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Oracle 1z0-071 certification exam is a multiple-choice exam that consists of 73 questions. You have 105 minutes to complete the exam, and the passing score is 63%. 1z0-071 exam is available in multiple languages, including English, Japanese, and Simplified Chinese.
Oracle 1z0-071 exam covers a wide range of topics related to SQL and Oracle databases, including SQL queries, data manipulation, data control language (DCL) and data definition language (DDL) statements, table creation and management, and database security. It also covers advanced SQL concepts such as subqueries, set operators, and data aggregation functions. 1z0-071 Exam consists of 73 multiple-choice questions that must be answered within 100 minutes, and requires a score of at least 63% to pass.
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Oracle 1z1-071 (Oracle Database SQL) Certification Exam is an industry-recognized certification program that validates an individual's skills and knowledge in SQL database. 1z0-071 Exam is designed to test the candidate's ability to manage, maintain, and manipulate data using SQL language. Oracle Database SQL certification is highly valued in the IT industry, and passing the exam opens up a range of career opportunities for individuals.
Oracle Database SQL Sample Questions (Q77-Q82):
NEW QUESTION # 77
View the Exhibit and examine the structure of the ORDER_ITEMS table. (Choose the best answer.)

You must select the ORDER_ID of the order that has the highest total value among all the orders in the ORDER_ITEMS table.
Which query would produce the desired result?
- A. SELECT order_idFROM order_itemsGROUP BY order_idHAVING SUM(unit_price*quantity) = (SELECT MAX (SUM(unit_price*quantity))FROM order_items GROUP BY order_id);
- B. SELECT order_idFROM order_itemsWHERE(unit_price*quantity)
MAX(unit_price*quantity)GROUP BY order_id); - C. SELECT order_idFROM order_itemsWHERE (unit_price*quantity) = (SELECT MAX(unit_price*quantity)FROM order_itemsGROUP BY order_id)
- D. SELECT order_idFROM order_itemsWHERE(unit_price*quantity) = (SELECT MAX (SUM(unit_price*quantity)FROM order_items) GROUP BY order_id);
Answer: A
NEW QUESTION # 78
Examine the commands used to create DEPARTMENT_DETAILSand COURSE_DETAILS:

You want to generate a report that shows all course IDs irrespective of whether they have corresponding department IDs or not but no department IDs if they do not have any courses.
Which SQL statement must you use?
SELECT course_id, department_id, FROM department_details d RIGHT OUTER JOIN
- A. .department_details d ON (c.depatrment_id=d.department_id)
SELECT c.course_id, d.department_id FROM course_details c FULL OUTER JOIN - B. course_details c USING (department_id)
SELECT c.course_id, d.department_id FROM course_details c RIGHT OUTER JOIN - C. department_details d ON (c.department_id=d. department_id)
SELECT c.course_id, d.department_id FROM course_details c FULL OUTER JOIN - D. department_details d ON (c.department_id<>d. department_id)
Answer: C
NEW QUESTION # 79
Which three statements are true regarding the WHEREand HAVINGclauses in a SQL statement? (Choose three.)
- A. WHEREand HAVINGclauses cannot be used together in a SQL statement.
- B. The HAVINGclause conditions can have aggregate functions.
- C. The WHEREclause is used to exclude rows before the grouping of data.
- D. The HAVINGclause conditions can use aliases for the columns.
- E. The HAVINGclause is used to exclude one or more aggregated results after grouping data.
Answer: A,B,C
NEW QUESTION # 80
View the Exhibit and examine the structure of the ORDERStable.

Which UPDATE statement is valid?
- A. UPDATE orders
SET order_date = '12-mar-2007',
order_total = NULL
WHERE order_id = 2455; - B. UPDATE orders
SET order_date = TO_DATE('12-mar-2007','dd-mon-yyyy'),
SET order_total = TO_NUMBER (NULL)
WHERE order_id = 2455; - C. UPDATE orders
SET order_date = '12-mar-2007',
AND order_total = TO_NUMBER(NULL)
WHERE order_id = 2455; - D. UPDATE orders
SET order_date = '12-mar-2007',
order_total IS NULL
WHERE order_id = 2455;
Answer: A
NEW QUESTION # 81
View the Exhibit and examine the description of the EMPLOYEES table.

Evaluate the following SQL statement:
SELECT first_name, employee_id, NEXT_DAY(ADD_MONTHS(hire_date, 6), 1) "Review" FROM employees; The query was written to retrieve the FIRST_NAME, EMPLOYEE_ID, and review date for employees. The review date is the firsts Monday after the completion of six months of the hiring. The NLS_TERRITORY parameter is set to AMERICA in the session.
Which statement is true regarding this query?
- A. The query would execute but the output would give review dates that are Sundays.
- B. The query would not execute because date functions cannot be nested.
- C. The query would not execute because the NEXT_DAY function accepts a string as argument.
- D. The query would execute to give the desired output.
Answer: A
NEW QUESTION # 82
......
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