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| Section | Objectives |
|---|---|
| Topic 1: View Building with SwiftUI | - Create multiple Views to implement app logic - Extract Subviews to simplify the structure of an overlarge View - Position and/or layout a single SwiftUI View with standard Views and modifiers - Create a multi-view app with navigation Stacks, Links, and/or Sheets - Use @State, @Binding, @Environment, and/or Observable to share data between Views - Use List Views to iterate through collections |
| Topic 2: Swift Programming Language | - Demonstrate the use of Optional types
- Know how and when to apply control flow and loops
|
| Topic 3: Xcode Developer Tools | - Use debugging techniques including, but not limited to, breakpoints, watchpoints, and logging to resolve errors
|
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質問 # 24
Which property wrapper allows you to read data from the system or device settings?
正解：D
解説：
Comprehensive and Detailed Explanation From App Development with Swift domains:
This question belongs to View Building with SwiftUI , specifically the objective about using property wrappers such as @State, @Binding, and @Environment to manage and share data between views.
The correct answer is @Environment because it is used to read values provided by the system or the surrounding view environment. These values can include device-related or system-provided information such as size classes, color scheme, locale, and dismiss actions. In SwiftUI, @Environment gives a view access to contextual information that it does not own directly, but which is supplied by the framework or ancestor views.
The other options are not correct for this purpose:
* @State is used for local mutable state owned by the current view.
* @Binding is used to create a two-way connection to state owned elsewhere, usually in a parent view.
* @StateObject is used to create and own an observable reference-type object for the lifetime of the view.
So if you want a SwiftUI view to read data coming from system or device settings, the correct property wrapper is @Environment .
質問 # 25
Select the location to set this app to run on an iPhone 14 in the simulator.
正解：
解説：
Explanation:
This question belongs to Xcode Developer Tools , specifically the domain for building and running an app on the iOS simulator . In Xcode, the place where you choose whether the app runs on a simulator or a connected device is the run destination / scheme destination selector in the toolbar. This control appears near the top center of the Xcode window and displays the current destination, such as a simulator model or device target. To run the app on iPhone 14 , you click that selector and choose iPhone 14 from the available simulator list. Apple's Xcode documentation describes choosing a run destination before building and running the app in Simulator or on a device.
So, for the hotspot, the correct place is the device/simulator dropdown in the top toolbar , not the preview canvas controls, not the project navigator, and not the code editor. That selector determines where the app launches when you press Run.
質問 # 26
Review the code.
var capitalCities = [ " USA " : " Washington D.C. " , " Spain " : " Madrid " , " Peru " : " Lima " ] Which two statements add the capital city of " Italy " to the dictionary? (Choose 2.)
正解：B、C
解説：
Comprehensive and Detailed Explanation From App Development with Swift domains:
This question falls under Swift Programming Language , specifically the domain for managing data using collection types , with emphasis on dictionaries . In Swift, a dictionary stores data as key-value pairs , so in this example the country name is the key and the capital city is the value. To add a new entry, Swift supports two standard approaches. The first is subscript assignment , which is shown in option C : capitalCities[ " Italy " ] = " Rome " . Apple's documentation explains that you can add a key-value pair to a dictionary by assigning a value for a new key through the dictionary subscript.
The second correct approach is option E : capitalCities.updateValue( " Rome " , forKey: " Italy " ). Apple documents that updateValue(_:forKey:) updates the value for an existing key, or adds a new key-value pair if the key does not already exist . That makes it equally valid for inserting " Italy " : " Rome " into the dictionary.
The incorrect options fail for different reasons. A reverses the key and value, making " Rome " the key and " Italy " the value. B is wrong because append is used with arrays, not dictionaries. D is not the standard valid insertion syntax for Swift dictionaries in this context; Swift's documented mutation approaches here are subscript assignment and updateValue. Therefore, the two correct answers are C and E .
質問 # 27
Review the code snippet and identify what happens when the program is executed.
正解：C
解説：
This question belongs to Swift Programming Language , specifically the objectives covering arrays , loops
, and range operators . The array has 6 elements, so menuItems.count is 6. The loop uses the half-open range operator:
for index in 1.. < (menuItems.count - 1)
That becomes:
for index in 1.. < 5
In Swift, the half-open range operator a.. < b includes the lower bound but does not include the upper bound.
So this loop runs with index values 1, 2, 3, 4, not 0 and not 5.
Array subscripting uses those indexes to print:
* menuItems[1] # " Burger "
* menuItems[2] # " Chicken "
* menuItems[3] # " Pasta "
* menuItems[4] # " Salad "
That means " Pizza " at index 0 is skipped, and " Steak " at index 5 is also skipped. Swift arrays use zero- based indexing, and count returns the number of elements in the array.
Therefore, the program prints only " Burger " , " Chicken " , " Pasta " , and " Salad " , so the correct answer is A .
質問 # 28 
Which two assignments of a value to direction are allowed? (Choose 2.)
正解：B、D
解説：
This question belongs to Swift Programming Language , specifically the domain covering basic Swift types and how Swift handles enumerations . The code defines an enum named CompassPoint with the cases north, south, east, and west, and then declares direction as type CompassPoint. In Swift, an enum case can be assigned using the fully qualified form CompassPoint.north, so B is valid. Swift also allows the shorthand form .north when the compiler already knows the expected type is CompassPoint, so D is also valid. Apple's Swift language documentation explains that once a variable is known to be of a specific enumeration type, you can set its value using the shorter dot syntax.
The other options are not allowed. A is invalid because enum cases are not assigned using constructor-style syntax like CompassPoint(north). C is invalid because north by itself is not enough unless it is written with dot shorthand in a context with inferred enum type. E is invalid because north is a case of the enum type, not a member accessed from the variable instance as direction.north. Swift enum cases are referenced from the enum type or by shorthand dot syntax, not as instance properties.
質問 # 29
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