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WGU Applied-Algebra Exam Syllabus Topics:

Section	Objectives
Foundations of Algebra	- Algebraic Expressions 1. Simplifying expressions 2. Evaluating expressions 3. Order of operations - Equations and Inequalities 1. Linear equations in one variable 2. Inequalities and interval notation
Polynomial and Rational Expressions	- Polynomials 1. Factoring techniques 2. Operations with polynomials - Rational Expressions 1. Simplification 2. Restrictions on variables
Exponential and Logarithmic Concepts	- Exponential Functions 1. Exponential equations 2. Growth and decay models - Logarithmic Basics 1. Conversion between exponential and logarithmic form 2. Logarithm properties
Functions and Graphs	- Graphing Functions 1. Transformations of graphs 2. Coordinate plane interpretation - Function Concepts 1. Function notation 2. Domain and range
Linear Functions and Systems	- Systems of Equations 1. Substitution method 2. Elimination method - Linear Equations 1. Slope-intercept form 2. Point-slope form

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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q30-Q35):

NEW QUESTION # 30
Consider the graph of h(t) shown. The function represents the height, h, in feet, of a ball t seconds after being launched.

What is the point, if any, at which the concavity changes from concave down to concave up?

A. At t=1.41
B. The graph is always concave up.
C. The graph is always concave down.
D. At t=0.705

Answer: C

Explanation:
The graph represents the height of a launched ball over time. Such height functions are typically quadratic because gravity causes the ball to rise, slow down, reach a maximum height, and then fall. The graph shown is a downward-opening parabola. A downward-opening parabola is concave down for its entire domain.
Concavity changes only if the curve switches from bending downward to bending upward, or from bending upward to bending downward. Since this graph bends downward the entire time, there is no point where the concavity changes from concave down to concave up. The vertex is a maximum point, but it is not a change in concavity. Therefore, the correct statement is that the graph is always concave down.

NEW QUESTION # 31
The function p(t)represents the number of active players, p, in a game thours after 11:00 a.m. The graph of p(t) is shown.

What is one example of an interval for which the number of players is decreasing faster and faster?

A. t=11.2to t=11.5
B. t=1.2to t=5.3
C. t=8.6to t=9.0
D. t=8.7to t=10.7

Answer: A

Explanation:
The graph represents:
p(t)= " number of active players "
where:
t= " hours after 11:00 a.m. "
The phrase "decreasing faster and faster" means two things are happening:
The graph is going downward, so the number of players is decreasing.
The graph is becoming steeper downward, so the rate of decrease is increasing.
This corresponds to a graph that is decreasing and concave down.
Looking at the graph, the number of active players reaches a maximum around:
t#9
After that, the graph begins decreasing. Near the far right side of the graph, especially around:
t=11.2 " to " t=11.5
the curve is dropping more and more steeply.
That means the number of players is decreasing faster and faster on that interval.

NEW QUESTION # 32
The population of fish in a lake is changing according to the function
P(t)=24t+185
where tis the number of months since the beginning of the year and P(t)is the fish population at time t.
Which interpretation of the rate of change is correct?

A. The number of fish in the lake is increasing at a constant rate of 185 fish per month.
B. The number of fish in the lake is decreasing at a constant rate of 185 fish per month.
C. The number of fish in the lake is increasing at a constant rate of 24 fish per month.
D. The number of fish in the lake is decreasing at a constant rate of 24 fish per month.

Answer: C

Explanation:
The function is:
P(t)=24t+185
This is a linear function in the form:
P(t)=mt+b
where:
m= " rate of change "
and
b= " initial value "
In the function:
P(t)=24t+185
the coefficient of tis:
24
So the rate of change is:
24 " fish per month "
Because 24is positive, the fish population is increasing.
The number 185is not the rate of change. It represents the starting fish population at the beginning of the year, when t=0:
P(0)=24(0)+185=185
Therefore, the correct interpretation is:
" The number of fish in the lake is increasing at a constant rate of 24 fish per month. " So the correct answer is:
# ( " B " )

NEW QUESTION # 33
The graph shows the progress of a manufacturing team, modeling the number of widgets the team is able to produce each day since the team was formed.

How should the average rate of change from day 16 to day 18 be interpreted?

A. The team increased production by an average of approximately 1.7 widgets each day.
B. Over the 2-day period, the team approximately produced an additional 1.7 widgets in total.
C. Over the 2-day period, the team approximately produced an additional 0.8 widgets in total.
D. The team increased production by an average of approximately 0.8 widgets each day.

Answer: A

Explanation:
The graph models the number of widgets the manufacturing team can produce each day.
The horizontal axis represents:
" Days "
The vertical axis represents:
" Widgets produced each day "
The two labeled points are:
(16#9.1)
and
(18#12.4)
This means:
On day 16, the team could produce about 9.1widgets per day.
On day 18, the team could produce about 12.4widgets per day.
The average rate of change is:
(12.4-9.1)/(18-16)
=3.3/2
=1.65
Rounded to the nearest tenth:
1.7
So from day 16 to day 18, the team's production increased by an average of about:
1.7 " widgets each day "

NEW QUESTION # 34
The exponential function
f(t)=2900(1.13)
t
represents the size of a bacteria population, where t is the time in hours.
How many bacteria are in the population when t=18?

A. 23,160
B. 20,495
C. 29,573
D. 26,170

Answer: D

Explanation:
This is an exponential growth problem because the base 1.13 is greater than 1. The function starts with 2,900 bacteria and grows by a factor of 1.13 each hour, which represents a 13% hourly increase. To find the population after 18 hours, substitute t=18 into the function: f(18)=2900(1.13)
18
Evaluating the exponent and multiplying by 2900 gives approximately 26,170.38. Since bacteria are counted as whole organisms, this rounds to about 26,170 bacteria. The other answer choices do not match the exponential model at t=18. Therefore, the correct answer is C.

NEW QUESTION # 35
......

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