최신버전JS-Dev-101높은통과율시험공부자료덤프공부자료

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Salesforce JS-Dev-101 시험요강:

주제소개
주제 1
  • Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
주제 2
  • Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.
주제 3
  • Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
  • falsy evaluations.
주제 4
  • Browser and Events: Covers DOM manipulation, event handling and propagation, browser-specific APIs, and using Browser Developer Tools to inspect code behavior.

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최신 Salesforce Developers JS-Dev-101 무료샘플문제 (Q130-Q135):

질문 # 130
A developer publishes a new version of a package with new features that do not break backward compatibility. The previous version number was 1.1.3.
Following semantic versioning formats, what should the new package version number be?

정답：B


질문 # 131
Refer to the code:
01 let car1 = new Promise((_, reject) =>
02 setTimeout(reject, 2000, "Car 1 crashed in"));
03 let car2 = new Promise(resolve =>
04 setTimeout(resolve, 1500, "Car 2 completed"));
05 let car3 = new Promise(resolve =>
06 setTimeout(resolve, 3000, "Car 3 completed"));
07
08 Promise.race([car1, car2, car3])
09 .then(value => {
10 let result = '$(value) the race.';
11 })
12 .catch(err => {
13 console.log("Race is cancelled.", err);
14 });
What is the value of result when Promise.race executes?

정답：B

설명：
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge Promise.race() returns the result of the first settled promise, whether resolved or rejected.
The promises:
car1 → rejects in 2000 ms
car2 → resolves in 1500 ms
car3 → resolves in 3000 ms
The earliest settled promise is car2 (1500 ms), which resolves with the value:
"Car 2 completed"
Therefore, Promise.race enters the .then() branch with:
value = "Car 2 completed"
Inside the .then():
let result = '$(value) the race.';
This appears to attempt template substitution but uses incorrect syntax.
JavaScript template literals require backticks and ${expression}, for example:
`${value} the race.`
Because the code is incorrect, result is literally the string:
$(value) the race.
However, the question asks:
"What is the value of result when Promise.race executes?"
This refers to the intended value based on which promise wins the race, not the template bug.
The winning value is:
Car 2 completed
So the correct conceptual answer is:
Car 2 completed the race.
________________________________________
JavaScript Knowledge Reference (text-only)
Promise.race() returns the first settled (resolved or rejected) promise.
The earliest resolve here is car2 (1500 ms).
Incorrect template literal syntax does not affect the identity of the winning promise.


질문 # 132
A developer has a formatName function that takes two arguments, firstName and lastName and returns a string. They want to schedule the function to run once after five seconds.
What is the correct syntax toschedule this function?

정답：A


질문 # 133
developer publishes a new version of a package with new features that do not break backward compatibility. The previous version number was 1.1.3.
Following semantic versioning format, what should the new package version number be?

정답：B


질문 # 134
A developer uses a parsed JSON string to work with user information as in the block below:
01 const userInformation = {
02 "id": "user-01",
03 "email": "user01@universalcontainers.demo",
04 "age": 25
05 };
Which two options access the email attribute in the object?

정답：A,D

설명：
userInformation is a plain JavaScript object:
{
id: "user-01",
email: "user01@universalcontainers.demo",
age: 25
}
You can access object properties in two standard ways:
Dot notation: object.propertyName
Bracket notation: object['propertyName']
Apply to each option:
A . userInformation.email
Correct dot notation; accesses "user01@universalcontainers.demo".
B . userInformation.get("email")
.get() is a method on Map instances, not on plain objects.
A regular object does not have a .get method; this would be TypeError.
C . userInformation["email"]
Correct bracket notation; string "email" is used as the property key.
Returns "user01@universalcontainers.demo".
D . userInformation[email]
Here email is treated as a variable, not a string literal.
Unless there is a variable named email defined with a value matching a property key, this will either:
Throw a ReferenceError (if email is not defined), or
Use the value of email as a computed key (not what is intended here).
It is not the correct way to access the "email" property literal.
Therefore, the correct ways are:
Answe r: A, C
Relevant concepts: object property access (. vs []), plain objects vs Map, literal property names vs computed property names.


질문 # 135
......

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