Applied-Algebra Formal Test | Dump Applied-Algebra Torrent

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WGU Applied-Algebra Exam Syllabus Topics:

Section	Objectives
Topic 1: Polynomial and Rational Expressions	- Rational Expressions 1. Restrictions on variables 2. Simplification - Polynomials 1. Operations with polynomials 2. Factoring techniques
Topic 2: Functions and Graphs	- Function Concepts 1. Domain and range 2. Function notation - Graphing Functions 1. Coordinate plane interpretation 2. Transformations of graphs
Topic 3: Linear Functions and Systems	- Linear Equations 1. Slope-intercept form 2. Point-slope form - Systems of Equations 1. Elimination method 2. Substitution method
Topic 4: Foundations of Algebra	- Equations and Inequalities 1. Linear equations in one variable 2. Inequalities and interval notation - Algebraic Expressions 1. Evaluating expressions 2. Simplifying expressions 3. Order of operations
Topic 5: Exponential and Logarithmic Concepts	- Logarithmic Basics 1. Conversion between exponential and logarithmic form 2. Logarithm properties - Exponential Functions 1. Growth and decay models 2. Exponential equations

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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q120-Q125):

NEW QUESTION # 120
The graph shows the value, O, in dollars, of an investment account over time.

What represents the value of the account after 8 years?

A. $1,028.81
B. $700.19
C. $2,221.12
D. $476.54

Answer: C

Explanation:
The graph shows the total value of an investment account as time increases.
The horizontal axis represents:
" Time in years "
The vertical axis represents:
" Total value in dollars "
We need to find the value of the account after:
8 " years "
From the graph, when t=8, the curve is slightly above $2,200. The closest answer choice is:
$2,221.12
So the value of the account after 8 years is approximately:
$2,221.12
Therefore, the correct answer is:
# ( " D " )

NEW QUESTION # 121
The number of daily raffle tickets sold, R(d), for a fundraiser is represented by the graph, with the number of days since the beginning of the month along the horizontal axis and the number of raffle tickets sold for the day along the vertical axis.

How can the concavity be described from d=0to d=4.4?

A. The number of raffle tickets decreases slower and slower and then decreases faster and faster.
B. The number of raffle tickets decreases faster and faster and then decreases slower and slower.
C. The number of raffle tickets decreases slower and slower and then increases faster and faster.
D. The number of raffle tickets increases slower and slower and then decreases faster and faster.

Answer: C

Explanation:
From d=0to about d=2, the graph is decreasing, but it is flattening as it approaches a minimum. This means the number of raffle tickets sold is decreasing at a slower rate:
" decreases slower and slower "
After the minimum, from about d=2to d=4.4, the graph increases and becomes steeper. This means the number of raffle tickets sold is increasing at a faster rate:
" increases faster and faster "
So the correct description is:
" The number of raffle tickets decreases slower and slower and then increases faster and faster. "

NEW QUESTION # 122
The population of bison in a preserve can be modeled using the logistic function f(x), where x represents the number of years since the preserve was established and f(x) represents the population. The graph of f(x) is shown.

How does the bison population change as time progresses from year 7 to year 10?

A. The bison population decreases slower and slower.
B. The bison population decreases faster and faster.
C. The bison population increases slower and slower.
D. The bison population increases faster and faster.

Answer: C

Explanation:
A logistic function often increases quickly in the middle and then begins to level off as it approaches a maximum carrying capacity. From year 7 to year 10, the graph is still increasing, so the bison population is going up. However, the curve is becoming flatter during this interval. A flatter curve means the slope is getting smaller, so the population is increasing at a slower rate. This behavior is described as "increases slower and slower." It is not decreasing, because the graph continues to move upward. It is also not increasing faster and faster, because the slope is not becoming steeper in this interval. Therefore, the correct interpretation is answer B.

NEW QUESTION # 123
The function d(x)=14+65xrepresents the distance, in meters, from a tower to an object at time x, in seconds.
What is the value of d(1.5)?

A. 0
B. 0.19
C. 111.5
D. 1

Answer: C

Explanation:
We are given the function:
d(x)=14+65x
This is a linear function because it has the form:
d(x)=mx+b
where 65is the rate of change and 14is the starting value.
We need to find:
d(1.5)
That means substitute x=1.5into the function:
d(1.5)=14+65(1.5)
Now multiply:
65(1.5)=97.5
Then add:
d(1.5)=14+97.5
d(1.5)=111.5
So the distance from the tower to the object at 1.5seconds is:
111.5 " meters "

NEW QUESTION # 124
As a drone travels away from an operator, the function G(x)=24+47x models the distance, in yards, between the drone and the operator at x minutes. What is the value of G(1.9)?

A. 0
B. 1
C. 1.88
D. 113.3

Answer: D

Explanation:
This is a linear function evaluation problem. The function G(x)=24+47x gives the drone's distance from the operator after x minutes. The constant 24 is the starting distance, and 47 is the rate of change in yards per minute. To evaluate G(1.9), substitute 1.9 for x. Then compute G(1.9)=24+47(1.9). Multiplying first gives
47×1.9=89.3. Adding 24 gives 113.3. Because the function measures distance in yards, the result means the drone is 113.3 yards from the operator after 1.9 minutes. The other options do not result from correctly substituting 1.9 into the function. Therefore, the correct answer is D.

NEW QUESTION # 125
......

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