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| Section | Weight | Objectives |
|---|
| Topic 1: Data Analysis | 30%-32% | - Perform advanced analytics using SQL
- 1. Time-series analysis
- 2. Snowflake-specific analytical features
- 3. Aggregate functions
|
| Topic 2: Data Transformation and Data Modeling | 22%-30% | - Transform data using SQL
- 1. Window functions
- 2. QUALIFY clauses
- 3. Common Table Expressions (CTEs)
- 4. PIVOT/UNPIVOT operations
- Design data models
- 1. Data vault models
- 2. Star schema design
- 3. Snowflake schema design
|
| Topic 3: Data Presentation and Data Visualization | 28%-29% | - Integrate with BI tools
- 1. Power BI integration
- 2. Other partner visualization tools
- 3. Tableau integration
- Create dashboards
- 1. Snowsight dashboards
- 2. Present analytical results
|
| Topic 4: Data Ingestion and Data Preparation | 15%-20% | - Use a collection system to retrieve data
- 1. Synthetic Data Generation
- 2. Retrieve data from structured sources (CSV)
- 3. Retrieve data from semi-structured sources (Parquet, Avro, ORC, JSON, XML)
- 4. Retrieve data from unstructured sources
- Prepare data and load into Snowflake
- 1. Load files using Snowsight
- 2. Load data from external/internal stages into a table
- Enrich data by identifying and accessing relevant data from the Snowflake Marketplace
- 1. Create tables and views
- 2. Use Secure Data Sharing (Marketplace, Internal Marketplace, Private Listings, Listings)
- 3. Find external data sets that correlate with available data
- Use best practice considerations relating to data integrity structures
- 1. Perform table joins between parent/child tables
- 2. Implement constraints
- 3. Define primary keys for tables
- Implement data processing solutions
- 1. Cleanse, conform, and enrich data
- 2. Use logging and monitoring solutions (auditing, data lineage)
- 3. Automate and implement data pipelines (scheduling)
- 4. Respond to processing failures
- Perform data discovery to identify what is needed from available datasets
- 1. Query tables to assess data elements and statistics maintained by Snowflake
- 2. Identify elements required for business goals using BI reports or SQL analysis
- 3. Evaluate required transformations (table joins, set operations, ASOF JOINS)
- 4. Determine the level of data granularity required
- 5. Use commands to read metadata or alter context (DESCRIBE, SHOW, USE)
|
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Snowflake SnowPro Advanced: Data Analyst Certification Exam Sample Questions (Q53-Q58):
NEW QUESTION # 53
You have a Snowflake table 'order details' with columns 'order id', 'customer id', 'order date', and 'order amount'. You need to calculate the 3-month moving average of 'order_amount' for each customer, but only for those customers who have placed at least 5 orders. Which of the following SQL statements will correctly achieve this? (Assume the current date is '2024-01-01 ')

- A. Option D
- B. Option E
- C. Option B
- D. Option C
- E. Option A
Answer: B
Explanation:
Option E is the correct and most clear solution. It calculates the 3-month moving average, filters customers who have placed at least 5 orders, and leverages the power and clarity of Snowflake syntax. The QUALIFY clause effectively filters for customers with at least 5 orders. The 'RANGE BETWEEN INTERVAL '3 MONTH' PRECEDING AND CURRENT ROW accurately calculates the moving average over a 3- month window based on A, B and C calculate a simple moving average of the last 3 rows regardless of date, while D is syntactically invalid as HAVING cannot be used with window function in this way.
NEW QUESTION # 54
How do materialized views differ from regular views in terms of data access and storage?
- A. Materialized views restrict data access for improved security.
- B. Materialized views provide precomputed snapshots, unlike regular views.
- C. Regular views enhance data accessibility more effectively than materialized views.
- D. Regular views offer better storage optimization compared to materialized views.
Answer: B
Explanation:
Materialized views provide precomputed snapshots, differentiating them from regular views.
NEW QUESTION # 55
A Data Analyst creates and populates the following table:
create or replace table aggr(v int) as select * from values (1), (2), (3), (4); The Analyst then executes this query:
select percentile_disc(0.60) within group (order by v desc) from aggr;
What will be the result?
Answer: B
Explanation:
The PERCENTILE_DISC (discrete percentile) function is an inverse distribution function that assumes a discrete distribution model. It takes a percentile value and a sort specification and returns the value from the set that corresponds to that percentile. Unlike PERCENTILE_CONT, which interpolates between values to find a continuous result, PERCENTILE_DISC always returns an actual value from the input set.
In this scenario, we have a set of four values: $\{1, 2, 3, 4\}$. The query specifies a descending order (order by v desc), so the ordered set for the calculation is $\{4, 3, 2, 1\}$.
