我們KaoGuTi配置提供給你最優質的Apple的App-Development-with-Swift-Certified-User考試考古題及答案，將你一步一步帶向成功，我們KaoGuTi Apple的App-Development-with-Swift-Certified-User考試認證資料絕對提供給你一個真實的考前準備，我們針對性很強，就如同為你量身定做一般，你一定會成為一個有實力的IT專家，我們KaoGuTi Apple的App-Development-with-Swift-Certified-User考試認證資料將是最適合你也是你最需要的培訓資料，趕緊註冊我們KaoGuTi網站，相信你會有意外的收穫。
| Section | Objectives |
|---|---|
| App Logic and Data Handling | - Data management in apps
|
| Introduction to App Development with Swift | - Swift programming fundamentals
|
| User Interface Development | - Building iOS interfaces
|
| App Lifecycle and Deployment Concepts | - Understanding app structure
|
>> App-Development-with-Swift-Certified-User考題套裝 <<
Apple App-Development-with-Swift-Certified-User 認證考試是個檢驗IT專業知識的認證考試。KaoGuTi是個能幫你快速通過Apple App-Development-with-Swift-Certified-User 認證考試的網站。在您考試之前使用我們提供的針對性培訓和測試練習題和答案，短時間內你會有很大的收穫。
問題 #23
Review the code snippet.
What value does the code output?
答案：
解題說明：
Answer the question by typing in the box.
2
Explanation:
This question belongs to Swift Programming Language , specifically the objectives covering functions , control flow , and default parameter values . The function is declared as func getAgeCategory(_ age: Int =
20) - > Int, which means if no argument is supplied, Swift uses the default value 20. Apple's Swift documentation explains that you can define a default value for any parameter, and that value is used when the caller omits that argument. Since the code calls getAgeCategory() with no parameter, the function executes using age = 20.
The conditional logic is then evaluated in order:
* if age > 64 # false, because 20 is not greater than 64
* else if age > 19 # true, because 20 is greater than 19
* so the function returns 2
Because Swift's if / else if control flow stops at the first true condition, the later checks are never reached once age > 19 succeeds. Apple describes Swift as supporting standard control flow including conditional branching, and this example is a direct use of that branching behavior.
Therefore, print(getAgeCategory()) outputs 2 , which corresponds to option B .
問題 #24
Complete the code that will add the BlueView to the NavigationStack and present the RedView modally.
|Complete the code by typing in the boxes.
答案：
解題說明：
NavigationLink, .sheet
Explanation:
This question falls under View Building with SwiftUI , specifically the domain covering multi-view apps with navigation stacks, links, and sheets . The first blank must be NavigationLink because SwiftUI uses a navigation link inside a NavigationStack to push or present a destination view as part of the navigation hierarchy. Apple's documentation states that people tap or click a NavigationLink to present a view inside a NavigationStack or NavigationSplitView. That matches the first code section, where tapping " Show Blue View " should navigate to BlueView().
The second blank must be .sheet because the code uses isPresented: $showRedView, which is the standard SwiftUI sheet modifier for modal presentation controlled by a Boolean binding. Apple documents sheet (isPresented:onDismiss:content:) as the modifier to use when you want to present a modal view when a Boolean becomes true. Since the button toggles showRedView, SwiftUI presents RedView() modally as a sheet.
So the completed structure is effectively:
NavigationLink( " Show Blue View " ) {
BlueView()
}
sheet(isPresented: $showRedView) {
RedView()
}
This directly aligns with SwiftUI navigation and modal presentation patterns in the App Development with Swift objective domains.
問題 #25
When you press ' Show Button ' on your app. a modal View appears.
Complete the code by selecting the correct option from each drop-down list.
Note: You will receive partial credit for each correct answer.
答案：
解題說明：
Explanation:
This question belongs to View Building with SwiftUI , specifically the domain on creating a multi-view app with navigation stacks, links, and sheets .
