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Oracle 1z0-071 Exam Syllabus Topics:

Section	Objectives
Relational Database Concepts	- Data types and database objects overview - Tables, rows, columns, and relational model basics
SQL Functions	- Single-row functions 1. Character, numeric, date functions - Conversion and conditional functions 1. TO_CHAR, TO_NUMBER, CASE expressions
SQL Retrieval	- Joins and set operations 1. INNER, OUTER, CROSS joins 2. UNION, INTERSECT, MINUS - SELECT statements and filtering data 1. WHERE clause and conditions 2. ORDER BY and row limiting
Data Manipulation and Schema Objects	- DML operations 1. INSERT, UPDATE, DELETE, MERGE - DDL operations 1. CREATE, ALTER, DROP tables and constraints
Subqueries and Advanced SQL	- Single-row and multi-row subqueries - Correlated subqueries and nested queries

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Oracle Database SQL Sample Questions (Q55-Q60):

NEW QUESTION # 55
Examine the description of the TRANSACTIONS table:

Which two SQL statements execute successfully?

A. SELECT customer_id AS "CUSTOMER-ID", transaction_date AS DATE, amount + 100 "DUES" FROM transactions;
B. SELECT customer_id AS 'CUSTOMER-ID', transaction_date AS DATE, amount + 100 'DUES' FROM transactions;
C. SELECT customer_id AS "CUSTOMER-ID", transaction_date AS "DATE", amount + 100 DUES FROM transactions;
D. SELECT customer_id CUSTID, transaction_date TRANS_DATE, amount +100 DUES FROM transactions;
E. SELECT customer_id AS CUSTOMER-ID, transaction_date AS TRANS_DATE, amount + 100 "DUES AMOUNT" FROM transactions;

Answer: C,D

NEW QUESTION # 56
Which two statements execute successfully? (Choose two.)

Answer: D,E

NEW QUESTION # 57
View the Exhibit and examine the structure of the EMPLOYEES table.
You want to display all employees and their managers having 100 as the MANAGER_ID. You want the output in two columns: the first column would have the LAST_NAME of the managers and the second column would have LAST_NAME of the employees.

Which SQL statement would you execute?

A. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
WHERE m.employee_id = e.manager_id AND e.managerjd=100;
B. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE e.managerjd=100;
C. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON e.employee_id = m.manager_id
WHERE m.manager_id=100;
D. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE m.manager_id=100;

Answer: B

NEW QUESTION # 58
You have the privileges to create any type of synonym.
Which stalement will create a synonym called EMP for the HCM.EMPLOYEE_RECORDS table that is accesible to all users?

A. CREATE SYNONYM PUBLIC.emp FOR hcm.employee_records;
B. CREATE PUBLIC SYNONYM emp FOR hcm. employee_records;
C. CREATE SYNONYM emp FOR hcm.employee_records;
D. CREATE SYNONYM SYS.emp FOR hcm.employee_records;
E. CREATE GLOBAL SYNONYM emp FOR hcm.employee_records;

Answer: B

Explanation:
Synonyms in Oracle are aliases for database objects that can simplify SQL statements for database users.
A . The term "GLOBAL" is not used in the creation of synonyms in Oracle.
B . The statement without the keyword PUBLIC will create a private synonym that is only accessible to the user creating the synonym, not all users.
C . The correct syntax does not include PUBLIC as a prefix to the synonym name itself, making this option incorrect.
D . You cannot specify the SYS schema for creating synonyms, as it is reserved for system objects.
E . This is the correct syntax to create a public synonym, which makes the underlying object accessible to all users.
Reference:
Oracle Database SQL Language Reference, 12c Release 1 (12.1): "CREATE SYNONYM"

NEW QUESTION # 59
Examine this SELECT statement and view the Exhibit to see its output:

SELECT constraints_name, constraints_type, search_condition, r_constraint_name, delete_rule, status,
FROM user_constraints
WHERE table_name = 'ORDERS';
Which two statements are true about the output? (Choose two.)

A. In the second column, 'c' indicates a check constraint.
B. The R_CONSTRAINT_NAME column contains an alternative name for the constraint.
C. The STATUS column indicates whether the table is currently in use.
D. The DELETE_RULE column indicates the desired state of related rows in the child table when the corresponding row is deleted from the parent table.

Answer: A,D

NEW QUESTION # 60
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