To find the discrete percentile, Snowflake calculates the cumulative distribution. For a set of $N$ elements, each element represents a percentile rank of $1/N$. With 4 elements, each covers 25% ($0.25$) of the distribution:
* Value 4: Cumulative Percentile $0.25$
* Value 3: Cumulative Percentile $0.50$
* Value 2: Cumulative Percentile $0.75$
* Value 1: Cumulative Percentile $1.00$
The PERCENTILE_DISC(0.60) function looks for the first value whose cumulative distribution is greater than or equal to the specified percentile ($0.60$).
* $0.25$ (Value 4) is not $\ge 0.60$.
* $0.50$ (Value 3) is not $\ge 0.60$.
* $0.75$ (Value 2) is the first value where the cumulative distribution is $\ge 0.60$.
Therefore, the result is 2. If the order had been ascending (ASC), the cumulative distribution would have been
$\{1: 0.25, 2: 0.50, 3: 0.75, 4: 1.00\}$, and the result for $0.60$ would have been 3. Understanding the impact of the ORDER BY clause within the WITHIN GROUP syntax is a critical skill for the Data Analysis domain of the SnowPro Advanced: Data Analyst exam.
NEW QUESTION # 56
A retail company has data about their products, sales, and inventory. They need a dashboard to visualize key metrics, including total sales, average order value, inventory levels, and product performance across different regions. The data is stored in the following tables: 'PRODUCTS (PRODUCT ID, PRODUCT NAME, CATEGORY, PRICE) 'SALES' (SALE_ID, PRODUCT_ID, SALE_DATE, QUANTITY, REGION) 'INVENTORY (PRODUCT ID, REGION, QUANTITY ON_HAND) Which of the following strategies will result in an efficient dashboard that allows users to quickly filter and drill down into the data by region, product category, and time period while minimizing query execution time? (Select all that apply.)
- A. Implement dynamic data masking policies to filter out sensitive data from the base tables, ensuring data governance.
- B. Create materialized views that pre-aggregate sales data by region, product category, and time period (e.g., daily, weekly, monthly). Join these materialized views with product and inventory data in the dashboard queries.
- C. Utilize Snowflake's search optimization service on relevant columns (e.g., PRODUCT ID, REGION) in the base tables and use standard JOINs and aggregations within views used by the dashboard.
- D. Create a single, wide denormalized table containing all the necessary data from the 'PRODUCTS, 'SALES, and 'INVENTORY tables using JOINs. Build the dashboard directly on this table.
- E. Create separate views for sales, inventory, and product information, then use the dashboard tool to join these views and perform aggregations.
Answer: B,C
Explanation:
Search optimization (C) can significantly speed up queries on large tables by creating a search index on frequently used filter columns. Materialized views (D) are also beneficial because they pre-aggregate the data, reducing the amount of computation required at query time. Creating a single, wide denormalized table (A) can lead to data redundancy and increased storage costs. Joining separate views in the dashboard tool (B) can be inefficient, as the joins are performed at query time. Data masking policies (E) are important for security but don't directly optimize query performance for dashboards.
NEW QUESTION # 57
You're working with time series data in Snowflake, specifically website traffic data with timestamps and page views. You need to calculate the cumulative page views for each day. However, the data contains missing timestamps, and you want to fill those gaps with a default page view count of 0 before calculating the cumulative sum. Which of the following approaches, used in conjunction with a cumulative SUM aggregate function, is MOST efficient?
- A. Use a recursive CTE (Common Table Expression) to generate the missing dates and then UNION ALL with the existing data, filling missing page views with 0 using NVL, prior to applying the cumulative SUM.
- B. Create a separate table containing all dates in the range and LEFT JOIN it with the website traffic data, using COALESCE to fill missing page views with 0 before applying the cumulative SUM.
- C. Use a stored procedure to iterate through the date range, inserting missing dates with a page view count of O before applying the cumulative SUM.
- D. Use a LATERAL FLATTEN function to generate a list of dates, LEFT JOIN it with the website traffic data, and use ZEROIFNULL to fill missing page views with 0 before the cumulative SUM.
- E. Use the 'GENERATE_SERIES' function (if available via UDF) to create a series of dates, LEFT JOIN with the website traffic data, and use COALESCE to fill missing page views with 0 before the cumulative SUM.
Answer: B
Explanation:
Creating a separate date table and using a LEFT JOIN with COALESCE is the most efficient approach. Stored procedures (A) are generally slower for large datasets. Recursive CTEs (C) can be resource-intensive. Using UDFs or Lateral Flatten (D & E) may also increase complexity and overhead compared to a simple JOIN. The key is to leverage Snowflake's ability to handle joins efficiently.
NEW QUESTION # 58
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