1z0-071 Zertifizierung - 1z0-071 Prüfungsfrage

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Oracle 1z0-071 Exam Syllabus Topics:

Section	Weight	Objectives
Using Subqueries to Solve Queries	15%	- List the types of subqueries - Describe the types of problems that subqueries can solve - Write single-row and multi-row subqueries - Define subqueries
Retrieving Data Using the SQL SELECT Statement	5%	- Differentiate between SQL statements and SQL*Plus commands - Execute a basic SELECT statement - List the capabilities of SQL SELECT statements
Manipulating Data	14%	- Update rows in a table - Insert rows into a table - Control transactions - Delete rows from a table - Describe each data manipulation language (DML) statement
Using DDL Statements to Create and Manage Tables	14%	- Describe the data types that are available for columns - Review the table structure - Drop, rename, and truncate tables - Alter table definitions - Create a simple table - Categorize the main database objects
Reporting Aggregated Data Using Group Functions	15%	- Identify the available group functions - Group data by using the GROUP BY clause - Describe the use of group functions - Include or exclude grouped rows by using the HAVING clause
Restricting and Sorting Data	6%	- Use ampersand substitution to restrict and sort output at runtime - Use DEFINE and UNDEFINE commands - Limit the rows that are retrieved by a query - Sort the rows that are retrieved by a query
Controlling User Access	5%	- Differentiate system privileges from object privileges - Grant privileges on tables and on a view - Distinguish between granting privileges and roles
Working with Oracle Database SQL	8%	- Describe the Oracle Database architecture - Start up and shut down a database - Create a container database - Explain the installation of Oracle Database software
Using Single-Row Functions to Customize Output	10%	- Describe the differences between single-row and multiple-row functions - Manipulate numbers with the ROUND, TRUNC, and MOD functions - Manipulate strings with character function in the SELECT and WHERE clauses - Perform arithmetic with date data - Manipulate dates with the date functions
Creating Other Schema Objects	10%	- Create, maintain, and use sequences - Create synonyms for database objects - Create and maintain indexes - Create, modify, and retrieve data from a view
Using Conversion Functions and Conditional Expressions	10%	- Apply the NVL, NULLIF, and COALESCE functions to data - Use conditional IF THEN ELSE logic in a SELECT statement - Use the TO_CHAR, TO_NUMBER, and TO_DATE conversion functions - Describe implicit and explicit data type conversion
Displaying Data from Multiple Tables Using Joins	15%	- View data that does not meet a join condition by using outer joins - Write SELECT statements to access data from more than one table using equijoins and non-equijoins - Cross join tables - Join a table to itself by using a self-join
Using Set Operators	5%	- Use a set operator to combine multiple queries into a single query - Describe the order of precedence when the set operators are used - Describe set operators

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1z0-071 Zertifizierungsfragen, Oracle 1z0-071 PrüfungFragen

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Oracle Database SQL 1z0-071 Prüfungsfragen mit Lösungen (Q282-Q287):

282. Frage
You issued this command: DROP TABLE hr. employees;
Which three statements are true?

A. The HR. EMPLOYEES table may be moved to the recycle bin.
B. ALL constraints defined on HR, EMPLOYEES are dropped.
C. Sequences used to populate columns in the HR. EMPLOYEES table are dropped.
D. Synonyms for HR EMPLOYEES are dropped.
E. Views referencing HR, EMPLOYEES are dropped.
F. All indexes defined on HR, EMPLOYEES are dropped.

Antwort: A,B,F

283. Frage
You are designing the structure of a table in which two columns have the specifications:
COMPONENT_ID- must be able to contain a maximum of 12 alphanumeric characters and must uniquely identify the row EXECUTION_DATETIME- contains Century, Year, Month, Day, Hour, Minute, Second to the maximum precision and is used for calculations and comparisons between components.
Which two options define the data types that satisfy these requirements most efficiently? (Choose two.)

A. The EXECUTION_DATETIME must be of TIMESTAMP data type.
B. The COMPONENT_IDmust be of ROWID data type.
C. The EXECUTION_DATETIME must be of DATE data type.
D. The COMPONENT_IDcolumn must be of CHAR data type.
E. The EXECUTION_DATETIME must be of INTERVAL DAY TO SECOND data type.
F. The COMPONENT_IDmust be of VARCHAR2 data type.

Antwort: C,D

284. Frage
You want to display the date for the first Monday of the next month and issue the following command:

What is the outcome?

A. It executes successfully but does not return the correct result.
B. In generates an error because TO_CHAR should be replaced with TO_DATE.
C. In generates an error because rrrr should be replaced by rr in the format string.
D. It executes successfully and returns the correct result.
E. In generates an error because fm and double quotation marks should not be used in the format string.

Antwort: D

285. Frage
Examine the description products table:

Examine the description of the new_projects table;

Which two queries execute successfully?

Antwort: D,E

Begründung:
To determine which queries will execute successfully, we need to consider the compatibility of the column definitions and the structure of the SELECT statements:
* Option A uses the MINUS set operator, which subtracts rows returned by the second SELECT statement from the rows returned by the first. For MINUS to work, the number and the order of columns and their data types must be the same in both queries. This query will not execute successfully because the second SELECT statement does not include all columns from the first SELECT statement, and the data types and sizes of PROD_ID do not match (CHAR(2) vs CHAR(4)).
* Option B uses the UNION ALL set operator, which appends the results of the second SELECT statement to the results of the first. Unlike UNION, UNION ALL does not eliminate duplicate rows.
This query will execute successfully because UNION ALL does not require the same data types or sizes, and the result will contain all columns from the first SELECT statement filled with NULL for non-matching columns from the second SELECT statement.
* Option C uses the UNION set operator, which requires the same number of columns and compatible data types. This query will not execute successfully because PROD_NAME has different data types (CHAR(4) vs VARCHAR2(10)), and the result of a UNION must have the same number of columns with compatible data types in the two SELECT statements.
* Option D uses the UNION set operator as well, but unlike Option C, it does not require a specific data type match because both SELECT statements include all columns and UNION is used (which will automatically handle type conversion where necessary). This query will execute successfully.
* Option E uses the INTERSECT set operator, which requires the same number and order of columns and their data types to be identical or compatible. This query will not execute successfully because the data types and sizes of PROD_ID do not match (CHAR(2) vs CHAR(4)).
References:
* Oracle Documentation on Set Operators: SQL Language Reference - Set Operators
* Oracle Documentation on Data Type Precedence: SQL Language Reference - Data Type Precedence In conclusion, only Option B and Option D will execute successfully because they adhere to the rules of the UNION ALL and UNION operators respectively, regarding column count and data type compatibility.

286. Frage
Examine the description of the CUSTOMERS table:

CUSTNO is the PRIMARY KEY.
You must determine if any customers' details have been entered more than once using a different CUSTNO, by listing all duplicate names.
Which two methods can you use to get the required result?

A. FULL OUTER JOIN with self join
B. subquery
C. RIGHT OUTER JOIN with self join
D. self join
E. LEFT OUTER JOIN with self join

Antwort: B,D

287. Frage
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