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>> JS-Dev-101 Customized Lab Simulation <<
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NEW QUESTION # 139
Which option is true about the strict mode in imported modules?
Answer: C
Explanation:
In JavaScript, ES modules (files imported using import / export) have special semantics:
All code inside a module is automatically executed in strict mode.
This is specified by the ECMAScript standard and does not require the explicit "use strict"; directive.
Effects:
You do not need to write "use strict"; at the top of a module file.
You cannot turn strict mode off for module code.
All module top-level code is treated as strict.
Now evaluate each option:
Option A:
Add the statement use non-strict; before any other statements in the module to enable notstrict mode.
There is no use non-strict; directive in JavaScript.
The only directive recognized by engines is "use strict";.
You cannot explicitly enable a "non-strict" mode with such a string.
Option B:
Imported modules are in strict mode whether you declare them as such or not.
This matches the language specification.
ES modules are always in strict mode, automatically.
This is true.
Option C:
Add the statement use strict = false; before any other statements in the module to enable notstrict mode.
use strict = false; is not a directive; it is parsed as a normal expression, and does not affect strict mode.
There is no supported way to disable strict mode in modules.
Option D:
A developer can only reference notStrict() functions from the imported module.
There is no special notStrict() restriction in modules.
Functions exported/imported in modules are simply subject to strict mode rules like the rest of the module's code.
Therefore, the only correct statement is:
Answe r: B
Study Guide / Concept Reference (no links):
ES modules (import / export)
Automatic strict mode in modules
"use strict"; directive for scripts vs modules
Inability to disable strict mode in ES module code
NEW QUESTION # 140
Given the code below:
01 function GameConsole (name) {
02 this.name = name;
03 }
04
05 GameConsole.prototype.load = function(gamename) {
06 console.log( ` $(this.name) is loading agame : $(gamename) ...`);
07 )
08 function Console 16 Bit (name) {
09 GameConsole.call(this, name) ;
10 }
11 Console16bit.prototype = Object.create ( GameConsole.prototype) ;
12 //insert code here
13 console.log( ` $(this.name) is loading a cartridge game :$(gamename) ...`);
14 }
15 const console16bit = new Console16bit(' SNEGeneziz ');
16 console16bit.load(' Super Nonic 3x Force ');
What should a developer insert at line 15 to output the following message using the method ?
> SNEGeneziz is loading a cartridgegame: Super Monic 3x Force . . .
Answer: A
NEW QUESTION # 141
Refer to the code below:
01 let sayHello = () => {
02 console.log('Hello, World!');
03 };
Which code executes sayHello once, two minutes from now?
Answer: A
Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge To schedule a function for later execution in JavaScript, the standard built-in method is:
setTimeout(functionReference, delayInMilliseconds)
Characteristics of setTimeout():
Executes only once.
Delay is specified in milliseconds.
Requires passing the function reference, not calling the function.
Two minutes is:
2 minutes = 120 seconds = 120,000 milliseconds
Now evaluate each option:
________________________________________
Option A: delay(sayHello, 120000);
Incorrect.
There is no built-in delay() function in JavaScript.
________________________________________
Option B: setTimeout(sayHello, 120000);
Correct.
sayHello is passed as a function reference, so it will execute once after 120,000 ms.
________________________________________
Option C: setTimeout(sayHello(), 120000);
Incorrect.
sayHello() calls the function immediately, and the return value (undefined) is passed to setTimeout.
This executes the function right away instead of after two minutes.
________________________________________
Option D: setInterval(sayHello, 120000);
Incorrect.
setInterval() repeats execution every 120,000 ms.
The question requires executing the function once, so this cannot be correct.
________________________________________
JavaScript Knowledge Reference (text-only)
setTimeout() schedules a function to run once after a specified delay.
Passing functionName gives a reference; passing functionName() invokes it immediately.
setInterval() repeats indefinitely, unlike setTimeout().
NEW QUESTION # 142
Refer to the code below:
Which replacement for the conditionalstatement on line 02 allows a developer to correctly determine that a specific element, myElement on the page had been clicked?
Answer:
Explanation:
event.target.id =='myElement'
NEW QUESTION # 143
Which two code snippets show working examples of a recursive function?
Answer: A,D
Explanation:
return startNumber;
}
};
(Note: Option D is shown here with corrected syntax: lowercase return and matching parentheses.) Explanation:
A recursive function is a function that calls itself and has a base case to terminate the recursion.
Evaluate each option:
Option A:
const sumToTen = numVar => {
if (numVar < 0)
return;
return sumToTen(numVar + 1);
};
This function calls itself: sumToTen(numVar + 1) - so it is recursive.
However, the base condition is if (numVar < 0) return;.
If you call sumToTen(0):
numVar < 0 is false, so it calls sumToTen(1), then sumToTen(2), and so on, incrementing forever.
There is no condition to stop the recursion when numVar increases; it will eventually cause a stack overflow.
This code does not represent a properly working recursive function with a valid termination for increasing values and is not a good example of correct recursion.
Option B:
function factorial(numVar) {
if (numVar < 0) return;
if (numVar === 0) return 1;
return numVar - 1;
}
This function does not call itself anywhere.
It has conditional returns, but there is no recursive call such as factorial(numVar - 1).
Therefore, it is not recursive at all.
Option C:
const factorial = numVar => {
if (numVar < 0) return;
if (numVar === 0) return 1;
return numVar * factorial(numVar - 1);
};
This is a classic recursive factorial implementation.
It calls itself with a smaller argument: factorial(numVar - 1).
Base cases:
If numVar < 0, it simply returns (could be treated as invalid input).
If numVar === 0, it returns 1, which is the mathematical definition of 0! (zero factorial).
For positive integers, it correctly multiplies numVar by factorial(numVar - 1) until it reaches the base case.
This is a correct and working recursive function.
Option D (corrected):
let countingDown = function(startNumber) {
if (startNumber > 0) {
console.log(startNumber);
return countingDown(startNumber - 1);
} else {
return startNumber;
}
};
This function also calls itself: countingDown(startNumber - 1).
Base case:
When startNumber is not greater than 0 (i.e., 0 or negative), it returns startNumber and stops recursing.
For example, countingDown(3) would:
Log 3, call countingDown(2)
Log 2, call countingDown(1)
Log 1, call countingDown(0)
At 0, it hits the else branch and returns 0, ending the recursion.
This is a valid working recursive function structure (once syntax is corrected).
Therefore, the snippets that show working recursive functions are:
Answe r: C, D
Study Guide / Concept Reference (no links):
Definition of recursion: a function calling itself
Base case vs recursive step
Recursive factorial implementation
Recursive countdown example
Importance of a terminating condition to avoid infinite recursion
NEW QUESTION # 144
......
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