-Probability-and-Statistics認證指南

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WGU Applied-Probability-and-Statistics Exam Syllabus Topics:

SectionObjectives
Topic 1: Statistical Inference- Estimation and Confidence Intervals
  • 1. Confidence interval interpretation
    • 2. Point estimates
      - Hypothesis Testing (Introductory Level)
      • 1. p-values interpretation
        • 2. Null vs alternative hypothesis
          Topic 2: Probability Theory- Fundamental Probability Concepts
          • 1. Basic probability rules
            • 2. Conditional probability
              • 3. Independent vs dependent events
                - Probability Distributions
                • 1. Binomial distribution basics
                  • 2. Normal distribution
                    Topic 3: Descriptive Statistics- Two Variable Data Analysis
                    • 1. Scatter plots interpretation
                      • 2. Correlation
                        • 3. Outliers and relationships
                          - Single Variable Data Analysis
                          • 1. Measures of central tendency (mean, median, mode)
                            • 2. Measures of dispersion (variance, standard deviation, range)
                              • 3. Data visualization (histograms, box plots)
                                Topic 4: Regression and Modeling- Linear Relationships
                                • 1. Slope and intercept interpretation
                                  • 2. Simple linear regression

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                                    Applied-Probability-and-Statistics認證指南,Applied-Probability-and-Statistics考題套裝

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                                    最新的 Courses and Certificates Applied-Probability-and-Statistics 免費考試真題 (Q154-Q159):

                                    問題 #154
                                    Review the following inequality:
                                    y < x # 1/2
                                    Which shaded portion in the graphs corresponds to this inequality?



                                    答案:D

                                    解題說明:
                                    The inequality y < x # 1/2 has boundary line y = x # 1/2. This line has slope 1 and y-intercept #1/2, so it crosses the y-axis slightly below the origin and rises one unit for every one unit moved to the right. Because the inequality is strict, using " < " rather than "#," the boundary line must be dashed, showing that points on the line are not included in the solution set. The solution region must be shaded below the line because y is less than the expression x # 1/2. A useful verification method is the test point (0, 0). Substituting gives 0 < 0 #
                                    1/2, or 0 < #1/2, which is false. Therefore, the region containing the origin should not be shaded. The fourth graph has the dashed boundary with intercept #1/2 and shades the region below the line while excluding the origin. References/topics from the Study Guide: graphing linear inequalities, slope-intercept form, dashed boundaries, test-point method.


                                    問題 #155
                                    In a class of 30 students, 18 are enrolled in a math course, and 12 are enrolled in a science course. Among the students enrolled in the science course, 8 are also enrolled in the math course.
                                    What is the probability that a student is enrolled in the math course given that they are enrolled in the science course?

                                    答案:A

                                    解題說明:
                                    The phrase "given that they are enrolled in the science course" indicates conditional probability. The reference group is not all 30 students; it is only the 12 students enrolled in science. Among those 12 science students, 8 are also enrolled in math. Therefore, the conditional probability is P(math | science) = P(math and science) ÷ P(science), or more directly, 8 ÷ 12. This simplifies to 2/3, which is approximately 0.6667, rounded to .67. Option A, .27, would come from comparing the 8 students to the entire class of 30, but that ignores the given condition. Option B, .40, corresponds to 12/30, the proportion enrolled in science. Option C, .44, is approximately 8/18, which reverses the condition and would represent the probability of science given math.
                                    The correct answer uses the science group as the denominator. References/topics from the Study Guide:
                                    conditional probability, two-way events, joint enrollment, probability ratios.


                                    問題 #156
                                    Sum of probabilities in sample space = ?

                                    答案:C

                                    解題說明:
                                    The probabilities of all outcomes in a complete sample space must sum to 1. A sample space contains every possible outcome of a probability experiment, and one of those outcomes must occur. For example, when rolling a fair six-sided die, the outcomes are 1, 2, 3, 4, 5, and 6. Each has probability 1/6, and the sum is 1/6 +
                                    1/6 + 1/6 + 1/6 + 1/6 + 1/6 = 1. A total probability of 0 would mean no outcome can occur, which is impossible for a valid experiment. A total greater than 1 violates probability rules because probabilities cannot exceed certainty. "Cannot exceed 2" is too broad and mathematically invalid, since the exact total must equal
                                    1. This principle is foundational for checking probability distributions and validating whether assigned probabilities are coherent. Study Guide references/topics: sample space, probability axioms, total probability, theoretical probability.


                                    問題 #157
                                    Determine z in the equation:
                                    1/(6z) = 2/9

                                    答案:C

                                    解題說明:
                                    The equation 1/(6z) = 2/9 is a proportion because it sets two fractions equal to each other. To solve it, use cross multiplication. Multiply the numerator of the first fraction by the denominator of the second fraction, and multiply the denominator of the first fraction by the numerator of the second fraction: 1 × 9 = 2 × 6z. This gives 9 = 12z. To isolate z, divide both sides by 12: z = 9/12. This fraction can also be simplified to 3/4, but the answer choices list the unsimplified equivalent form 9/12. The other options do not satisfy the original equation. For example, if z = 2/54, then 6z is very small and the left side becomes much larger than 2/9. If z =
                                    12/9 or 18/2, the denominator becomes too large, making the left side too small. References/topics from the Study Guide: proportions, solving equations, cross multiplication, equivalent fractions.


                                    問題 #158
                                    Ten teachers each had a jar of jelly beans. The jars had this number of jelly beans in each respective jar: 50,
                                    60, 80, 80, 100, 100, 100, 120, 120, and 140.
                                    What is the mean of these data?

                                    答案:B

                                    解題說明:
                                    The mean is the arithmetic average of a quantitative data set. To calculate it, add all observed values and divide by the number of observations. The jelly bean counts are 50, 60, 80, 80, 100, 100, 100, 120, 120, and
                                    140. Their sum is 950. There are 10 jars, so the mean is 950 ÷ 10 = 95. This means the average number of jelly beans per jar is 95. Option A, 100, may seem plausible because 100 appears frequently and is near the center of the data, but frequency alone determines the mode, not the mean. Option C, 80, is one of the repeated values but not the average. Option B, 120, is too high because several observations fall well below
                                    120. The mean uses every value in the data set, including the low values 50 and 60 and the high value 140.
                                    References/topics from the Study Guide: mean, measures of center, quantitative data, arithmetic average.


                                    問題 #159
                                    ......

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