Exam ARA-C01 Practice - ARA-C01 Clearer Explanation

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Snowflake ARA-C01 Exam Syllabus Topics:

SectionWeightObjectives
Data Engineering25%- Data Transformation
  • 1. Semi-structured data processing
  • 2. ETL and ELT design
  • 3. Data modeling strategies
- Data Loading and Pipelines
  • 1. Bulk and continuous data loading
  • 2. External stages and file formats
  • 3. Streams and CDC
  • 4. Snowpipe and tasks
Accounts and Security25%- Governance and Compliance
  • 1. Object ownership and privilege management
  • 2. Encryption and security architecture
  • 3. Data governance strategies
- Access Control and Authentication
  • 1. SSO and MFA
  • 2. Network policies
  • 3. Role-based access control
  • 4. Data masking and row access policies
Snowflake Architecture30%- Platform Architecture Design
  • 1. Cross-region and cross-cloud architecture
  • 2. Multi-account strategies
  • 3. Organization and account structure
  • 4. Data sharing architecture
- Storage and Compute Design
  • 1. Warehouse sizing and scaling
  • 2. Micro-partitions and clustering
  • 3. Database and schema design
Performance Optimization20%- Cost and Resource Optimization
  • 1. Concurrency scaling
  • 2. Warehouse cost optimization
  • 3. Resource monitors
- Query Performance
  • 1. Materialized views
  • 2. Search optimization service
  • 3. Caching strategies
  • 4. Query profiling and tuning

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Snowflake SnowPro Advanced Architect Certification Sample Questions (Q199-Q204):

NEW QUESTION # 199
There are two databases in an account, named fin_db and hr_db which contain payroll and employee data, respectively. Accountants and Analysts in the company require different permissions on the objects in these databases to perform their jobs. Accountants need read-write access to fin_db but only require read-only access to hr_db because the database is maintained by human resources personnel.
An Architect needs to create a read-only role for certain employees working in the human resources department.
Which permission sets must be granted to this role?

Answer: B


NEW QUESTION # 200
A healthcare company wants to share data with a medical institute. The institute is running a Standard edition of Snowflake; the healthcare company is running a Business Critical edition.
How can this data be shared?

Answer: C

Explanation:
By default, Snowflake does not allow sharing data from a Business Critical edition to a non-Business Critical edition. This is because Business Critical edition provides enhanced security and data protection features that are not available in lower editions. However, this restriction can be overridden by setting the share_restriction parameter on the shared object (database, schema, or table) to false. This parameter allows the data provider to explicitly allow sharing data with lower edition accounts. Note that this parameter can only be set by the data provider, not the data consumer. Also, setting this parameter to false may reduce the level of security and data protection for the shared data.
References:
* Enable Data Share:Business Critical Account to Lower Edition
* Sharing Is Not Allowed From An Account on BUSINESS CRITICAL Edition to an Account On A Lower Edition
* SQL Execution Error: Sharing is Not Allowed from an Account on BUSINESS CRITICAL Edition to an Account on a Lower Edition
* Snowflake Editions | Snowflake Documentation


NEW QUESTION # 201
A table, EMP_ TBL has three records as shown:

The following variables are set for the session:

Which SELECT statements will retrieve all three records? (Select TWO).

Answer: A,E

Explanation:
* The correct answer is B and E because they use the correct syntax and values for the identifier function and the session variables.
* The identifier function allows you to use a variable or expression as an identifier (such as a table name or column name) in a SQL statement. It takes a single argument and returns it as an identifier. For example, identifier($tbl_ref) returns EMP_TBL as an identifier.
* The session variables are set using the SET command and can be referenced using the $ sign. For example, $var1 returns Name1 as a value.
* Option A is incorrect because it uses Stbl_ref and Scol_ref, which are not valid session variables or identifiers. They should be $tbl_ref and $col_ref instead.
* Option C is incorrect because it uses identifier<Stbl_ref>, which is not a valid syntax for the identifier
* function. It should be identifier($tbl_ref) instead.
* Option D is incorrect because it uses Cvarl, var2, and var3, which are not valid session variables or values. They should be $var1, $var2, and $var3 instead. References:
* Snowflake Documentation: Identifier Function
* Snowflake Documentation: Session Variables
* Snowflake Learning: SnowPro Advanced: Architect Exam Study Guide


NEW QUESTION # 202
An Architect entered the following commands in sequence:

USER1 cannot find the table.
Which of the following commands does the Architect need to run for USER1 to find the tables using the Principle of Least Privilege? (Choose two.)

Answer: A,C

Explanation:
Explanation
* According to the Principle of Least Privilege, the Architect should grant the minimum privileges necessary for the USER1 to find the tables in the SANDBOX database.
* The USER1 needs to have USAGE privilege on the SANDBOX database and the SANDBOX.PUBLIC schema to be able to access the tables in the PUBLIC schema. Therefore, the commands B and C are the correct ones to run.
* The command A is not correct because the PUBLIC role is automatically granted to every user and role in the account, and it does not have any privileges on the SANDBOX database by default.
* The command D is not correct because it would transfer the ownership of the SANDBOX database from the Architect to the USER1, which is not necessary and violates the Principle of Least Privilege.
* The command E is not correct because it would grant all the possible privileges on the SANDBOX database to the USER1, which is also not necessary and violates the Principle of Least Privilege.
References: : Snowflake - Principle of Least Privilege : Snowflake - Access Control Privileges : Snowflake - Public Role : Snowflake - Ownership and Grants


NEW QUESTION # 203
An Architect for a multi-national transportation company has a system that is used to check the weather conditions along vehicle routes. The data is provided to drivers.
The weather information is delivered regularly by a third-party company and this information is generated as JSON structure. Then the data is loaded into Snowflake in a column with a VARIANT data type. This table is directly queried to deliver the statistics to the drivers with minimum time lapse.
A single entry includes (but is not limited to):
- Weather condition; cloudy, sunny, rainy, etc.
- Degree
- Longitude and latitude
- Timeframe
- Location address
- Wind
The table holds more than 10 years' worth of data in order to deliver the statistics from different years and locations. The amount of data on the table increases every day.
The drivers report that they are not receiving the weather statistics for their locations in time.
What can the Architect do to deliver the statistics to the drivers faster?

Answer: B

Explanation:
To improve the performance of queries on semi-structured data, such as JSON stored in a VARIANT column, Snowflake's search optimization service can be utilized. By adding search optimization specifically for the longitude and latitude fields within the VARIANT column, the system can perform point lookups and substring queries more efficiently. This will allow for faster retrieval of weather statistics, which is critical for the drivers to receive timely updates.
References: The solution is supported by Snowflake documentation that details how search optimization can enhance query performance for semi-structured data1.


NEW QUESTION # 204
......

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