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Salesforce JS-Dev-101 Exam Syllabus Topics:

TopicDetails
Topic 1
  • Testing: Covers evaluating unit test effectiveness against a block of code and modifying tests to improve their coverage and reliability.
Topic 2
  • Browser and Events: Covers DOM manipulation, event handling and propagation, browser-specific APIs, and using Browser Developer Tools to inspect code behavior.
Topic 3
  • Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
  • falsy evaluations.
Topic 4
  • Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.
Topic 5
  • Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.
Topic 6
  • Debugging and Error Handling: Covers proper error handling techniques and the use of the console and breakpoints to debug code.

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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q12-Q17):

NEW QUESTION # 12
Refer to the code below:
Let str = 'javascript';
Str[0] = 'J';
Str[4] = 'S';
After changing the string indexvalues, the value of str is 'javascript'. What is the reason for this value:

Answer: A


NEW QUESTION # 13
Refer to the code snippet:
01 function getAvailableilityMessage(item) {
02 if (getAvailableility(item)) {
03 var msg = "Username available";
04 }
05 return msg;
06 }
What is the return value of msg when getAvailableilityMessage("newUserName") is executed and getAvailableility("newUserName") returns false?

Answer: C

Explanation:
Key details:
var has function scope, not block scope.
Declaration var msg is hoisted to the top of the function, but initialization only happens if the if condition is true.
Effectively, the function behaves like:
function getAvailableilityMessage(item) {
var msg; // hoisted declaration
if (getAvailableility(item)) {
msg = "Username available";
}
return msg;
}
Now, given:
getAvailableility("newUserName") returns false.
Execution:
The if condition is false, so the body does not execute.
Therefore msg is declared but never assigned.
In JavaScript, an uninitialized variable that has been declared with var has the value undefined.
Thus:
return msg; // returns undefined
Why other options are wrong:
A: "newUserName" - msg never receives the parameter value; it's only set to "Username available" inside the if, which does not run.
B: "msg is not defined" - That kind of error occurs if msg were never declared. Here it is declared via var, so it is defined but undefined.
D: "Username available" - This would require the if branch to run, which it does not when getAvailableility(...) is false.
So the return value is:
undefined
Study Guide Concepts:
var hoisting and function scope
Uninitialized variables default to undefined
Control flow and conditional initialization


NEW QUESTION # 14
A developer imports:
import printPrice from '/path/PricePrettyPrint.js';
What must be true about printPrice for this import to work?

Answer: D

Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge The syntax:
import printPrice from 'module';
means the module must export its function as a default export:
export default function printPrice() { ... }
Why the others are wrong:
Named exports require curly braces:
import { printPrice } from 'module';
"all export" and "multi export" are not JavaScript terms.
Therefore, printPrice must be the default export.
________________________________________
JavaScript Knowledge Reference (text-only)
Default imports use: import name from 'module'.
Named imports require braces: import { name } from 'module'.


NEW QUESTION # 15
function myFunction() {
a = a + b;
var b = 1;
}
myFunction();
console.log(a);
console.log(b);
Which statement is correct?

Answer: B

Explanation:
The correct answer is A, not D.
Inside myFunction(), the declaration:
var b = 1;
is hoisted to the top of the function scope, but only the declaration is hoisted, not the assignment. So internally, JavaScript treats the function approximately like this:
function myFunction() {
var b;
a = a + b;
b = 1;
}
Now examine this line:
a = a + b;
Before JavaScript can assign a value to a, it must first evaluate the right-hand side:
a + b
At this point:
b
exists locally because var b was hoisted, so its value is:
undefined
However:
a
has not been declared anywhere. Reading an undeclared variable causes a:
ReferenceError
So this line throws an error before assignment happens:
a = a + b;
Because the error occurs on that line, the next line inside the function is never executed:
var b = 1;
Also, because the error is not handled with try...catch, the program stops before reaching:
console.log(a);
console.log(b);
Therefore, the accurate statement is:
Line 02 throws a reference error, therefore line 03 is never executed.
So the verified answer is A.


NEW QUESTION # 16
A developer wrote the following code:
01 let X = object.value;
02
03 try {
04 handleObjectValue(X);
05 } catch (error) {
06 handleError(error);
07 }
Thedeveloper has a getNextValue function to execute after handleObjectValue(), but does not want to execute getNextValue() if an error occurs.
How can the developer change the code to ensure this behavior?

Answer: C


NEW QUESTION # 17
......

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