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| Section | Objectives |
|---|---|
| Xcode Developer Tools | - Identify and use the features of the Xcode interface
|
| View Building with SwiftUI | - Use @State, @Binding, @Environment, and/or Observable to share data between Views - Create a multi-view app with navigation Stacks, Links, and/or Sheets - Position and/or layout a single SwiftUI View with standard Views and modifiers - Extract Subviews to simplify the structure of an overlarge View - Use List Views to iterate through collections - Create multiple Views to implement app logic |
| Swift Programming Language | - Evaluate variable scope and shadowing - Declare and use basic Swift types
|
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NEW QUESTION # 17
If View A calls View B, which Swift Property Wrapper would you use in View B in order to return the value of a state to View A?
Answer: A
Explanation:
Comprehensive and Detailed Explanation From App Development with Swift domains:
This question belongs to View Building with SwiftUI , specifically the objective on using @State,
@Binding, @Environment, and observable data to share data between views.
The correct answer is @Binding because @Binding creates a two-way connection to a value that is owned by another view. In this scenario, View A owns the state, and View B needs to read and modify that value so the change is reflected back in View A. Apple's SwiftUI documentation describes a binding as a reference to a mutable value that is owned elsewhere, which is exactly the pattern used when a child view needs to update a parent view's state. ( developer.apple.com )
@State is not correct for View B here because @State is used for local state owned by that specific view. If View B used @State, it would manage its own separate copy rather than updating the parent's value.
@Environment is used to access values provided by the system or ancestor views, not for directly returning a specific parent state value in this pattern. @Observable is related to observable model objects and is not the direct property wrapper used in a child view for two-way parent-child state passing. ( developer.apple.com ) So when View A passes a state value into View B and expects updates to flow back, View B should use
@Binding .
NEW QUESTION # 18
Review the code.
struct ContentView: View {
let fruits = [ " Apple " , " Banana " , " Kiwi " ]
var body: some View {
List(fruits, id: \.self) { fruit in
Text(fruit)
.font(.headline)
.padding()
}
}
}
Which of the following statements is true about the code?
Answer: A
Explanation:
Comprehensive and Detailed Explanation From App Development with Swift domains:
This question belongs to View Building with SwiftUI , especially the domain covering List Views to iterate through collections . In the code, fruits is an array of strings, and the List initializer is being used to create one row for each item in that collection. Apple's SwiftUI documentation explains that List can present rows from a collection of data, and when the data elements are not supplied through a type that already provides identity, you can provide an id key path so SwiftUI can uniquely identify each row. Here, id: \.self tells SwiftUI to use each string value itself as the identifier.
Option D is therefore the correct statement because the List is clearly rendering the contents of the fruits array as separate rows, and each row shows a Text(fruit) view. Apple's app development tutorials describe List as a container view that displays rows of data arranged in a single scrollable column, which matches exactly what this code is doing.
Option A is false because for an array of String values in this form, id: \.self is used to identify each row.
Option B is false because the key path is not related to .font(.headline) or .padding(); those are standard view modifiers, not dynamic property extraction in this example. Option C is false because Swift key-path syntax uses a backslash, as in \.self, not /self. Apple's KeyPath documentation shows that Swift key paths use the backslash form.
NEW QUESTION # 19
You are creating or updating human resource records for your employees. For each identifier, select whether it is a Constant or a Variable Note: You will receive partial credit for each correct answer.
Answer:
Explanation:
Explanation:
* age - Variable
* birthDate - Constant
* socialSecurityNumber - Constant
* salary - Variable
* currentDepartment - Variable
This question belongs to Swift Programming Language , specifically the objective on demonstrating when to use constants and variables . In Swift, a constant is declared with let and is used for values that should not change after they are set. A variable is declared with var and is used for values that may change over time.
Birth date is a constant because a person's date of birth does not change. Social security number is also a constant because it is intended to be a fixed identifier for that employee record. By contrast, age is a variable because it changes over time. Salary is a variable because compensation can be adjusted. Current department is also a variable because an employee may transfer to another department.
This matches Swift best practice: use let for fixed data and var for mutable data. So in a human resources record, identifiers that are permanent should be constants, while values that can change during employment should be variables.
NEW QUESTION # 20
Review the code.
You need to add the word " Great! " to the Capsule shape.
Complete the code by typing in the boxes.
Answer:
Explanation:
overlay, Text
Explanation:
This question belongs to View Building with SwiftUI , particularly the domain involving positioning and/or laying out a single SwiftUI view with standard views and modifiers . To place text on top of a shape such as a Capsule, SwiftUI uses the overlay modifier. Apple documents overlay as a view modifier that layers one view in front of another, which is exactly what is needed here: the text should appear on top of the blue capsule rather than beside or below it. The second blank must therefore be Text , because SwiftUI uses a Text view to display string content like " Great! " .
The completed code is:
struct ContentView: View {
var body: some View {
Capsule()
.fill(.blue)
.frame(width: 200.0, height: 100.0)
.overlay(
Text( " Great! " )
.font(.largeTitle)
)
}
}
This works because Capsule() creates the shape, .fill(.blue) gives it the blue color, .frame(width:height:) sets its size, and .overlay(...) places the Text( " Great! " ) directly above that shape. This is a standard SwiftUI composition pattern: build a base view, then apply modifiers to style it and layer additional content. In App Development with Swift objectives, this aligns with understanding standard views, modifiers, and layout techniques in SwiftUI.
NEW QUESTION # 21
Review the code snippet and then predict the output.
Answer: D
Explanation:
This question belongs to Swift Programming Language , especially the domains covering control flow , loops , logical operators , and guard . The loop runs through 0.. < max, and since max = 101, the values of num are 0 through 100. Inside the loop, the guard statement keeps only values that satisfy both conditions:
* num % 5 == 0 # the number must be divisible by 5
* num % 2 != 0 # the number must be odd
So the code counts numbers from 0 to 100 that are odd multiples of 5 . Those values are:
5, 15, 25, 35, 45, 55, 65, 75, 85, 95
That gives a total of 10 numbers. Therefore count becomes 10, and the printed output is:
Total count: 10
The key Swift concept here is that guard ... else { continue } skips any loop iteration that does not meet the required condition. Only matching values reach count += 1. This is a standard use of guard for early exit and of the remainder operator % for divisibility checks. Therefore, the correct answer is B .
NEW QUESTION # 22
......
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