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Salesforce JavaScript-Developer-I Exam Syllabus Topics:

SectionWeightObjectives
Debugging and Error Handling7%- Error types and exception handling
- Defensive programming practices
- Console methods and logging
- Debugging tools and breakpoints
Testing7%- Code coverage and best practices
- Test doubles and mocks
- Testing frameworks and assertions
- Unit testing concepts
Browsers and Events17%- Window and document object properties
- Event handling, propagation, and delegation
- Document Object Model (DOM) manipulation
- Script loading and execution order
- Browser APIs and Web Storage
Objects, Functions, and Classes25%- Decorators and advanced function patterns
- Modules and imports/exports
- Class syntax, inheritance, and prototypes
- Object creation, properties, and methods
- Function definitions, parameters, and scope
- Closures and execution context
Server-Side JavaScript8%- Command-line tools and scripts
- Node.js fundamentals and runtime
- Module system and require/import
- Core Node.js modules
Variables, Types, and Collections23%- JSON parsing and usage
- Array methods and data manipulation
- Type coercion and conversion rules
- Truthy and falsy values
- Variable declaration and initialization
- Working with strings, numbers, dates, and booleans
Asynchronous Programming13%- Fetch API and HTTP requests
- Promises and chaining
- Async/await syntax
- Callbacks and callback hell
- Event loop and micro/macro tasks

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Salesforce Certified JavaScript Developer (JS-Dev-101) Sample Questions (Q122-Q127):

NEW QUESTION # 122
Refer to the following code block:
01 let array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11];
02 let output = 0;
03
04 for (let num of array) {
05 if (output > 10) {
06 break;
07 }
08 if (num % 2 == 0) {
09 continue;
10 }
11 output += num;
12 }
What is the value of output after the code executes?

Answer: C

Explanation:
This code uses:
* A for...of loop to iterate over values in array.
* break to exit the loop entirely when output > 10.
* continue to skip even numbers.
* It sums only certain numbers into output.
Let's walk through the loop step by step.
Initial values:
* array = [1,2,3,4,5,6,7,8,9,10,11]
* output = 0
Loop: for (let num of array) { ... }
* First iteration: num = 1
* Line 05: if (output > 10) # 0 > 10 is false # no break.
* Line 08: if (num % 2 == 0) # 1 % 2 == 1, not 0, so false # no continue.
* Line 11: output += num # output = 0 + 1 = 1.
* Second iteration: num = 2
* output > 10 # 1 > 10 is false # no break.
* num % 2 == 0 # 2 % 2 == 0, so true # continue.
* Because of continue, line 11 is skipped.
* output remains 1.
* Third iteration: num = 3
* output > 10 # 1 > 10 is false.
* num % 2 == 0 # 3 % 2 == 1, false # no continue.
* output += num # output = 1 + 3 = 4.
* Fourth iteration: num = 4
* output > 10 # 4 > 10 is false.
* num % 2 == 0 # 4 % 2 == 0, true # continue.
* Skip sum; output remains 4.
* Fifth iteration: num = 5
* output > 10 # 4 > 10 is false.
* num % 2 == 0 # 5 % 2 == 1, false.
* output += num # output = 4 + 5 = 9.
* Sixth iteration: num = 6
* output > 10 # 9 > 10 is false.
* num % 2 == 0 # 6 % 2 == 0, true # continue.
* output remains 9.
* Seventh iteration: num = 7
* output > 10 # 9 > 10 is false.
* num % 2 == 0 # 7 % 2 == 1, false.
* output += num # output = 9 + 7 = 16.
* Eighth iteration would be num = 8, but:
At the top of the loop body, line 05 is checked again:
* if (output > 10) # 16 > 10 is true, so break; is executed.
When break runs:
* The loop terminates immediately.
* No further iterations (for num = 8, 9, 10, 11) are executed.
* Therefore, output stays at 16.
Final value of output after the loop ends is 16.
This matches option A.
Why other options do not match:
* B. 25: Would require adding more odd numbers (e.g., 9, 11) after 7, but the loop stops early due to output > 10.
* C. 11: Would be smaller; the actual sum of 1 + 3 + 5 + 7 until break is 16.
* D. 36: Would require summing many more values (e.g., most or all odd numbers up to 11), but again, the break condition stops the loop once output exceeds 10.
So:
The answer: A
JavaScript knowledge / Study Guide references (concept names only, no links):
* for...of loop over arrays
* break statement in loops (terminating a loop early)
* continue statement in loops (skipping to the next iteration)
* Modulo operator % to test even and odd numbers
* Step-by-step execution and control flow in loops


NEW QUESTION # 123
Refer to the code below:
Function changeValue(obj) {
Obj.value = obj.value/2;
}
Const objA = (value: 10);
Const objB = objA;
changeValue(objB);
Const result = objA.value;
What is the value of result after the code executes?

Answer: A


NEW QUESTION # 124
Refer to the code below:
for(let number =2 ; number <= 5 ; number += 1 ) {
// insert code statement here
}
The developer needs to insert a code statement in the location shown. The code statement has these requirements:
1. Does require an import
2. Logs an error when the boolean statement evaluates to false
3. Works in both the browser and Node.js
Which meet the requirements?

Answer: C


NEW QUESTION # 125
Given the code below:

What is logged to the console'

Answer: C


NEW QUESTION # 126
Given the following code:
let x = ( ' 15 ' + 10) * 2;
What is the value of x?

Answer: D

Explanation:
Comprehensive and Detailed Explanation:
Evaluate step by step:
* ' 15 ' + 10
* + with a string operand performs string concatenation.
* 10 is coerced to ' 10 ' .
* Result: ' 1510 ' .
* ' 1510 ' * 2
* * always performs numeric multiplication.
* ' 1510 ' is converted to the number 1510.
* 1510 * 2 = 3020.
So x is 3020.


NEW QUESTION # 127
......

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