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| Section | Weight | Objectives |
|---|---|---|
| Exponents, Radicals, and Quadratic Relationships | 15% | - Basic quadratic graphs - Simplifying radical expressions - Solving quadratic equations - Properties of exponents |
| Algebraic Expressions and Operations | 20% | - Simplifying and evaluating expressions - Order of operations - Variables, constants, and coefficients - Operations with polynomials |
| Linear Equations and Inequalities | 25% | - Solving and graphing inequalities - Real-world applications - Solving single-variable equations |
| Systems of Equations and Inequalities | 15% | - Graphical solutions - Applications of systems - Solving by substitution and elimination |
| Graphing and Functions | 25% | - Slope and equations of lines - Coordinate plane and plotting points - Linear functions and their graphs - Function notation and evaluation |
>> Applied-Algebra Free Sample Questions <<
Our Applied-Algebra guide torrent has gone through strict analysis and summary according to the past exam papers and the popular trend in the industry and are revised and updated. The Applied-Algebra exam questions have simplified the sophisticated notions. The software boosts varied self-learning and self-assessment functions to check the learning results. The software of our Applied-Algebra Test Torrent provides the statistics report function and help the students find the weak links and deal with them. With this version of our Applied-Algebra exam questions, you will be able to pass the exam easily.
NEW QUESTION # 85
The number of people auditioning for a game show is expected to be 4 times the number of people who auditioned last year. The function A(t) can be used to model the situation, where t represents the number of people who auditioned last year and A represents the number of people expected to audition this year.
Which quantity represents the number of people expected to audition this year, given that 330 people auditioned last year?
Answer: A
Explanation:
We are told that the number of people expected to audition this year is 4 times the number of people who auditioned last year.
Let:
t=number of people who auditioned last year
and
A(t)=number of people expected to audition this year
Since this year's number is 4 times last year's number, the function is:
A(t)=4t
The question says that 330 people auditioned last year, so:
t=330
Now substitute 330 into the function:
A(330)=4(330)
A(330)=1320
So, the correct function notation is:
A(330)=1,320
This means: when 330 people auditioned last year, 1,320 people are expected to audition this year.
Therefore, the correct answer is:
B
NEW QUESTION # 86
The function V(t)represents the number of travelers, V, in a travel depot thours after 7:00 a.m. The graph of V (t)is shown.
What does V(2)represent?
Answer: D
Explanation:
The function V(t)represents the number of travelers in the travel depot.
The input trepresents:
" hours after 7:00 a.m. "
The output V(t)represents:
" number of travelers "
So V(2)means the number of travelers in the depot:
2 " hours after 7:00 a.m. "
From the graph, when:
t=2
the value of V(t)is approximately:
79.2
Since V(t)measures travelers, not hours, V(2)represents:
79.2 " travelers "
Therefore, the correct answer is:
# ( " D " )
NEW QUESTION # 87
The number of people, P, in a festival audience is represented by the graph, with the number of hours since the beginning of the festival along the horizontal axis and the size of the audience along the vertical axis.
Point Arepresents an audience size of 402 for the first hour of the festival, or P(0)=402.
Which ordered pair represents a point on the graph?
Answer: D
Explanation:
This question is about reading an ordered pair from a graph.
An ordered pair has the form:
(x#y)
where:
x= " time in hours "
and
y= " audience size "
From the graph:
Point Ais at approximately (0#402)
Point Bis at (2#401)
Point Cis at (4#403)
Point Dis at (6#406)
Point Eis at approximately (8#410)
Point Fis at (10#408)
Now compare these graph points with the answer choices.
Choice A says:
(2#401)
This matches point Bon the graph exactly.
The other choices do not match the graph:
(4#404)
is incorrect because at x=4, the graph shows about 403, not 404.
(8#409)
is incorrect because at x=8, the graph is about 410, not 409.
(10#407)
is incorrect because at x=10, the graph shows about 408, not 407.
NEW QUESTION # 88
The graphed function v(t) represents the number of vehicles, v, stopped at a toll booth t hours after 6:00 a.m.
The coordinates of points A and B are (1,49.4) and (4,45.8), respectively.
What is the average rate of change of the number of vehicles from point A to point B?
Answer: C
Explanation:
The average rate of change measures how much the output changes per one unit of input. Here, the input is time in hours after 6:00 a.m., and the output is the number of vehicles stopped at the toll booth. The two given points are A=(1,49.4) and B=(4,45.8). Use the average rate of change formula: (y
2
#y
1
)/(x
2
#x
1
). Substituting the coordinates gives (45.8#49.4)/(4#1). The numerator is #3.6, and the denominator is 3, so the average rate of change is #1.2. The negative sign means the number of vehicles decreased over the interval.
NEW QUESTION # 89
The value of an investment portfolio after x years is modeled by the function g(x)=3100(1.059) x
.
What is the value of the portfolio when x=10?
Answer: C
Explanation:
This problem uses an exponential growth model. The initial portfolio value is 3100, and the growth factor is
1.059. Since the growth factor is greater than 1, the portfolio increases over time. To find the value after 10 years, substitute x=10 into the function: g(10)=3100(1.059)
10
First evaluate the exponent, then multiply by 3100. This gives g(10)#5499.4758. Rounded to the nearest cent, the value is $5,499.48. The answer must be written as money because the function models the value of an investment portfolio. Among the choices, only option B matches the correctly evaluated exponential expression. Therefore, the correct answer is B.
NEW QUESTION # 90
......
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