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Oracle 1z1-071 Exam Syllabus Topics:

Section	Weight	Objectives
Using Set Operators	5%	- Describe set operators - Describe the order of precedence when the set operators are used - Use a set operator to combine multiple queries into a single query
Restricting and Sorting Data	6%	- Limit the rows that are retrieved by a query - Use ampersand substitution to restrict and sort output at runtime - Use DEFINE and UNDEFINE commands - Sort the rows that are retrieved by a query
Controlling User Access	5%	- Distinguish between granting privileges and roles - Differentiate system privileges from object privileges - Grant privileges on tables and on a view
Using Subqueries to Solve Queries	15%	- Write single-row and multi-row subqueries - Define subqueries - Describe the types of problems that subqueries can solve - List the types of subqueries
Working with Oracle Database SQL	8%	- Describe the Oracle Database architecture - Explain the installation of Oracle Database software - Create a container database - Start up and shut down a database
Creating Other Schema Objects	10%	- Create and maintain indexes - Create synonyms for database objects - Create, modify, and retrieve data from a view - Create, maintain, and use sequences
Reporting Aggregated Data Using Group Functions	15%	- Identify the available group functions - Describe the use of group functions - Group data by using the GROUP BY clause - Include or exclude grouped rows by using the HAVING clause
Displaying Data from Multiple Tables Using Joins	15%	- Write SELECT statements to access data from more than one table using equijoins and non-equijoins - Join a table to itself by using a self-join - View data that does not meet a join condition by using outer joins - Cross join tables
Manipulating Data	14%	- Insert rows into a table - Update rows in a table - Control transactions - Describe each data manipulation language (DML) statement - Delete rows from a table
Using DDL Statements to Create and Manage Tables	14%	- Drop, rename, and truncate tables - Categorize the main database objects - Review the table structure - Describe the data types that are available for columns - Create a simple table - Alter table definitions
Using Single-Row Functions to Customize Output	10%	- Manipulate strings with character function in the SELECT and WHERE clauses - Describe the differences between single-row and multiple-row functions - Perform arithmetic with date data - Manipulate numbers with the ROUND, TRUNC, and MOD functions - Manipulate dates with the date functions
Retrieving Data Using the SQL SELECT Statement	5%	- Execute a basic SELECT statement - Differentiate between SQL statements and SQL*Plus commands - List the capabilities of SQL SELECT statements
Using Conversion Functions and Conditional Expressions	10%	- Use conditional IF THEN ELSE logic in a SELECT statement - Apply the NVL, NULLIF, and COALESCE functions to data - Describe implicit and explicit data type conversion - Use the TO_CHAR, TO_NUMBER, and TO_DATE conversion functions

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Oracle Database SQL Sample Questions (Q268-Q273):

NEW QUESTION # 268
Which three queries execute successfully?

A. SELECT 1 / SYSDATE - DATE '2019-01-01' FROM DUAL;
B. SELECT (SYSDATE-DATE '2019-01-01') / 1 FROM DUAL;
C. SELECT 1 - SYSDATE- DATE '2019-01-01' FROM DUAL;
D. SELECT SYSDATE - DATE '2019-01-01' - 1 FROM DUAL;
E. SELECT SYSDATE - 1 - DATE'2019-01-01' EROM DUAL;
F. SELECT SYSDATE / DATE '2019-01-01' - 1 FROM DUAL

Answer: B,D,E

Explanation:
In Oracle SQL, date arithmetic can be performed directly, subtracting one date from another to get the number of days between them:
* Option A:
* SELECT (SYSDATE - DATE '2019-01-01') / 1 FROM DUAL; This query successfully calculates the difference between the current date and a specific date.
* Option D:
* SELECT SYSDATE - DATE '2019-01-01' - 1 FROM DUAL; This query subtracts a specific date from the current date and then subtracts 1 more day, which will execute successfully.
* Option F:
* SELECT SYSDATE - 1 - DATE '2019-01-01' FROM DUAL; Similar to D, this will successfully compute the date difference minus one day.
Options B, C, and E are incorrect because:
* Option B and Option C: You cannot divide by a date or divide a date by a number.
* Option E: You cannot subtract a date from a number.

