Updated Oracle 1z0-071 Exam Questions for 1z0-071 Exam Success

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Oracle 1z0-071 Exam Syllabus Topics:

Section	Objectives
SQL Retrieval	- SELECT statements and filtering data 1. WHERE clause and conditions 2. ORDER BY and row limiting - Joins and set operations 1. UNION, INTERSECT, MINUS 2. INNER, OUTER, CROSS joins
SQL Functions	- Single-row functions 1. Character, numeric, date functions - Conversion and conditional functions 1. TO_CHAR, TO_NUMBER, CASE expressions
Subqueries and Advanced SQL	- Single-row and multi-row subqueries - Correlated subqueries and nested queries
Relational Database Concepts	- Data types and database objects overview - Tables, rows, columns, and relational model basics
Data Manipulation and Schema Objects	- DML operations 1. INSERT, UPDATE, DELETE, MERGE - DDL operations 1. CREATE, ALTER, DROP tables and constraints

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Oracle Database SQL Sample Questions (Q322-Q327):

NEW QUESTION # 322
An Oracle database server session has an uncommitted transaction in progress which updated 5000 rows in a table.
In which three situations does the transaction complete thereby committing the updates?

A. when a create index statement is executed successfully in the same session
B. when a CREATE TABLE AS SELECT statement is executed unsuccessfully in the same session
C. when a DBA issues a successful shutdown transactional statement and the user then issues a commit
D. when a commit statement is issued by the same user from another session in the same database instance
E. when the session logs out successfully
F. when a DBA issues a successful shutdown immediate statement and the user then issues a commit

Answer: A,C,E

NEW QUESTION # 323
Examine the description of the EMPLOYEES table:

Which two queries return rows for employees whose manager works in a different department?

A. SELECT emp. *
FROM employees emp
WHERE manager_ id NOT IN (
SELECT mgr.employee_ id
FROM employees mgr
WHERE emp. department_ id < > mgr.department_ id
);
B. SELECT emp.*
FROM employees emp
WHERE NOT EXISTS (
SELECT NULL
FROM employees mgr
WHERE emp.manager id = mgr.employee_ id
AND emp.department_id<>mgr.department_id
);
C. SELECT emp. *
FROM employees emp
RIGHT JOIN employees mgr
ON emp.manager_ id = mgr. employee id
AND emp. department id <> mgr.department_ id
WHERE emp. employee_ id IS NOT NULL;
D. SELECT emp.*
FROM employees emp
LEFT JOIN employees mgr
ON emp.manager_ id = mgr.employee_ id
AND emp. department id < > mgr. department_ id;
E. SELECT emp. *
FROM employees emp
JOIN employees mgr
ON emp. manager_ id = mgr. employee_ id
AND emp. department_ id<> mgr.department_ id;

Answer: B,E

Explanation:
To find employees whose manager works in a different department, you can use a subquery or a join that compares the DEPARTMENT_ID of the employee with the DEPARTMENT_ID of their manager.
A . This query is incorrect because the NOT IN subquery incorrectly attempts to compare EMPLOYEE_ID with MANAGER_ID, and the correlation condition inside the subquery is incorrect.
B . This query is correct. The NOT EXISTS clause correctly identifies employees whose MANAGER_ID matches the EMPLOYEE_ID of another employee (mgr) and where the DEPARTMENT_ID differs from that manager's DEPARTMENT_ID.
C . This query is incorrect because the LEFT JOIN will return all employees, and there is no WHERE clause to filter out those employees whose managers are in the same department.
D . This query is incorrect. The RIGHT JOIN does not ensure that the resulting rows are for employees whose manager works in a different department. It also returns all managers, which is not the requirement.
E . This query is correct. The JOIN ensures that the returned rows are for employees (emp) whose MANAGER_ID matches the EMPLOYEE_ID of managers (mgr), and it correctly filters to include only those employees whose DEPARTMENT_ID is different from their manager's DEPARTMENT_ID.
Reference:
Oracle Documentation on Joins: https://docs.oracle.com/database/121/SQLRF/queries006.htm#SQLRF52358

NEW QUESTION # 324
Examine the data in the CUST_NAMEcolumn of the CUSTOMERStable:

You want to display the CUST_NAMEvalues where the last name starts with Mcor MC.
Which two WHERE clauses give the required result? (Choose two.)

A. WHERE INITCAP (SUBSTR (cust_name, INSTR(cust_name, `')+1)) IN (`MC%', `Mc%)
B. WHERE SUBSTR (cust_name, INSTR (cust_name, `') +1) LIKE `Mc%'
C. WHERE SUBSTR (cust_name, INSTR (cust_name, `') +1) LIKE `Mc%' OR `MC%'
D. WHERE UPPER (SUBSTR (cust_name, INSTR(cust_name, `')+1)) LIKE UPPER (`MC%')
E. WHERE INITCAP (SUBSTR (cust_name, INSTR(cust_name, `')+1)) LIKE `Mc%'

Answer: B,C

NEW QUESTION # 325
Which two statements are true about sequences created in a single instance database? (Choose two.)

A. DELETE <sequencename> would remove a sequence from the database.
B. When a database instance shuts down abnormally, the sequence numbers that have been cached but not used would be available once again when the database instance is restarted.
C. The numbers generated by a sequence can be used only for one table.
D. When the MAXVALUE limit for the sequence is reached, you can increase the MAXVALUE limit by using the ALTER SEQUENCE statement.
E. CURRVAL is used to refer to the last sequence number that has been generated.

Answer: D,E

Explanation:
Explanation
References:
http://docs.oracle.com/cd/E11882_01/server.112/e41084/statements_2012.htm#SQLRF00817
https://docs.oracle.com/cd/A84870_01/doc/server.816/a76989/ch26.htm

NEW QUESTION # 326
Evaluate this ALTER TABLE statement: (Choose the best answer.)
ALTER TABLE orders
SET UNUSED (order_date);
Which statement is true?

A. After executing the ALTER TABLE command, a new column called ORDER_DATE can be added to the ORDERS table.
B. The DESCRIBE command would still display the ORDER_DATE column.
C. The ORDER_DATE column must be empty for the ALTER TABLE command to execute successfully.
D. ROLLBACK can be used to restore the ORDER_DATE column.

Answer: A

NEW QUESTION # 327
......

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