Introduction-to-Cryptography真實考試題庫

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WGU Introduction-to-Cryptography Exam Syllabus Topics:

SectionObjectives
Applied Cryptography- PGP and Email Encryption
- Cryptographic Best Practices
- SSL/TLS Protocols
- VPN Security
Cryptanalysis and Attacks- Common Attack Vectors
- Social Engineering Prevention
- Brute Force and Dictionary Attacks
Hashing and Digital Signatures- Message Authentication Codes (MAC)
- Digital Signature Standards
- Hash Functions (MD5, SHA-1, SHA-256)
Cryptography Fundamentals- History and Evolution of Cryptography
- Symmetric vs Asymmetric Encryption
- Cryptographic Terminology
Symmetric Cryptography- Initialization Vectors (IV)
- Block Ciphers (AES, DES, 3DES)
- Key Management
- Stream Ciphers
Asymmetric Cryptography- Elliptic Curve Cryptography (ECC)
- RSA Algorithm
- Diffie-Hellman Key Exchange
- Public Key Infrastructure (PKI)

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真實的Introduction-to-Cryptography最新試題&保證WGU Introduction-to-Cryptography考試成功與頂級的Introduction-to-Cryptography下載

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最新的 Courses and Certificates Introduction-to-Cryptography 免費考試真題 (Q51-Q56):

問題 #51
(Which encryption algorithm uses an 80-bit key and operates on 64-bit data blocks?)

答案:B

解題說明:
Skipjack is a symmetric block cipher historically associated with the Clipper chip initiative. Its defining parameters match the question: it operates on 64-bit blocks and uses an 80-bit key. The other options do not fit those exact sizes. Twofish is a 128-bit block cipher with key sizes up to 256 bits. Blowfish is a
64-bit block cipher, but its key size is variable from 32 up to 448 bits and is not fixed at 80 bits as a defining property. Camellia is a 128-bit block cipher with key sizes of 128, 192, or 256 bits. Skipjack's smaller key size and legacy design make it unsuitable for modern security needs, but the question is purely about identifying the algorithm that matches an 80-bit key and 64-bit blocks. Therefore, the correct answer is Skipjack.


問題 #52
(What are the roles of keys when using digital signatures?)

答案:D

解題說明:
Digital signatures provide integrity, authenticity, and typically non-repudiation by using an asymmetric key pair. The signer uses the private key to create a signature over a message (usually over a hash/digest of the message). Because the private key is kept secret, only the legitimate signer should be able to produce a valid signature. Anyone who has the corresponding public key can then validate the signature: they verify that the signature matches the message digest under the public key and that the signed data has not been altered. This is why the public key can be widely distributed (often inside an X.509 certificate) while the private key must be protected by the signer. If a public key were used to sign, anyone could forge signatures; if a private key were required for validation, only the signer could validate, defeating the purpose of public verifiability.
Therefore, the correct key roles are private key for signing and public key for signature validation.


問題 #53
(Which symmetric encryption technique uses a 256-bit key size and a 128-bit block size?)

答案:C

解題說明:
AES (Advanced Encryption Standard) is a symmetric block cipher standardized to operate on a fixed 128-bit block size and supports key sizes of 128, 192, and 256 bits. When the key size is 256 bits, the cipher is commonly referred to as AES-256, but the block size remains 128 bits regardless of key length. This combination (256-bit key, 128-bit block) matches the question precisely. By comparison, DES uses a 64-bit block size with a 56-bit effective key. 3DES also uses a 64-bit block size and effectively applies DES three times, yielding an effective key length typically cited as 112 bits (two-key 3DES) or 168 bits (three-key
3DES), depending on how keys are configured. IDEA uses a 64-bit block size with a 128-bit key. Therefore, the only listed algorithm that supports a 256-bit key while maintaining a 128-bit block size is AES. This is one reason AES is widely adopted for modern symmetric encryption: strong key sizes with efficient implementation and broad standardization.


問題 #54
(What is the value of 51 mod 11?)

答案:A

解題說明:
The value 51 mod 11 is the remainder after dividing 51 by 11. Modular arithmetic is widely used in cryptography to keep computations within a finite set of residues, such as in RSA where values are taken modulo n, or in Diffie-Hellman where exponents and group elements are reduced modulo a prime. To compute 51 mod 11, find the largest multiple of 11 less than or equal to 51. Multiples of 11 are 11, 22, 33, 44, 55. The closest without exceeding 51 is 44. Subtracting gives 51 # 44 = 7, so the remainder is 7. Therefore, 51 mod 11 = 7, matching option "07." This remainder is always in the range
0 through 10 because the modulus is 11. Such residue computations underpin the "wraparound" behavior that makes modular exponentiation and inverse computations well-defined in cryptographic groups.


問題 #55
(What is a characteristic of a hash function?)

答案:A

解題說明:
A cryptographic hash function maps input data of arbitrary length to a fixed-length digest and is designed to be one-way: given a digest, it should be computationally infeasible to recover the original input (preimage resistance). This one-way property enables many security applications: file integrity checking (any change alters the digest), password storage (combined with salt and slow hashing), digital signatures (signing a digest rather than large data), and commitment schemes. Hash functions are not encryption because they do not support decryption; they intentionally discard information about the input. They also do not use public/private key pairs; those are features of asymmetric cryptography. "Reversible" is the opposite of the intended design goal. A well-designed hash also aims for collision resistance (hard to find two different inputs with the same digest) and second-preimage resistance. Among the answer choices, the defining characteristic that best captures what makes a hash function distinct is that it is one-way.


問題 #56
......

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