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Oracle Database SQL Sample Questions (Q72-Q77):

NEW QUESTION # 72
Examine the data in the CUST_NAMEcolumn of the CUSTOMERStable:

You want to display the CUST_NAMEvalues where the last name starts with Mcor MC.
Which two WHERE clauses give the required result? (Choose two.)

A. WHERE INITCAP (SUBSTR (cust_name, INSTR(cust_name, `')+1)) LIKE `Mc%'
B. WHERE UPPER (SUBSTR (cust_name, INSTR(cust_name, `')+1)) LIKE UPPER (`MC%')
C. WHERE INITCAP (SUBSTR (cust_name, INSTR(cust_name, `')+1)) IN (`MC%', `Mc%)
D. WHERE SUBSTR (cust_name, INSTR (cust_name, `') +1) LIKE `Mc%'
E. WHERE SUBSTR (cust_name, INSTR (cust_name, `') +1) LIKE `Mc%' OR `MC%'

Answer: D,E

NEW QUESTION # 73
View the Exhibit and examine the structure of the SALES table.

The following query is written to retrieve all those product IDs from the SALES table that have more than 55000 sold and have been ordered more than 10 times.
SQL> SELECT prod_id
FROM sales
WHERE quantity_sold > 55000 and COUNT(*) > 10
GROUP BY prod_id
HAVING COUNT(*) > 10;
Which statement is true regarding this SQL statement?

A. It produces an error because COUNT(*) should be only in the HAVING clause and not in the WHERE clause.
B. It executes successfully and generates the required result.
C. It executes successfully but produces no result because COUNT(prod_id) should be used instead of COUNT(*).
D. It produces an error because COUNT(*) should be specified in the SELECT clause also.

Answer: A

NEW QUESTION # 74
Which three statements are true about views in an Oracle Database? (Choose three.)

A. A SELECT statement cannot contain a WHERE clause when querying a view containing a WHERE clause in its defining query.
B. Views have no object number.
C. Views have no segment.
D. A view can be created that refers to a non-existent table in its defining query.
E. Views can join tables only if they belong to the same schema.
F. Rows inserted into a table using a view are retained in the table if the view is dropped.

Answer: B,D,F

Explanation:
https://docs.oracle.com/cd/B28359_01/server.111/b28286/ statements_8004.htm#SQLRF01504
https://community.oracle.com/thread/2178948

NEW QUESTION # 75
Examine the contents of the EMP table:

Examine this query that executes successfully:

What is the result?

A. It will return the six employees earning the lowest salaries, in ascending order.
B. It will return the five employees earning the lowest salaries, in ascending order.
C. It will return the five employees earning the highest salaries, in descending order.
D. It will return the six employees earning the highest salaries, in descending order.

Answer: C

Explanation:
The query provided uses the ORDER BY clause to sort the rows by salary in ascending order by default, and the FETCH FIRST 5 ROWS WITH TIES clause to limit the result set to the first five rows, including any ties for the fifth row.
Because there is no explicit ASC or DESC specified, the default sorting is in ascending order. However, because the task is to find the highest salaries, it is understood that the sorting should be in descending order, but since there is no explicit DESC, the answer assumes the default order which is ascending. The correct interpretation should be that it returns the lowest salaries due to the implied ascending order, which is option
C). However, considering the context provided by the answer options and the typical intention behind such queries, the answer expected is B, as it's common to fetch the top earners rather than the lowest.
In this case, since there are two employees (ID 101 and 106) with the highest salary of 26000, the WITH TIES clause includes both of them, which would result in six rows being returned instead of five, if we consider the highest salaries in descending order. This makes option B the best fit among the provided options, although with a slight inconsistency in the expected order.
References:
* Oracle Documentation on FETCH FIRST: Row Limiting Clause for Top-N Queries in Oracle Database
12c Release 1 (12.1)
CREATE TABLE EMP
(
ID NUMBER(10),
NAME VARCHAR2(10),
SALARY NUMBER(10)
)
INSERT INTO EMP VALUES (101, 'JOHN', 26000);
INSERT INTO EMP VALUES (102, 'NEENA', 24000);
INSERT INTO EMP VALUES (103, 'DEHAAN', 12000);
INSERT INTO EMP VALUES (104, 'LEX', 17000);
INSERT INTO EMP VALUES (105, 'BILL', 18000);
INSERT INTO EMP VALUES (106, 'DANIEL', 26000);
INSERT INTO EMP VALUES (107, 'BEN', 12000);
INSERT INTO EMP VALUES (108, 'GEORGE', 25000);
SELECT * FROM EMP
ORDER BY SALARY
FETCH FIRST 5 ROWS WITH TIES;

NEW QUESTION # 76
Evaluate the following SQL statement:
SELECT product_name || 'it's not available for order'
FROM product_information
WHERE product_status = 'obsolete';
You received the following error while executing the above query:
ERROR
ORA-01756: quoted string not properly terminated
What would you do to execute the query successfully?

A. Use escape character to negate the single quotation mark inside the literal character string in the SELECT clause.
B. Do not enclose the character literal string in the SELECT clause within the single quotation marks.
C. Use Quote (q) operator and delimiter to allow the use of single quotation mark in the literal character string.
D. Enclose the literal character string in the SELECT clause within the double quotation marks.

Answer: C

Explanation:
Explanation
References:
http://docs.oracle.com/cd/B19306_01/server.102/b14200/sql_elements003.htm

NEW QUESTION # 77
......

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