NEW QUESTION # 269
View the Exhibit and examine the details of the ORDER_ITEMS table.

Evaluate the following SQL statements:
Statement 1:
SELECT MAX(unit_price*quantity) "Maximum Order"
FROM order_items;
Statement 2:
SELECT MAX(unit_price*quantity) "Maximum Order"
FROM order_items
GROUP BY order_id;
Which statements are true regarding the output of these SQL statements? (Choose all that apply.)

A. Both statements would ignore NULL values for the UNIT_PRICE and QUANTITY columns.
B. Statement 1 would not return give the same output.
C. Both the statements would give the same output.
D. Statement 2 would return multiple rows of output.
E. Statement 1 would return only one row of output.

Answer: A,D,E

NEW QUESTION # 270
Examine the description or the CUSTOMERS table:

For Customers whose income level has a value, you want to display the first name and due amount as 5% of their credit limit. Customers whose due amount is null should not be displayed.
Which query should be used?

A. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMONT FROM customers WHERE cust_income_level != NULL AND due_amount != NULL;
B. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMONT FROM customers WHERE cust_income_level IS NOT NULL AND cust_credit_limit IS NOT NULL;
C. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMONT FROM customers WHERE cust_income_level <> NULL AND due_amount <> NULL;
D. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNT FROM customers WHERE cust_income_level != NULL AND cust_credit_level != NULL;
E. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMONT FROM customers WHERE cust_income_level IS NOT NULL AND due_amount IS NOT NULL;

Answer: B

Explanation:
In Oracle SQL, the correct way to check for non-null values is to use the IS NOT NULL condition. Using != NULL or <> NULL is incorrect because NULL represents the absence of any value, and you cannot use equality or inequality operators to check for NULL.
* C. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNT FROM customers WHERE cust_income_level IS NOT NULL AND cust_credit_limit IS NOT NULL; This query will correctly filter out any customers with a NULL income level or credit limit and then calculate the due amount as 5% of their credit limit for the remaining customers.
References:
* Oracle Database SQL Language Reference 12c, especially sections on conditions and expressions that deal with NULL values.

NEW QUESTION # 271
Which three statements are true about inner and outer joins?

A. A full outer join returns matched and unmatched rows.
B. Outer joins can be used when there are multiple join conditions on two tables.
C. Outer joins can only be used between two tables per query.
D. A left or right outer join returns only unmatched rows.
E. An inner join returns matched rows.
F. A full outer join must use Oracle syntax.

Answer: A,E

Explanation:
A: True. A full outer join does indeed return both matched and unmatched rows from both tables involved in the join. It combines the results of both left and right outer joins.
E: True. An inner join, by definition, returns rows that have matching values in both tables. Rows from both tables that do not match are not returned in an inner join result set.
Inner joins match rows from the joined tables based on the join condition, while outer joins include all rows from one or both tables regardless of whether a matching row exists in the other table.
Reference:
The Oracle SQL documentation explains different types of joins, including inner joins, left and right outer joins, and full outer joins, clarifying how they differ in the result sets they produce.

NEW QUESTION # 272
Examine the following query:
SQL> SELECT prod_id, amount_sold
FROM sales
ORDER BY amount_sold
FETCH FIRST 5 PERCENT ROWS ONLY;
What is the output of this query?

A. It displays 5 percent of the products with the lowest amount sold.
B. It displays the first 5 percent of the rows from the SALES table.
C. It results in an error because the ORDER BY clause should be the last clause.
D. It displays 5 percent of the products with the highest amount sold.

Answer: A

Explanation:
Explanation
References:
https://oracle-base.com/articles/12c/row-limiting-clause-for-top-n-queries-12cr1

NEW QUESTION # 273
......

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