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Snowflake ARA-C01 Exam Syllabus Topics:

Section	Objectives
Security, Governance, and Compliance	- Data governance 1. Audit and compliance features 2. Data classification and masking policies - Access control and security model 1. Role-based access control (RBAC) 2. Network security and authentication
Performance and Optimization	- Query performance tuning 1. Query profiling and optimization techniques 2. Warehouse sizing and scaling - Cost optimization 1. Storage and compute efficiency 2. Resource monitoring and cost control
Data Sharing and Collaboration	- Secure data sharing 1. Data marketplace concepts 2. Cross-account data sharing
Data Pipelines and Data Engineering	- Data ingestion and transformation 1. Batch and streaming ingestion 2. Snowpipe and continuous data loading - Data orchestration 1. Pipeline design patterns 2. Tasks and Streams usage
Data Architecture and Design	- Data modeling and schema design 1. Star and snowflake schema concepts 2. Semi-structured data modeling - Design scalable Snowflake architectures 1. Account and environment strategy 2. Multi-cluster virtual warehouse design

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Snowflake SnowPro Advanced Architect Certification Sample Questions (Q131-Q136):

NEW QUESTION # 131
An Architect is implementing a CI/CD process. When attempting to clone a table from a production to a development environment, the cloning operation fails.
What could be causing this to happen?

A. The table is transient.
B. Tables cannot be cloned from a higher environment to a lower environment.
C. The retention time for the table is set to zero.
D. The table has a masking policy.

Answer: D

Explanation:
Cloning a table with a masking policy can cause the cloning operation to fail because the masking policy is not automatically cloned with the table. This is due to the fact that the masking policy is considered a separate object with its own set of privileges1.
References
Snowflake Documentation on Cloning Considerations1.

NEW QUESTION # 132
A company has an inbound share set up with eight tables and five secure views. The company plans to make the share part of its production data pipelines.
Which actions can the company take with the inbound share? (Choose two.)

A. Create a table stream on the shared table.
B. Create additional views inside the shared database.
C. Create a table from the shared database.
D. Clone a table from a share.
E. Grant modify permissions on the share.

Answer: B,D

Explanation:
Explanation
These two actions are possible with an inbound share, according to the Snowflake documentation and the web search results. An inbound share is a share that is created by another Snowflake account (the provider) and imported into your account (the consumer). An inbound share allows you to access the data shared by the provider, but not to modify or delete it. However, you can perform some actions with the inbound share, such as:
* Clone a table from a share. You can create a copy of a table from an inbound share using the CREATE TABLE ... CLONE statement. The clone will contain the same data and metadata as the original table, but it will be independent of the share. You can modify or delete the clone as you wish, but it will not reflect any changes made to the original table by the provider1.
* Create additional views inside the shared database. You can create views on the tables or views from an inbound share using the CREATE VIEW statement. The views will be stored in the shared database, but they will be owned by your account. You can query the views as you would query any other view in your account, but you cannot modify or delete the underlying objects from the share2.
The other actions listed are not possible with an inbound share, because they would require modifying the share or the shared objects, which are read-only for the consumer. You cannot grant modify permissions on the share, create a table from the shared database, or create a table stream on the shared table34.
References:
* Cloning Objects from a Share | Snowflake Documentation
* Creating Views on Shared Data | Snowflake Documentation
* Importing Data from a Share | Snowflake Documentation
* Streams on Shared Tables | Snowflake Documentation

NEW QUESTION # 133
What step will im the performance of queries executed against an external table?

A. Convert the source files' character encoding to UTF-8.
B. Shorten the names of the source files.
C. Use an internal stage instead of an external stage to store the source files.
D. Partition the external table.

Answer: D

Explanation:
Partitioning an external table is a technique that improves the performance of queries executed against the table by reducing the amount of data scanned. Partitioning an external table involves creating one or more partition columns that define how the table is logically divided into subsets of data based on the values in those columns. The partition columns can be derived from the file metadata (such as file name, path, size, or modification time) or from the file content (such as a column value or a JSON attribute). Partitioning an external table allows the query optimizer to prune the files that do not match the query predicates, thus avoiding unnecessary data scanning and processing2 The other options are not effective steps for improving the performance of queries executed against an external table:
Shorten the names of the source files. This option does not have any impact on the query performance, as the file names are not used for query processing. The file names are only used for creating the external table and displaying the query results3 Convert the source files' character encoding to UTF-8. This option does not affect the query performance, as Snowflake supports various character encodings for external table files, such as UTF-8, UTF-16, UTF-32, ISO-8859-1, and Windows-1252. Snowflake automatically detects the character encoding of the files and converts them to UTF-8 internally for query processing4 Use an internal stage instead of an external stage to store the source files. This option is not applicable, as external tables can only reference files stored in external stages, such as Amazon S3, Google Cloud Storage, or Azure Blob Storage. Internal stages are used for loading data into internal tables, not external tables5 Reference:
1: SnowPro Advanced: Architect | Study Guide
2: Snowflake Documentation | Partitioning External Tables
3: Snowflake Documentation | Creating External Tables
4: Snowflake Documentation | Supported File Formats and Compression for Staged Data Files
5: Snowflake Documentation | Overview of Stages
6: SnowPro Advanced: Architect | Study Guide
7: Partitioning External Tables
8: Creating External Tables
9: Supported File Formats and Compression for Staged Data Files
10: Overview of Stages

NEW QUESTION # 134
A table, EMP_ TBL has three records as shown:

The following variables are set for the session:

Which SELECT statements will retrieve all three records? (Select TWO).

A. SELECT * FROM identifier($tbl_ref) WHERE ID IN Cvarl','var2','var3');
B. SELECT * FROM EMP_TBL WHERE identifier(Scol_ref) IN ('Namel','Name2', 'Name3');
C. SELECT * FROM identifier<Stbl_ref> WHERE NAME IN ($var1, $var2, $var3);
D. Select * FROM Stbl_ref WHERE Scol_ref IN ('Name1','Nam2','Name3');
E. SELECT * FROM $tb1_ref WHERE $col_ref IN ($var1, Svar2, Svar3);

Answer: B,E

Explanation:
* The correct answer is B and E because they use the correct syntax and values for the identifier function and the session variables.
* The identifier function allows you to use a variable or expression as an identifier (such as a table name or column name) in a SQL statement. It takes a single argument and returns it as an identifier. For example, identifier($tbl_ref) returns EMP_TBL as an identifier.
* The session variables are set using the SET command and can be referenced using the $ sign. For example, $var1 returns Name1 as a value.
* Option A is incorrect because it uses Stbl_ref and Scol_ref, which are not valid session variables or identifiers. They should be $tbl_ref and $col_ref instead.
* Option C is incorrect because it uses identifier<Stbl_ref>, which is not a valid syntax for the identifier function. It should be identifier($tbl_ref) instead.
* Option D is incorrect because it uses Cvarl, var2, and var3, which are not valid session variables or values. They should be $var1, $var2, and $var3 instead. References:
* Snowflake Documentation: Identifier Function
* Snowflake Documentation: Session Variables
* Snowflake Learning: SnowPro Advanced: Architect Exam Study Guide

NEW QUESTION # 135
All multi cluster warehouses that were using the Legacy policy now use the default Standard policy

A. TRUE
B. FALSE

Answer: A

NEW QUESTION # 136
......

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