2026 Oracle 1z1-071: Valid Test Oracle Database SQL Passing Score

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Oracle 1z1-071 Exam Syllabus Topics:

Section	Objectives
Topic 1: SQL Functions	- Single-row functions 1. Character, numeric, date functions - Conversion and conditional functions 1. TO_CHAR, TO_NUMBER, CASE expressions
Topic 2: SQL Retrieval	- SELECT statements and filtering data 1. WHERE clause and conditions 2. ORDER BY and row limiting - Joins and set operations 1. INNER, OUTER, CROSS joins 2. UNION, INTERSECT, MINUS
Topic 3: Relational Database Concepts	- Tables, rows, columns, and relational model basics - Data types and database objects overview
Topic 4: Subqueries and Advanced SQL	- Single-row and multi-row subqueries - Correlated subqueries and nested queries
Topic 5: Data Manipulation and Schema Objects	- DML operations 1. INSERT, UPDATE, DELETE, MERGE - DDL operations 1. CREATE, ALTER, DROP tables and constraints

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Oracle Database SQL Sample Questions (Q222-Q227):

NEW QUESTION # 222
View the Exhibit and examine the data in the PRODUCTS table. (Choose the best answer.)

You must display product names from the PRODUCTS table that belong to the 'Software/other' category with minimum prices as either $2000 or $4000 and with no unit of measure.
You issue this query:
SQL > SELECT prod_name, prod_category, prod_min_price FROM products
Where prod_category LIKE '%Other%' AND (prod_min_price = 2000 OR prod_min_price = 4000) AND prod_unit_of_measure <> ' '; Which statement is true?

A. It generates an error because the condition specified for the PROD_CATEGORY column is not valid.
B. It executes successfully but returns no result.
C. It generates an error because the condition specified for PROD_UNIT_OF_MEASURE is not valid.
D. It executes successfully and returns the required result.

Answer: B

NEW QUESTION # 223
Examine the structure of the BOOKS_TRANSACTIONS table:
You want to display the member IDs, due date, and late fee as $2 for all transactions.
Which SQL statement must you execute?

A. SELECT member_id 'MEMBER ID', due_date 'DUE DATE', '$2 AS LATE FEE' FROM BOOKS_TRANSACTIONS;
B. SELECT member_id AS MEMBER_ID, due_date AS DUE_DATE, $2 AS LATE_FEE
FROM BOOKS_TRANSACTIONS
C. SELECT member_id AS "MEMBER ID", due_date AS "DUE DATE", '$2' AS "LATE FEE" FROM BOOKS_TRANSACTIONS
D. SELECT member_id AS "MEMBER ID", due_date AS "DUE DATE", $2 AS "LATE FEE" FROM BOOKS_TRANSACTIONS

Answer: C

NEW QUESTION # 224
Examine the structure of the BOOKS_TRANSACTIONStable:

You want to display the member IDs, due date, and late fee as $2 for all transactions.
Which SQL statement must you execute?

A. SELECT member_id AS "MEMBER ID", due_date AS "DUE DATE", $2 AS "LATE FEE" FROM BOOKS_TRANSACTIONS;
B. SELECT member_id 'MEMBER ID', due_date 'DUE DATE', '$2 AS LATE FEE' FROM BOOKS_TRANSACTIONS;
C. SELECT member_id AS MEMBER_ID, due_date AS DUE_DATE, $2 AS LATE_FEE FROM BOOKS_TRANSACTIONS;
D. SELECT member_id AS "MEMBER ID", due_date AS "DUE DATE", '$2' AS "LATE FEE" FROM BOOKS_TRANSACTIONS;

Answer: D

NEW QUESTION # 225
The CUSTOMERS table has the following structure:
You need to write a query that does the following tasks:
1. Display the first name and tax amount of the customers. Tax is 5% of their credit limit.
2. Only those customers whose income level has a value should be
considered.
3. Customers whose tax amount is null should not be considered.
Which statement accomplishes all the required tasks?

A. Which statement accomplishes all the required tasks? SELECT cust_first_name, cust_credit_limit
* .05 AS TAX_AMOUNT FROM customers WHERE cust_income_level IS NOT NULL AND tax_amount IS NOT NULL;
B. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNT FROM customers WHERE cust_income_level IS NOT NULL AND cust_credit_limit IS NOT NULL;
C. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNT FROM customers WHERE (cust_income_level,tax_amount) IS NOT NULL;
D. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNT FROM customers WHERE cust_income_level <> NULL AND tax_amount <> NULL;

Answer: B

NEW QUESTION # 226
View the exhibit and examine the ORDERStable.

The ORDERStable contains data and all orders have been assigned a customer ID. Which statement would add a NOTNULLconstraint to the CUSTOMER_IDcolumn?

A. ALTER TABLE orders
ADD customer_id NUMBER(6)CONSTRAINT orders_cust_id_nn NOT NULL;
B. ALTER TABLE orders
MODIFY customer_id CONSTRAINT orders_cust_nn NOT NULL (customer_id);
C. ALTER TABLE orders
ADD CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);
D. ALTER TABLE orders
MODIFY CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);

Answer: B

NEW QUESTION # 227
......

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