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>> Latest JS-Dev-101 Practice Questions <<
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NEW QUESTION # 108
Refer to the code below:
01 const objBook = {
02 title: 'JavaScript',
03 };
04 Object.preventExtensions(objBook);
05 const newObjBook = objBook;
06 newObjBook.author = 'Robert';
What are the values of objBook and newObjBook respectively?
Answer: C
Explanation:
Object.preventExtensions(obj)
This built-in JavaScript method marks an object so that no new properties can be added to it.
Existing properties can still be read and updated, but adding new ones is disallowed.
const newObjBook = objBook;
Both variables reference the same object in memory. JavaScript objects are assigned by reference, not copied.
newObjBook.author = "Robert";
Because the object has been marked as non-extensible, JavaScript will not allow new properties to be added.
The behavior depends on mode:
In non-strict mode: the assignment silently fails and does nothing.
In strict mode: this would throw a TypeError.
Since nothing indicates strict mode, this is non-strict behavior, making the assignment fail silently.
Therefore, the object remains:
{ title: "JavaScript" }
Both objBook and newObjBook point to the same unchanged object.
This matches option A.
JavaScript knowledge references (text-only)
Object.preventExtensions() prevents adding new properties.
Assigning an object to another variable copies the reference, not the object.
Adding a property to a non-extensible object silently fails in non-strict mode.
NEW QUESTION # 109
Refer to the code below:
let productSKU = '8675309';
A developer has a requirement to generate SKU numbers that are always 19 characters long, starting with 'sku', and padded with zeros.
Which statement assigns the value sku000000008675309?
Answer: C
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
We start with:
let productSKU = '8675309';
The requirement:
Final SKU string:
Length: 19 characters.
Starts with 'sku'.
Remaining characters are digits padded with zeros on the left (to reach total length).
We can use String.prototype.padStart and String.prototype.padEnd:
str.padStart(targetLength, padString)
If str.length < targetLength, it adds padString to the start until the length is targetLength.
str.padEnd(targetLength, padString)
Similar, but adds padString to the end.
We want a pattern like:
First, pad the numeric part out to a fixed length with zeros.
Then, pad to total length with 'sku' at the start.
Analyze Option B
productSKU = productSKU.padStart(16, '0').padStart(19, 'sku');
Step 1: productSKU.padStart(16, '0')
Initial productSKU is '8675309' (length 7).
After padStart(16, '0'), we pad zeros on the left to reach length 16.
We need 16 โ 7 = 9 zeros:
Result after step 1:
productSKU === '0000000008675309' // length 16
Step 2: .padStart(19, 'sku')
Now productSKU has length 16.
We call padStart(19, 'sku'):
We need 19 โ 16 = 3 extra characters.
The pad string 'sku' is exactly 3 characters, so it is added as-is at the start.
Result after step 2:
productSKU === 'sku0000000008675309' // length 19
This satisfies:
Length 19.
Starts with 'sku'.
Remaining characters are zeros plus the original digits, i.e. a zero-padded numeric section.
While the literal sample sku000000008675309 in the text has a slightly different count of zeros, Option B follows the requirement pattern:
3 characters of 'sku'
Numeric part padded with zeros to make 16 characters total for the numeric part
3 + 16 = 19 total characters
Option B matches the intended logic using padStart and padEnd.
Why the other options are incorrect
Option A:
productSKU = productSKU.padEnd(16, '0').padStart('sku');
padEnd(16, '0') produces '8675309000000000' (original number followed by zeros).
padStart('sku') is invalid usage:
padStart takes a numeric target length as the first argument, not a string.
Passing 'sku' as the first argument leads to type coercion that does not achieve the intended behavior.
This will not reliably produce the desired SKU.
Option C:
productSKU = productSKU.padEnd(16, '0').padStart(19, 'sku');
First padEnd(16, '0') from '8675309' gives '8675309000000000' (length 16, zeros at the end).
Then padStart(19, 'sku') adds 3 chars 'sku' at the front:
Result: 'sku8675309000000000'.
This string starts with 'sku', but the zeros are at the end of the digits, not padding the numeric part on the left as desired.
Option D:
productSKU = productSKU.padStart(19, '0').padStart('sku');
First padStart(19, '0') pads zeros at the left to make the length 19.
Then padStart('sku') again incorrectly uses a string where a numeric targetLength is required.
This will not produce the correct SKU format.
Therefore, the only option that correctly uses padStart to create a 16-character zero-padded numeric portion and then a 19-character string starting with 'sku' is:
Reference / Study Guide concepts (no links):
String.prototype.padStart(targetLength, padString)
String.prototype.padEnd(targetLength, padString)
String length calculations
Left-padding numeric strings with zeros
Building prefixed identifiers with fixed total length
NEW QUESTION # 110
There is a new requirement for a developer to implement a currPrice method that will return the current price of the item or sales..
What is the output when executing the code above
Answer: D
NEW QUESTION # 111
Code:
01 const sayHello = (name) => {
02 console.log('Hello ', name);
03 };
04
05 const world = () => {
06 return 'World';
07 };
08
09 sayHello(world);
This does not print "Hello World".
What change is needed?
Answer: C
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge:
Currently:
sayHello expects a value name and prints it.
world is a function that returns 'World'.
sayHello(world); passes the function object itself, not the result of calling it.
So name inside sayHello is a function, not the string "World".
To keep the call sayHello(world) yet get "World", sayHello must call the function parameter:
const sayHello = (name) => {
console.log('Hello', name());
};
Now:
sayHello(world) passes the function.
Inside sayHello, name() calls world(), which returns "World".
The console logs "Hello World".
Why the others are wrong:
B: Changing line 7 to }(); would attempt to IIFE the function definition and break the declaration.
C: sayHello(world)() would try to call the return value of sayHello, which is undefined, causing an error.
D: Changing world to a function declaration does not change the fact that it is passed as a function reference; sayHello still prints the function object, not 'World'.
________________________________________
NEW QUESTION # 112
What are two unique features of fat-arrow functions compared to normal function definitions?
Answer: A,D
Explanation:
Arrow functions have two defining characteristics:
Implicit return when written as a single expression:
const fn = () => 5; // returns 5 automatically
This is unique to arrow functions โ A is correct.
Lexical this binding:
Arrow functions do not create their own this.
Instead, they use the this value from the surrounding scope โ B is correct.
Incorrect options:
C is false: There is no special argument called parentThis.
D is the opposite of arrow function behavior:
Normal functions create their own this; arrow functions do not.
JavaScript Knowledge Reference (text-only)
Arrow functions have lexical this binding.
Arrow functions support implicit return for single expressions.
NEW QUESTION # 113
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