真正全新的1z1-071考古題 -順利通過Oracle Database SQL - 1z1-071考試

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Oracle 1z1-071 Exam Overview:

Certification Vendor:	Oracle
Exam Name:	Oracle Database SQL
Exam Number:	1Z0-071
Exam Format:	Multiple Select, Multiple Choice
Certificate Validity Period:	18 months
Related Certifications:	Oracle Database Administrator Certified Associate Oracle Database Developer Certified Associate
Passing Score:	63%
Available Languages:	Traditional Chinese, Simplified Chinese, Korean, Spanish, English, Japanese
Exam Price:	US$245
Real Exam Qty:	63 - 78
Exam Duration:	120 minutes
Recommended Training:	Oracle Database 19c: SQL Workshop Oracle Database SQL Fundamentals
Exam Registration:	Pearson VUE Registration Oracle University Registration
Sample Questions:	Oracle 1z1-071 Sample Questions
Exam Way:	Online proctored or Onsite at Pearson VUE test centers
Pre Condition:	No mandatory prerequisites; basic knowledge of SQL and relational databases recommended
Official Syllabus URL:	https://education.oracle.com/pexam_1Z0-071

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最新的 Oracle PL/SQL Developer Certified Associate 1z1-071 免費考試真題 (Q147-Q152):

問題 #147
In the customers table, the CUST_CITY column contains the value 'Paris' for the
CUST_FIRST_NAME 'Abigail'.
Evaluate the following query:

What would be the outcome?

A. Abigail PA
B. An error message
C. Abigail IS
D. Abigail Pa

答案：D

問題 #148
View the Exhibit and examine the structure of the CUSTOMERStable.

Using the CUSTOMERStable, you must generate a report that displays a credit limit increase of 15% for all customers.
Customers with no credit limit should have "Not Available" displayed.
Which SQL statement would produce the required result?
SELECT NVL(TO_CHAR(cust_credit_limit*.15),'Not Available') "NEW CREDIT"

A. FROM customers;
B. FROM customers;
SELECT NVL(cust_credit_limit,'Not Available')*.15 "NEW CREDIT"
C. FROM customers;
SELECT NVL(cust_credit_limit*.15,'Not Available') "NEW CREDIT"
D. FROM customers;
SELECT TO_CHAR(NVL(cust_credit_limit*.15,'Not Available')) "NEW CREDIT"

答案：D

問題 #149
Which two statements are true about the results of using the intersect operator in compound queries?

A. The number of columns in each select in the compound query can be different.
B. Column names in each select in the compound query can be different.
C. intersect returns rows common to both sides of the compound query.
D. Reversing the order of the intersected tables can sometimes affect the output.
E. intersect ignores nulls.

答案：B,C

問題 #150
Examine the description of the PRODUCT_ DETAILS table:

Which two statements are true?

A. EXPIRY_ DATE contains the SYSDATE by default if no date is assigned to it.
B. PRODUCT_ NAME cannot contain duplicate values.
C. PRODUCT_ ID can be assigned the PRIMARY KEY constraint.
D. EXPIRY_ DATE cannot be used in arithmetic expressions.
E. PRODUCT_ PRICE contains the value zero by default if no value is assigned to it.
F. PRODUCT_ PRICE can be used in an arithmetic expression even if it has no value stored in it.

答案：C,D

解題說明：
In reference to the attributes of the PRODUCT_DETAILS table:
A). This statement is false. If PRODUCT_PRICE has no value (i.e., it is NULL), it cannot be used directly in arithmetic expressions because any operation with NULL results in NULL.
B). This statement is true. PRODUCT_ID has the NOT NULL constraint and is of type NUMBER, making it eligible to be a PRIMARY KEY. Primary keys require all values to be unique and not null.
C). This statement is true. EXPIRY_DATE is of type DATE, and it cannot be used in arithmetic expressions directly without a date function that operates on dates.
D). This statement is false. By default, columns of type DATE do not have a default value unless explicitly assigned using the DEFAULT keyword in the column definition.
E). This statement is false. By default, numeric columns do not have a default value unless specified with the DEFAULT keyword.
F). This statement is false. The statement about PRODUCT_NAME not containing duplicate values would be true if it were a UNIQUE or PRIMARY KEY, but there is no such constraint indicated in the provided table description.

問題 #151
The CUSTOMERStable has a CUST_CREDIT_LIMITcolumn of data type NUMBER.
Which two queries execute successfully? (Choose two.)

A. SELECT NVL2(cust_credit_limit, TO_CHAR(cust_credit_limit * .15), 'Not
B. SELECT TO_CHAR(NVL(cust_credit_limit * .15, 'Not Available')) FROM customers;
C. Available') FROM customers;
SELECT NVL2(cust_credit_limit * .15, 'Not Available') FROM customers;
D. SLECT NVL(TO_CHAR(cust_credit_limit * .15), 'Not Available') FROM customers;
E. SELECT NVL(cust_credit_limit * .15, 'Not Available') FROM customers;

答案：C,D

問題 #152
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