To present a modal view in SwiftUI when a Boolean state changes, the correct modifier is .sheet . The matching sheet API for a Boolean binding is:
sheet(isPresented: $showInfo) {
// modal content
}
So the first blank must be .sheet , and the second blank must be (isPresented: .
The logic works like this:
* @State stores the local Boolean that controls presentation.
* Pressing the button calls showInfo.toggle(), changing the value from false to true.
* When that Boolean becomes true, the .sheet(isPresented:) modifier presents the modal view.
* When the modal is dismissed, SwiftUI updates the Boolean back as needed.
There is also a typing issue in the screenshot: the state variable appears as ShowInfo, while the button and binding use showInfo. Swift is case-sensitive, so those names must match. The corrected code should use the same identifier consistently, such as:
@State var showInfo = false
Therefore, the correct dropdown selections are:
sheet
(isPresented:
問題 #26
Review the code snippet.
The code snippet does not compile.
Which two actions will fix the errors? (Choose 2.)
答案：B,D
解題說明：
This question belongs to Swift Programming Language , especially the domains covering basic Swift types
, operators , and constants versus variables .
There are two compile problems in the snippet. First, unitPrice and shipping are inferred as Double, while quantity is inferred as Int. In Swift, arithmetic operands must have compatible types; Swift does not automatically mix Int and Double in one arithmetic expression. So unitPrice * quantity fails unless quantity is changed to Double or explicitly converted. That makes A a correct fix.
Second, the line totalCost += ... uses the compound assignment operator +=, which stores a new value back into the left-hand side. Swift requires the left-hand side of += to be mutable, so totalCost must be declared with var, not let. That makes D the second correct fix.
The other choices do not solve the actual compile issues. B is unnecessary because totalCost is already explicitly declared as Double, so 0 is valid there. C would still leave shipping as Double, so the mixed-type arithmetic problem remains. E is irrelevant because shipping is never reassigned. Therefore, the two correct answers are A and D
問題 #27
For each statement about Navigation in SwiftUI. select True or False.
答案：
解題說明：
Explanation:
* You can treat a NavigationLink like a button, and run some Swift code when it is pressed. - False
* NavigationSplitView can be used to do navigation differently on different device sizes. - True
* You can put a header on your present View in a NavigationStack using .navigationTitle. - True
* If you have a NavigationLink that goes to another View with a NavigationLink, you need to declare a NavigationStack at each level. - False This question belongs to View Building with SwiftUI , specifically the objective on creating a multi-view app with navigation stacks, links, and sheets . Statement 1 is False because NavigationLink is primarily a navigation control that pushes or presents a destination in a navigation container; Apple documents it as creating a navigation link that presents a destination, not as a general-purpose action control like Button.
Statement 2 is True because NavigationSplitView is designed for adaptive navigation and can present navigation in different ways depending on platform and available space. Apple documents NavigationSplitView as a container for navigation across multiple columns, and this adaptive behavior is exactly why it is used differently across device sizes.
Statement 3 is True because .navigationTitle(...) sets the navigation title for a view shown inside a navigation container. Apple explicitly describes a view's navigation title as something used to visually display the current navigation state of an interface.
Statement 4 is False because you do not need a separate NavigationStack at every level. Apple describes NavigationStack as the container that manages a stack of views, and NavigationLink pushes additional destinations onto that stack. Nested destinations can keep navigating within the same stack.
問題 #28
......
KaoGuTi為你提供了不同版本的資料以方便你的使用。PDF版的App-Development-with-Swift-Certified-User考古題方便你的閱讀，為你真實地再現考試題目。軟體版本的App-Development-with-Swift-Certified-User考古題作為一個測試引擎，可以幫助你隨時測試自己的準備情況。如果你想知道你是不是充分準備好了App-Development-with-Swift-Certified-User考試，那麼你可以利用軟體版的考古題來測試一下自己的水準。這樣你就可以快速找出自己的弱點和不足，進而有利於你的下一步學習安排。
App-Development-with-Swift-Certified-User考試題庫: https://www.kaoguti.com/App-Development-with-Swift-Certified-User_exam-pdf.html