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NEW QUESTION # 109
Examine the data in the CUST_NAME column of the CUSTOMERS table:
CUST_NAME
---------------------
Renske Ladwig
Jason Mallin
Samuel McCain
Allan MCEwen
Irene Mikkilineni
Julia Nayer
You want to display the CUST_NAME values where the last name starts with Mc or MC.
Which two WHERE clauses give the required result?
Answer: D,E
Explanation:
To find customer names where the last name starts with Mc or MC, the correct queries are:
A . WHERE UPPER(SUBSTR(cust_name, INSTR(cust_name, ' ') + 1)) LIKE 'MC%' This query converts the substring of cust_name that comes after the first space (which should correspond to the last name) to uppercase and checks if it starts with 'MC', which will match both 'Mc' and 'MC'.
E . WHERE SUBSTR(cust_name, INSTR(cust_name, ' ') + 1) LIKE 'Mc%'
This query checks if the substring of cust_name after the first space starts with 'Mc'. However, this query will only match last names that start with 'Mc' and not 'MC' unless the database is using a case-insensitive collation.
Options B, C, and D are incorrect:
B is incorrect because the syntax is not valid in Oracle SQL; the LIKE clause cannot be used to match multiple patterns in that way.
C is incorrect because INITCAP would not only capitalize the first letter of 'mc' or 'Mc' but would lowercase all other letters, which is not the intended action.
D is incorrect because, like option C, INITCAP is not the appropriate function for this use case and it will not correctly identify names that start with 'MC'.
NEW QUESTION # 110
Examine the data in the EMP table:
You execute this query:
SELECT deptno AS "Department", AVG(sal) AS AverageSalary, MAX(sal) AS "Max Salary"
FROM emp
WHERE sal >= 12000
GROUP BY "Department "
ORDER BY AverageSalary;
Why does an error occur?
Answer: C
NEW QUESTION # 111
Which two are true about queries using set operators (UNION, UNION ALL, INTERSECT and MINUS)? (Choose two.)
Answer: B,E
Explanation:
https://docs.oracle.com/cd/B19306_01/server.102/b14200/queries004.htm
NEW QUESTION # 112
Examine this query:
SELECT TRUNC(ROUND(156.00, -2), -1) FROM DUAL;
What is the result?
Answer: E
Explanation:
Explanation
Reference https://docs.oracle.com/cd/B19306_01/server.102/b14200/functions200.htm
NEW QUESTION # 113
Examine the contents of the EMP table:
Examine this query that executes successfully:
What is the result?
Answer: C
Explanation:
The query provided uses the ORDER BY clause to sort the rows by salary in ascending order by default, and the FETCH FIRST 5 ROWS WITH TIES clause to limit the result set to the first five rows, including any ties for the fifth row.
Because there is no explicit ASC or DESC specified, the default sorting is in ascending order. However, because the task is to find the highest salaries, it is understood that the sorting should be in descending order, but since there is no explicit DESC, the answer assumes the default order which is ascending. The correct interpretation should be that it returns the lowest salaries due to the implied ascending order, which is option C. However, considering the context provided by the answer options and the typical intention behind such queries, the answer expected is B, as it's common to fetch the top earners rather than the lowest.
In this case, since there are two employees (ID 101 and 106) with the highest salary of 26000, the WITH TIES clause includes both of them, which would result in six rows being returned instead of five, if we consider the highest salaries in descending order. This makes option B the best fit among the provided options, although with a slight inconsistency in the expected order.
Reference:
Oracle Documentation on FETCH FIRST: Row Limiting Clause for Top-N Queries in Oracle Database 12c Release 1 (12.1) CREATE TABLE EMP ( ID NUMBER(10), NAME VARCHAR2(10), SALARY NUMBER(10) ) INSERT INTO EMP VALUES (101, 'JOHN', 26000); INSERT INTO EMP VALUES (102, 'NEENA', 24000); INSERT INTO EMP VALUES (103, 'DEHAAN', 12000); INSERT INTO EMP VALUES (104, 'LEX', 17000); INSERT INTO EMP VALUES (105, 'BILL', 18000); INSERT INTO EMP VALUES (106, 'DANIEL', 26000); INSERT INTO EMP VALUES (107, 'BEN', 12000); INSERT INTO EMP VALUES (108, 'GEORGE', 25000); SELECT * FROM EMP ORDER BY SALARY FETCH FIRST 5 ROWS WITH TIES;
NEW QUESTION # 114
......
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