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| Section | Weight | Objectives |
|---|---|---|
| MPLS Technologies | 19% | - MPLS basics and label distribution - MPLS VPN and traffic engineering - MPLS protection and fast reroute |
| Advanced Ethernet Technologies | 10% | - Advanced link aggregation and reliability - VLAN stacking and QinQ - Ethernet OAM and protection mechanisms |
| Network Cutover and Migration | 7% | - Migration strategies and risk control - Service switchover and verification |
| IPv6 Routing | 20% | - BGP4+ and IPv6 route deployment - OSPFv3 and IS-IS for IPv6 - IPv6 addressing and transition technologies |
| Network Troubleshooting | 10% | - Troubleshooting routing and switching issues - Fault diagnosis and analysis methods |
| Network O&M | 7% | - Network monitoring and management tools - Performance optimization and capacity planning |
| Advanced IGP Features | 17% | - IGP route selection and control - IS-IS advanced features and convergence - OSPF advanced features and optimization |
| Advanced BGP Features | 10% | - Route reflectors and confederations - BGP path control and filtering - BGP route attributes and policies |
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NEW QUESTION # 240 
On the OSPF network shown in the figure, the cost values of links are marked. OSPF IP FRR is enabled on R1, and the maximum load-balancing 8 command is configured in the OSPF process. Which of the following is the cost value of the route 10.0.35.0/24 in the routing table of R1?
Answer: A
Explanation:
Comprehensive and Detailed In-Depth Explanation:
To determine the cost value of the route 10.0.35.0/24 in the routing table of R1, let ' s analyze the possible shortest paths from R1 to R3 (which owns the 10.0.35.0/24 network) based on the given OSPF link costs:
* Path 1: R1 # R2 # R3
* R1 to R2: Cost = 20
* R2 to R3: Cost = 10
* Total Cost = 20 + 10 = 30
* Path 2: R1 # R4 # R3
* R1 to R4: Cost = 10
* R4 to R3: Cost = 10
* Total Cost = 10 + 10 = 20 # (Lowest cost path)
* Path 3: R1 # R5 # R3
* R1 to R5: Cost = 10
* R5 to R3: Cost = 10
* Total Cost = 10 + 10 = 20 # (Equal-cost path)
Final Calculation:
* The two best equal-cost paths (R1 # R4 # R3 and R1 # R5 # R3) have a cost of 20.
* Since OSPF supports equal-cost multi-path (ECMP) routing and maximum load-balancing 8 is enabled, OSPF will install both routes into the routing table with the same cost of 20.
* The path R1 # R2 # R3 has a higher cost (30) and will not be chosen.
Final Answer: # 20 (Option C)
References:
HCIP-Datacom-Advanced Routing & Switching Technology V1.0 - OSPF Route Calculation & Load Balancing OSPF Equal-Cost Multi-Path (ECMP) and Route Selection OSPF Fast Reroute (FRR) Mechanism
NEW QUESTION # 241
Link LSAs of OSPFv3 are propagated throughout the area.
Answer: B
NEW QUESTION # 242
A park deployed IPv6 for business testing. There are 4 routers (R1, 22, R3 and R4) in this network, running OSPFv3 to realize the interconnection of IPv6 network. There is a new router R5 that needs to be connected to the network for testing. An engineer introduced a direct route in the OSPFvV3 process of R4 to realize that the devices in the campus network can access the GE0/0/1 port address of R5. Which of the following descriptions of the scene are correct? (Multiple choice)
Answer: A,C,D
NEW QUESTION # 243
On the network shown in the figure, EBGP peer relationships are established between neighboring routers through directly connected interfaces .
* The router ID of each router is 10.0.X.X , and the AS number is 6500X , where X is the number of the router .
* Both R1 and R4 have static routes to 192.168.1.0/24 , which are imported to BGP through the import-route command.
Which of the following statements are true ?
Answer: A,B,C,D
Explanation:
Comprehensive and Detailed In-Depth Explanation:
Understanding the BGP Network Topology in the Question:
* EBGP Peering
* Each router forms EBGP peer relationships with directly connected neighbors.
* This is a fully meshed topology , meaning each router exchanges BGP routes with its adjacent routers .
* Routing Information for 192.168.1.0/24
* R1 and R4 import the static route 192.168.1.0/24 into BGP.
* Since BGP prefers the shortest AS path , traffic to 192.168.1.0/24 will follow the shortest path to R1 or R4 .
Route Analysis for Each Statement:
Statement A: R6 # R5 # R4 # (Correct)
* R6 does not have a direct route to 192.168.1.0/24 , so it must rely on BGP advertisements from its EBGP neighbors .
* R5 learns the route to 192.168.1.0/24 from R4 .
* Therefore, R6 forwards traffic to R5, and then R5 sends it to R4 .
# Correct path: R6 # R5 # R4
Statement B: R5 # R4 # (Correct)
* R5 is directly connected to R4 , and since R4 advertises the 192.168.1.0/24 route via BGP ,
* R5 will forward traffic directly to R4 as the shortest AS path .
# Correct path: R5 # R4
Statement C: R2 # R1 # (Correct)
* R2 is directly connected to R1 and learns the 192.168.1.0/24 route from R1 via BGP .
* Since R1 advertises the static route, R2 forwards traffic directly to R1.
# Correct path: R2 # R1
Statement D: R3 # R2 # R1 # (Correct)
* R3 is directly connected to R2 and learns the 192.168.1.0/24 route from R2 via BGP .
* Since R2 prefers R1 as the shortest AS path to 192.168.1.0/24 ,
* R3 will send traffic to R2, and R2 will send it to R1 .
# Correct path: R3 # R2 # R1
Final Conclusion:
# A. The path for traffic from R6 to 192.168.1.0/24 is R6 # R5 # R4.
# B. The path for traffic from R5 to 192.168.1.0/24 is R5 # R4.
# C. The path for traffic from R2 to 192.168.1.0/24 is R2 # R1.
# D. The path for traffic from R3 to 192.168.1.0/24 is R3 # R2 # R1.
Thus, the correct answers are: A, B, C, D .
Reference:
HCIP-Datacom-Advanced Routing & Switching Technology V1.0 - BGP Best Path Selection and AS Path Preferences Huawei Official HCIP-Datacom Study Guide - EBGP Route Advertisement and Static Route Import into BGP Huawei Documentation on BGP Route Selection and Path Preference Mechanisms
NEW QUESTION # 244
The exchange of Hello messages between two LSRs (Label switching Routers) triggers the establishment of an LDP session. The Hello message carries the transport address. The device with the smaller transport address will act as the active party and initiate the establishment of a TCP connection.
Answer: A
NEW QUESTION # 245
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