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| Section | Objectives |
|---|---|
| Topic 1: Browser and DOM Interaction | - DOM Manipulation - Events and Event Handling |
| Topic 2: Salesforce Platform Integration | - Lightning Web Components (LWC) Basics - Working with Salesforce Data Models |
| Topic 3: JavaScript Fundamentals | - Variables, Data Types, and Operators - Control Flow and Error Handling - Functions and Scope |
| Topic 4: Object-Oriented JavaScript | - Classes and Inheritance - Objects and Prototypes |
| Topic 5: Asynchronous Programming | - API Calls and Data Fetching - Callbacks, Promises, and Async/Await |
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NEW QUESTION # 61
HTML:
<p> The current status of an Order: <span id="status"> In Progress </span> </p> Which JavaScript statement changes 'In Progress' to 'Completed'?
Answer: D
Explanation:
To select an element by ID, JavaScript uses:
document.getElementById("status")
The ID must be passed without any selector prefixes (no dot, no hash).
Then, to update the text inside:
element.innerHTML = 'Completed';
Why the others are wrong:
A uses ".status" which would match a CSS class, not an ID.
B incorrectly prepends #, which is used in CSS selectors but not in getElementById.
D attempts to use .Value with capital V, which is incorrect for DOM text; .value only applies to form elements.
Thus, option C is correct.
JavaScript Knowledge Reference (text-only)
getElementById takes a raw ID string with no prefixes.
innerHTML updates an element's displayed HTML content.
NEW QUESTION # 62
A developer needs to debug a Node.js web server because a runtime error keeps occurring at one of the endpoints.
The developer wants to test the endpoint on a local machine and make the request against a local server to look at the behavior. In the source code, the server.js file will start the server. The developer wants to debug the Node.js server only using the terminal.
Which command can the developer use to open the CLI debugger in their current terminal window?
(With corrected typing errors: node_inspect โ node inspect, node_start_inspect โ node start inspect.)
Answer: A
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
Node.js includes a built-in command-line (CLI) debugger. To use it directly in the terminal, the standard command is:
node inspect server.js
This:
Starts server.js under the Node.js inspector.
Opens the CLI debugger right in the terminal window where you ran the command.
Lets you interactively:
Step through code
Set breakpoints
Inspect variables
Continue execution, etc.
Why B is correct:
Option B (corrected to node inspect server.js) is exactly the standard Node.js command to run a script under the CLI debugger in the current terminal.
It does not rely on any external GUI tools.
You stay entirely in the terminal to debug.
Why the other options are incorrect:
A . node start inspect server.js
There is no start subcommand like this in standard Node.js CLI.
This is not a valid Node.js debugging command.
C . node server.js --inspect
This starts Node.js with the Inspector protocol enabled and is typically used to connect external tools like Chrome DevTools or VS Code.
It does not open the CLI debugger in the current terminal. Instead, it opens a debugging port that other tools attach to.
The question specifically says "only using the terminal" and "open the CLI debugger in their current terminal window", which points to node inspect, not --inspect.
D . node -i server.js
-i starts Node in interactive REPL mode, optionally after running a script.
This is for an interactive shell, not the Node debugger.
It does not provide breakpoint/step/next/continue debugging features like the CLI debugger.
Therefore, the only option that opens the Node.js CLI debugger in the current terminal is:
JavaScript / Node.js knowledge / Study Guide references (concept names only, no links):
Node.js CLI debugger: node inspect <script>
Node.js inspector protocol: node --inspect
Difference between CLI debugger and DevTools-based debugging
Node.js command-line options and subcommands
________________________________________
NEW QUESTION # 63
01 function Animal(size, type) {
02 this.type = type || 'Animal';
03 this.canTalk = false;
04 }
05
06 Animal.prototype.speak = function() {
07 if (this.canTalk) {
08 console.log("It spoke!");
09 }
10 };
11
12 let Pet = function(size, type, name, owner) {
13 Animal.call(this, size, type);
14 this.size = size;
15 this.name = name;
16 this.owner = owner;
17 }
18
19 Pet.prototype = Object.create(Animal.prototype);
20 let pet1 = new Pet();
Given the code above, which three properties are set for pet1?
Answer: A,B,C
Explanation:
When pet1 = new Pet(); is created:
Inside Pet constructor:
Animal.call(this, size, type);
this.size = size;
this.name = name;
this.owner = owner;
Animal.call(this, size, type):
Sets this.type = type || 'Animal' โ 'Animal' (because type is undefined).
Sets this.canTalk = false.
Then this.size, this.name, this.owner are set (to undefined since no args passed), but they do exist as properties.
So as own properties, pet1 has: type, canTalk, size, name, owner.
speak is defined on Animal.prototype, so pet1.speak exists by inheritance, but is not an own data property created in the constructor.
From the listed options, three important properties directly set by constructor logic and clearly used in behavior are:
canTalk
name
type
Thus, C, D, E.
NEW QUESTION # 64
A developer wrote the following code:
01 let X = object.value;
02
03 try {
04 handleObjectValue(X);
05 } catch (error) {
06 handleError(error);
07 }
Thedeveloper has a getNextValue function to execute after handleObjectValue(), but does not want to execute getNextValue() if an error occurs.
How can the developer change the code to ensure this behavior?
Answer: D
NEW QUESTION # 65
In which situation should a developer include a try .. catch block around their function call ?
Answer: D
NEW QUESTION # 66
......
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