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WGU Foundations-of-Programming-Python Exam Syllabus Topics:

Section	Weight	Objectives
Data Structures and Input/Output	20%	- Lists, tuples, dictionaries, sets - Basic file handling - User input and output operations
Control Flow and Decision Making	20%	- If, elif, else statements - Conditional expressions - Comparisons and logical operators
Functions and Modular Programming	20%	- Variable scope and code reuse - Defining and calling functions - Parameters, arguments, and return values
Loops and Iteration	20%	- Iterating over sequences - For loops and while loops - Break, continue, and pass statements
Variables, Data Types, and Basic Operations	20%	- Variables and assignment - Data types: integers, floats, strings, booleans - Arithmetic operations and type conversion

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WGU Foundations of Programming (Python) - E010 JIV1 Sample Questions (Q34-Q39):

NEW QUESTION # 34
In the code for item in my_list:, what does item represent?

A. The entire list
B. The length of the list
C. The current element being processed
D. The index of the current element

Answer: C

Explanation:
In the loop:
for item in my_list:
print(item)
item represents the current element from my_list during each loop iteration.
For example:
my_list = [ " apple " , " banana " ]
for item in my_list:
print(item)
The loop first processes " apple " , then " banana " . Python's documentation explains that a for statement iterates over the items of a sequence in order.
Therefore, the correct answer isB. The current element being processed.

NEW QUESTION # 35
Complete the function is_positive(number) that returns True if the number is greater than 0, and False otherwise.
def is_positive(number):
# TODO: Return True if number > 0, False otherwise
pass

Answer:

Explanation:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: The function receives one parameter named number.
Step 2: The condition number > 0 checks whether the number is positive.
Step 3: In Python, this comparison already returns either True or False.
Correct code:
def is_positive(number):
return number > 0
Example:
print(is_positive(5))
print(is_positive(-2))
print(is_positive(0))
Output:
True
False
False

NEW QUESTION # 36
Write a complete function password_strength(password) that returns " Strong " if the password is at least 8 characters long and contains both letters and numbers, " Weak " otherwise.
For example, password_strength( " abc123def " ) should return " Strong " .
def password_strength(password):
# TODO: Return " Strong " or " Weak " based on password criteria
if len(password) < 8:
return " Weak "
has_letter = False
has_number = False
for char in password:
if char.isalpha():
has_letter = True
elif char.isdigit():
has_number = True
# TODO: Add your return logic here based on has_letter and has_number
pass

Answer:

Explanation:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: First, check the password length using len(password).
Step 2: If the password has fewer than 8 characters, return " Weak " immediately.
Step 3: Create two Boolean variables: has_letter and has_number.
Step 4: Loop through each character in the password.
Step 5: Use .isalpha() to check for letters and .isdigit() to check for numbers.
Step 6: If the password contains both at least one letter and at least one number, return " Strong " .
Step 7: Otherwise, return " Weak " .
Correct code:
def password_strength(password):
if len(password) < 8:
return " Weak "
has_letter = False
has_number = False
for char in password:
if char.isalpha():
has_letter = True
elif char.isdigit():
has_number = True
if has_letter and has_number:
return " Strong "
else:
return " Weak "
Example:
print(password_strength( " abc123def " ))
print(password_strength( " abcdefgh " ))
print(password_strength( " 12345678 " ))
Output:
Strong
Weak
Weak

NEW QUESTION # 37
Complete the function double_number(num) that takes one number parameter and returns double that number.
For example, double_number(5) should return 10.
def double_number(num):
# TODO: Return double the input number
# Example: double_number(5) should return 10
pass

Answer:

Explanation:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: The function receives one parameter named num.
Step 2: To double a number, multiply it by 2.
Step 3: The function should return the result using the return statement.
Correct code:
def double_number(num):
return num * 2
Example:
print(double_number(5))
Output:
10

NEW QUESTION # 38
Fix the logic error in this function that should return the larger of two numbers.
def find_maximum(a, b):
if a < b:
return a
else:
return b

Answer:

Explanation:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: The function should return the larger number.
Step 2: The condition a < b means b is larger than a.
Step 3: In the original code, when a < b is true, it incorrectly returns a.
Step 4: The return values need to be corrected.
Correct code:
def find_maximum(a, b):
if a < b:
return b
else:
return a
Alternative correct code:
def find_maximum(a, b):
if a > b:
return a
else:
return b
Example:
print(find_maximum(10, 20))
print(find_maximum(30, 15))
Output:
20
30

NEW QUESTION # 39
......

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