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Oracle 1z1-071 Exam Syllabus Topics:

Section	Objectives
Relational Database Concepts	- Tables, rows, columns, and relational model basics - Data types and database objects overview
SQL Retrieval	- Joins and set operations 1. UNION, INTERSECT, MINUS 2. INNER, OUTER, CROSS joins - SELECT statements and filtering data 1. WHERE clause and conditions 2. ORDER BY and row limiting
Subqueries and Advanced SQL	- Single-row and multi-row subqueries - Correlated subqueries and nested queries
Data Manipulation and Schema Objects	- DML operations 1. INSERT, UPDATE, DELETE, MERGE - DDL operations 1. CREATE, ALTER, DROP tables and constraints
SQL Functions	- Single-row functions 1. Character, numeric, date functions - Conversion and conditional functions 1. TO_CHAR, TO_NUMBER, CASE expressions

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최신 Oracle PL/SQL Developer Certified Associate 1z1-071 무료샘플문제 (Q121-Q126):

질문 # 121
Examine the description of the EMPLOYERS table:

Examine these requirements:
Disable the manager ID and salary of the lowest paid employees for that manager.
Exclude anyone whose manager is not known.
Exclude any managers where the minimum salary is 6000 or less.
Sort the output by minimum salary with the highest salary shown first.
Which statement will do this?

A. SELECT manager_id, MTN(salary)
FROM employees
WHERE manager_ id IS NOT NULL
GROUP BY manager_id
HAVING MlN (salary) > 6000
ORDER BV MlN (salary);
B. SELECT manager_id, MIN(salary)
FROM employees
WHERE manager_id IS NOT NULL
AND MIN(salary) > 6000
GROUP BY manager_id
ORDER BY MlN (salary) DESC;
C. SELECT managar_id, MIN (salary)
FROM employees
HAVING MIN(salary) > 6000
WHERE manager_id IS NOT NULL
GROUP BY manager_id
ORDER BY MTN(salary) DESC;
D. SELECT manager_id, HTN(salary)
FROM employees
WHERE manager_id IS NOT NULL
HAVING MIN (salary) > 6000
GROUP BY manager_id
ORDEU BY MIN (salary) DESC;

정답：A

질문 # 122
View and Exhibit and examine the structure and data in the INVOICE table.

Which two statements are true regarding data type conversion in query expressions? (Choose two.)

A. inv_date = '15-february-2008' :uses implicit conversion
B. inv_no BETWEEN '101' AND '110' : uses implicit conversion
C. inv_amt = '0255982' : requires explicit conversion
D. inv_date > '01-02-2008' : uses implicit conversion
E. CONCAT(inv_amt, inv_date) : requires explicit conversion

정답：A,B

질문 # 123
Examine the data in the EMP table:

You execute this query:
SELECT deptno AS "Department", AVG(sal) AS AverageSalary, MAX(sal) AS "Max Salary" FROM emp WHERE sal >= 12000 GROUP BY "Department " ORDER BY AverageSalary; Why does an error occur?

A. An alias name must always be specified in quotes.
B. An alias name must not be used in an ORDER BY clause.
C. An allas name must not contain space characters.
D. An alias name must not be used in a GROUP BY clause.

정답：D

설명：
C . True. The error occurs because the alias "Department" used in the GROUP BY clause is enclosed in double quotes, which makes it case-sensitive. However, the column deptno is not originally created with double quotes in the table definition, so you cannot refer to it with a case-sensitive alias in the GROUP BY clause. Oracle interprets "Department" as a string literal, not a column alias, in the GROUP BY clause.
A is incorrect because you can use an alias in an ORDER BY clause. B is incorrect because an alias can contain space characters if it is quoted. D is incorrect because an alias does not always have to be specified in quotes, only when it includes special characters or spaces or if it is case-sensitive.

질문 # 124
View the Exhibit and examine the structure of the ORDERStable.

Which UPDATE statement is valid?

A. UPDATE orders
SET order_date = '12-mar-2007',
order_total IS NULL
WHERE order_id = 2455;
B. UPDATE orders
SET order_date = '12-mar-2007',
AND order_total = TO_NUMBER(NULL)
WHERE order_id = 2455;
C. UPDATE orders
SET order_date = '12-mar-2007',
order_total = NULL
WHERE order_id = 2455;
D. UPDATE orders
SET order_date = TO_DATE('12-mar-2007','dd-mon-yyyy'),
SET order_total = TO_NUMBER (NULL)
WHERE order_id = 2455;

정답：C

질문 # 125
Examine this statement:
SELECT 1 AS id, ' John' AS first name
FROM DUAL
UNION
SELECT 1 , ' John' AS name
FROM DUAL
ORDER BY 1;
What is returned upon execution?

A. 0 rows
B. an error
C. 2 rows
D. 1 row

정답：D

설명：
The statement provided uses the UNION operator, which combines the results of two or more queries into a single result set. However, UNION also eliminates duplicate rows. Both queries in the union are selecting the same values 1 and ' John', thus the result is one row because duplicates will be removed.
SELECT 1 AS id, ' John' AS first name FROM DUAL UNION SELECT 1 , ' John' AS name FROM DUAL ORDER BY 1; Given that both SELECT statements are actually identical in the values they produce, despite the differing column aliases, the UNION will eliminate one of the duplicate rows, resulting in a single row being returned.
References:
* Oracle Documentation on UNION: SQL Language Reference - UNION

질문 # 126
......

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