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Oracle 1z1-071 (Oracle Database SQL) Exam is designed for professionals who want to show their skills and knowledge in SQL. 1z1-071 exam measures a candidate's ability to design, manage, and manipulate the Oracle database system's SQL language. Passing 1z1-071 Exam is a prerequisite for many Oracle certification programs.
Oracle Database SQL Sample Questions (Q166-Q171):
NEW QUESTION # 166
The PRODUCTStable has the following structure.

Evaluate the following two SQL statements:
SQL>SELECT prod_id, NVL2 (prod_expiry_date, prod_expiry_date + 15, ' ') FROM products; SQL>SELECT prod_id, NVL (prod_expiry_date, prod_expiry_date + 15) FROM products; Which statement is true regarding the outcome?
- A. Only the first SQL statement executes successfully
- B. Both the statements execute and give the same result
- C. Both the statements execute and give different results
- D. Only the second SQL statement executes successfully
Answer: C
Explanation:
Using the NVL2 Function
The NVL2 function examines the first expression. If the first expression is not null, the NVL2 function returns the second expression. If the first expression is null, the third expression is returned.
Syntax
NVL2(expr1, expr2, expr3)
In the syntax:
Expr1 is the source value or expression that may contain a null
Expr2 is the value that is returned if expr1 is not null
Expr3 is the value that is returned if expr1 is null
NEW QUESTION # 167
Which two statements about INVISIBLE indexes are true?
- A. You use AlTER INDEX to make an INVISIBLE Index VISIBLE
- B. The query optimizer never considers INVISIBLE Indexes when determining execution plans
- C. an INVISIBLE Index consumes no storage
- D. You can only create one INVISIBLE index on the same column list
- E. All INSERT, UPDATE, and DELETE statements maintain entries in the index
Answer: A,E
Explanation:
INVISIBLE indexes are a feature in Oracle Database 12c and later versions that allow an index to be maintained but not used by the optimizer unless explicitly hinted.
A). False. An INVISIBLE index still consumes storage space as it is maintained in the background.
B). False. There is no such restriction. You can create multiple INVISIBLE indexes on the same column list.
C). False. The optimizer can consider INVISIBLE indexes if they are hinted at in the query.
D). True. You can alter the visibility of an index using the ALTER INDEX command to make an INVISIBLE index VISIBLE.
E). True. Even though they are invisible to the optimizer by default, all DML operations such as INSERT, UPDATE, and DELETE continue to maintain the index as they would with a VISIBLE index.
NEW QUESTION # 168
Examine these statements which execute successfully:

Both statements display departments ordered by their average salaries.
Which two are true?
- A. Both statements will execute successfully If you add e.avg_sal to the select list.
- B. Both statements will display departments with no employees.
- C. Only the second statement will execute successfully if you add E.AVG_SAL to the select list.
- D. Only the first statement will execute successfully if you add E.AVG_SAK to the select list.
- E. Only the second statement will display departments with no employees.
- F. Only the first statement will display departments with no employees.
Answer: A,E
Explanation:
* A. Only the second statement will display departments with no employees. This is true because the second statement uses a LEFT JOIN to include all departments from the departments table, even those without matching entries in the employees table. When there are no employees in a department, the AVG(salary) will be NULL, and the department will still be displayed1.
* C. Both statements will execute successfully if you add e.avg_sal to the select list. This is correct. Both statements calculate e.avg_sal as an average salary, either through a subquery or a join operation.
Adding e.avg_sal to the select list will display the average salary alongside the departments. However, it's important to note that the first statement will not display departments with no employees because it does not use a join that would allow for NULL values from the employees table2.
References:
* Understanding SQL JOINs - Stack Overflow1.
* Oracle Documentation on JOIN Operations2.
Note: The other options are incorrect because:
* B. The first statement will not display departments with no employees since it does not use a join that includes departments without matching employee records.
* D. As explained, the first statement will not display departments with no employees.
* E. There is a typo in the option; it should be E.AVG_SAL. Even if corrected, the first statement alone would not execute successfully because it does not include a join to bring in the avg_sal value.
* F. The second statement will display departments with no employees, but the first statement will not, so this option is incorrect.
NEW QUESTION # 169
Examine this SQL statement:

Identify three order by clauses, any one of which can complete the query successfully.
- A. ORDER BY 2, cust_id
- B. ORDER BY "Last Name"
- C. ORDER BY 2, 1
- D. ORDER BY CUST_NO
- E. ORDER BY "CUST NO"
Answer: A,B,C
NEW QUESTION # 170
Examine the description of the CUSTOMERS table:

You want to display details of all customers who reside in cities starting with the letter D followed by at least two character.
Which query can be used?
- A. SELECT * FROM customers WHERE city LIKE'D_';
- B. SELECT * FROM customers WHERE city ='%D_';
- C. SELECT * FROM customers WHERE city LIKE'D %';
- D. SELECT * FROM customers WHERE city ='D_%';
Answer: C
NEW QUESTION # 171
......
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