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Salesforce JS-Dev-101 考試大綱:
| 主題 | 簡介 |
|---|
| 主題 1 | - Browser and Events: Covers DOM manipulation, event handling and propagation, browser-specific APIs, and using Browser Developer Tools to inspect code behavior.
|
| 主題 2 | - Debugging and Error Handling: Covers proper error handling techniques and the use of the console and breakpoints to debug code.
|
| 主題 3 | - Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
- falsy evaluations.
|
>> JS-Dev-101資訊 <<
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最新的 Salesforce Developers JS-Dev-101 免費考試真題 (Q33-Q38):
問題 #33
Given the following code:
let x = null;
console.log(typeof x);
What is the output?
- A. "x"
- B. "undefined"
- C. "null"
- D. "object"
答案:D
問題 #34
Refer to the following code:
<html lang="en">
<body>
<button class="secondary">Save draft</button>
<button class="primary">Save and close</button>
</body>
<script>
function displaySaveMessage(event) {
console.log('Save message.');
}
function displaySuccessMessage(event) {
console.log('Success message.');
}
window.onload = function() {
document.querySelector('.secondary')
.addEventListener('click', displaySaveMessage, true);
document.querySelector('.primary')
.addEventListener('click', displaySuccessMessage, true);
}
</script>
</html>
- A. > Outer message
- B. > Outer message
Inner message - C. > Inner message
- D. > Inner message
Outer message
答案:B
解題說明:
The answer choices appear to belong to an event propagation question using nested elements such as an outer element and an inner element.
The important clue is this third argument:
addEventListener('click', handlerFunction, true);
When the third argument is true, the event listener runs during the capturing phase.
In event capturing, the browser handles the event from the outside toward the inside:
Outer element → Inner element
So, if an inner element is clicked and both the outer and inner elements have click listeners registered with capture mode set to true, the outer listener runs first, then the inner listener runs.
That produces:
Outer message
Inner message
So the matching option is B.
Important correction:
In the exact code shown, the buttons are sibling elements:
<button class="secondary">Save draft</button>
<button class="primary">Save and close</button>
They are not nested inside one another. Therefore, with the code exactly as written:
Clicking the secondary button logs:
Save message.
Clicking the primary button logs:
Success message.
However, because the provided answer choices refer to Outer message and Inner message, the intended concept is clearly event capturing. In a capturing-phase question with nested outer and inner elements, the correct order is:
Outer message
Inner message
Therefore, the verified answer for the intended event-capturing question is B.
問題 #35
Refer to the code below:
Const myFunction = arr => {
Return arr.reduce((result, current) =>{
Return result = current;
}, 10};
}
What is the output of this function when called with an empty array ?
- A. Returns NaN
- B. Returns 0
- C. Returns 10
- D. Throws an error
答案:C
問題 #36
Refer to the code below:
01 let first = 'Who';
02 let second = 'What';
03 try {
04 try {
05 throw new Error('Sad trombone');
06 } catch (err) {
07 first = 'Why';
08 throw err;
09 } finally {
10 second = 'When';
11 }
12 } catch (err) {
13 second = 'Where';
14 }
What are the values for first and second once the code executes?
- A. first is Who and second is When.
- B. first is Who and second is Where.
- C. first is Why and second is Where.
- D. first is Why and second is When.
答案:C
解題說明:
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge:
Initial values:
first = 'Who'
second = 'What'
Execution:
Inner try/catch/finally:
Line 05: throw new Error('Sad trombone');
Control goes to the inner catch.
Inner catch (lines 06-08):
catch (err) {
first = 'Why';
throw err;
}
first is set to 'Why'.
The error is rethrown.
Inner finally (lines 09-11):
finally {
second = 'When';
}
finally runs whether or not there was an error.
second becomes 'When'.
After inner finally, the rethrown error continues to propagate to the outer catch.
Outer catch (lines 12-14):
} catch (err) {
second = 'Where';
}
Because the inner try rethrew, the outer catch runs.
It sets second = 'Where'.
Final values:
first was changed to 'Why' in the inner catch and never changed again.
second became 'When' in the inner finally, and then 'Where' in the outer catch.
So:
first is 'Why'
second is 'Where'
Option B is correct.
Concepts: nested try/catch/finally, rethrowing errors, order of execution for catch vs finally, variable mutation through error propagation.
________________________________________
問題 #37
Refer to the following object:
const cat ={
firstName: 'Fancy',
lastName: ' Whiskers',
Get fullName() {
return this.firstName + ' ' + this.lastName;
}
};
How can a developer access the fullName property for cat?
- A. cat.get.fullName
- B. cat.function.fullName()
- C. cat.fullName
- D. cat.fullName()
答案:C
問題 #38
......
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