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| Section | Objectives |
|---|---|
| Topic 1: Xcode Developer Tools | - Identify and use the features of the Xcode interface
|
| Topic 2: View Building with SwiftUI | - Create a multi-view app with navigation Stacks, Links, and/or Sheets - Position and/or layout a single SwiftUI View with standard Views and modifiers - Use @State, @Binding, @Environment, and/or Observable to share data between Views - Extract Subviews to simplify the structure of an overlarge View - Create multiple Views to implement app logic - Use List Views to iterate through collections |
| Topic 3: Swift Programming Language | - Declare and use basic Swift types
- Know how and when to apply control flow and loops
|
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NEW QUESTION # 13
For each statement about Navigation in SwiftUI. select True or False.
Answer:
Explanation:
Explanation:
* You can treat a NavigationLink like a button, and run some Swift code when it is pressed. - False
* NavigationSplitView can be used to do navigation differently on different device sizes. - True
* You can put a header on your present View in a NavigationStack using .navigationTitle. - True
* If you have a NavigationLink that goes to another View with a NavigationLink, you need to declare a NavigationStack at each level. - False This question belongs to View Building with SwiftUI , specifically the objective on creating a multi-view app with navigation stacks, links, and sheets . Statement 1 is False because NavigationLink is primarily a navigation control that pushes or presents a destination in a navigation container; Apple documents it as creating a navigation link that presents a destination, not as a general-purpose action control like Button.
Statement 2 is True because NavigationSplitView is designed for adaptive navigation and can present navigation in different ways depending on platform and available space. Apple documents NavigationSplitView as a container for navigation across multiple columns, and this adaptive behavior is exactly why it is used differently across device sizes.
Statement 3 is True because .navigationTitle(...) sets the navigation title for a view shown inside a navigation container. Apple explicitly describes a view's navigation title as something used to visually display the current navigation state of an interface.
Statement 4 is False because you do not need a separate NavigationStack at every level. Apple describes NavigationStack as the container that manages a stack of views, and NavigationLink pushes additional destinations onto that stack. Nested destinations can keep navigating within the same stack.
NEW QUESTION # 14
Review the code.
Note: You might need to scroll to see the entire block of code.
A breakpoint is set on line 3. When the application is run. it will stop at line 3. You need to debug the code.
Drag each debugging control from the left to the correct instruction on the right. You will receive partial credit for each correct answer
Answer:
Explanation:
Explanation:
This question belongs to Xcode Developer Tools , especially the objective on using debugging techniques including breakpoints and stepping controls .
When execution stops at a breakpoint on line 3, Step Over runs that line without entering into another function call, so it is the correct action for moving past line 3 while staying in the current function. Step Into is used when execution reaches line 4 and you want to enter the display(numbers) function, which takes you into the function body starting at line 8. Once inside that function, Step Out continues execution until the current function returns, which is exactly what "step out from line 8" means.
Deactivate breakpoints turns breakpoint handling off so the debugger no longer stops on active breakpoints.
Continue program execution resumes the app until the next breakpoint or until the program finishes.
So the correct control order is:
1 = Continue
2 = Deactivate breakpoints
3 = Step Over
4 = Step Into
5 = Step Out
NEW QUESTION # 15
You have created a view which includes some formatted text:
You decide to extract this formatted text into a subview so that you can reuse the formatting for other texts.
You highlight the Text and choose Extract subview.
You refactor ExtractedView to BigGreenTextView.
You add the line let text: String to the extracted view above the body.
You replace " That ' s all folks " with a reference to text
How should you call this extracted View from the original View?
Answer: D
Explanation:
This question belongs to View Building with SwiftUI , specifically the domain on extracting subviews to simplify the structure of an overlarge View .
When you create a custom SwiftUI view and add a stored property like:
let text: String
that property becomes part of the view's initializer. Since the property name is text, Swift expects you to pass the value using the parameter label text: when creating the view. So the correct call is:
BigGreenTextView(text: " That ' s all folks " )
That makes B the correct answer.
Why the others are wrong:
* A is incorrect because this is not using the expected parameter label.
* C would only be correct if there were already another variable named text in the calling scope and you wanted to pass that variable instead of the literal string shown in the question.
* D is incorrect because it omits the parameter label.
This is a standard SwiftUI pattern: extract reusable formatting into a separate custom View, give it an input property, and then pass the needed value through the initializer using the property label.
NEW QUESTION # 16
Given the function definition, which two statements call the function correctly? (Choose 2.)
Based on the image provided, here is the text for each of the multiple-choice options:
Answer: C,D
Explanation:
This question belongs to Swift Programming Language , specifically the objective on functions , including internal and external parameter names and default parameter values .
The function is defined as:
func schedule(who name: String, from starting: String, to ending: String, _ place: String = " Zoom " ) { print( " Appointment: meeting \(name) from \(starting) to \(ending) at \(place) " )
}
This means:
* the external parameter names are who, from, and to
* the internal parameter names are name, starting, and ending
* the last parameter uses _, which means it has no external label
* the last parameter also has a default value of " Zoom "
Now evaluate the options:
* A is incorrect because it uses place: as an external label, but _ place means no external label is allowed.
* B is correct because it uses the required external names who, from, and to, and it omits the last parameter, which is allowed because it has a default value.
* C is incorrect because it uses who:, from:, and to: correctly, but this function's first three parameters are not declared that way in the provided option set; the valid matching call style from the choices is not this one because the function's labels are paired with internal names in the declaration syntax shown in the question.
* D is incorrect because it uses the internal names name, starting, and ending as if they were external labels.
* E is correct because it uses the external labels who, from, and to, and omits the final unlabeled parameter, letting Swift use the default " Zoom " .
So the two correct answers are B and E .
NEW QUESTION # 17
Why does the initializer for the following struct need the keyword self?
Answer: B
Explanation:
This question belongs to Swift Programming Language , specifically the objective covering structs, properties, and initializers .
In the struct, both the property and the initializer parameter are named age:
struct person {
var age: Int
init(age: Int) {
self.age = age
}
}
Here, age inside the initializer could refer to either the property of the struct or the parameter passed into the initializer. Swift uses self.age to clearly mean the property that belongs to the current instance , while plain age refers to the initializer parameter . So self.age = age means: assign the parameter value to the instance property.
That is why C is correct. The keyword self is required here to remove ambiguity between two identifiers with the same name.
The other options are incorrect:
* A is wrong because self here is not pointing to the parameter; it points to the instance property.
* B is wrong because self is not always required in every initializer assignment. It is specifically needed here because of the naming conflict.
* D is wrong because whether the property has a default value is not the reason self is needed in this example.
So the correct answer is C. self is needed to distinguish between the property and the parameter with the same name.
NEW QUESTION # 18
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