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With the Salesforce JavaScript-Developer-I certification exam you will get an opportunity to learn new and in-demand skills. In this way, you will stay updated and competitive in the market and advance your career easily. To do this you just need to pass the Salesforce Certified JavaScript Developer (JS-Dev-101) JavaScript-Developer-I Certification Exam.
| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I |
| Exam Number: | JS-Dev-001 |
| Available Languages: | English |
| Passing Score: | 65% |
| Exam Price: | USD 200 (may vary by region/tax) |
| Real Exam Qty: | 60 |
| Exam Duration: | 105 minutes |
| Exam Format: | Multiple Choice, Multiple Select |
| Related Certifications: | Salesforce Certified JavaScript Developer I Salesforce Certified Platform Developer I Salesforce Certified Platform App Builder |
| Certificate Validity Period: | 1 year (maintenance required via Salesforce certification maintenance modules) |
| Recommended Training: | Salesforce Developer Learning Paths Salesforce Trailhead JavaScript Developer I Prep |
| Exam Registration: | Salesforce Certification Registration (Webassessor) Salesforce Credentials Page |
| Sample Questions: | Salesforce JavaScript-Developer-I Sample Questions |
| Exam Way: | Online proctored or onsite testing via Kryterion Webassessor |
| Pre Condition: | No formal prerequisites, but familiarity with JavaScript and Salesforce platform development is strongly recommended. |
| Official Syllabus URL: | https://trailhead.salesforce.com/credentials/javascriptdeveloper1 |
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Salesforce JavaScript-Developer-I (Salesforce Certified JavaScript Developer I) Exam is a certification exam that is designed to test the skills and knowledge of developers who use JavaScript in the Salesforce platform. Salesforce Certified JavaScript Developer (JS-Dev-101) certification is ideal for developers who are looking to demonstrate their expertise in using JavaScript to build custom applications, automate business processes, and enhance the user experience in Salesforce.
NEW QUESTION # 25
Refer to the code below:
Function changeValue(obj) {
Obj.value = obj.value/2;
}
Const objA = (value: 10);
Const objB = objA;
changeValue(objB);
Const result = objA.value;
What is the value of result after the code executes?
Answer: A
NEW QUESTION # 26
A developer has the following array of hourly wages:
Let arr = (8, 5, 9, 75, 11, 25, 7, 75, , 13, 25);
For workers making less than $10 an hour rate should be multiple by 1.25 and returned in a new array.
How should the developer implement the request?
Answer: A
NEW QUESTION # 27
A developer initiates a server with the file server.js and adds dependencies in the source code ' s package.json that are required to run the server.
Which command should the developer run to start the server locally?
Answer: A
Explanation:
Comprehensive and Detailed Explanation From JavaScript/Node.js Knowledge:
In a Node.js project that uses package.json, you typically define a " start " script:
{
" scripts " : {
" start " : " node server.js "
}
}
Then you start the app with:
npm start
npm start:
* Looks up the " start " script in package.json.
* Runs the command defined there (commonly node server.js).
* This is the standard way to start a Node.js app with npm-managed dependencies.
Why others are incorrect:
* A. node start
* Tries to run a file named start with Node; does not use package.json scripts.
* C. npm start server.js
* npm start does not take the script filename as an argument in this way; it just runs the start script as defined.
* D. start server.js
* Not an npm or node command; on some shells it just tries to "start" a process but is not the standard Node/npm workflow.
Relevant concepts: package.json, npm scripts, npm start, Node entry file execution.
NEW QUESTION # 28
Refer to the following code block:
01 let array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11];
02 let output = 0;
03
04 for (let num of array) {
05 if (output > 10) {
06 break;
07 }
08 if (num % 2 == 0) {
09 continue;
10 }
11 output += num;
12 }
What is the value of output after the code executes?
Answer: B
Explanation:
This code uses:
* A for...of loop to iterate over values in array.
* break to exit the loop entirely when output > 10.
* continue to skip even numbers.
* It sums only certain numbers into output.
Let's walk through the loop step by step.
Initial values:
* array = [1,2,3,4,5,6,7,8,9,10,11]
* output = 0
Loop: for (let num of array) { ... }
* First iteration: num = 1
* Line 05: if (output > 10) # 0 > 10 is false # no break.
* Line 08: if (num % 2 == 0) # 1 % 2 == 1, not 0, so false # no continue.
* Line 11: output += num # output = 0 + 1 = 1.
* Second iteration: num = 2
* output > 10 # 1 > 10 is false # no break.
* num % 2 == 0 # 2 % 2 == 0, so true # continue.
* Because of continue, line 11 is skipped.
* output remains 1.
* Third iteration: num = 3
* output > 10 # 1 > 10 is false.
* num % 2 == 0 # 3 % 2 == 1, false # no continue.
* output += num # output = 1 + 3 = 4.
* Fourth iteration: num = 4
* output > 10 # 4 > 10 is false.
* num % 2 == 0 # 4 % 2 == 0, true # continue.
* Skip sum; output remains 4.
* Fifth iteration: num = 5
* output > 10 # 4 > 10 is false.
* num % 2 == 0 # 5 % 2 == 1, false.
* output += num # output = 4 + 5 = 9.
* Sixth iteration: num = 6
* output > 10 # 9 > 10 is false.
* num % 2 == 0 # 6 % 2 == 0, true # continue.
* output remains 9.
* Seventh iteration: num = 7
* output > 10 # 9 > 10 is false.
* num % 2 == 0 # 7 % 2 == 1, false.
* output += num # output = 9 + 7 = 16.
* Eighth iteration would be num = 8, but:
At the top of the loop body, line 05 is checked again:
* if (output > 10) # 16 > 10 is true, so break; is executed.
When break runs:
* The loop terminates immediately.
* No further iterations (for num = 8, 9, 10, 11) are executed.
* Therefore, output stays at 16.
Final value of output after the loop ends is 16.
This matches option A.
Why other options do not match:
* B. 25: Would require adding more odd numbers (e.g., 9, 11) after 7, but the loop stops early due to output > 10.
* C. 11: Would be smaller; the actual sum of 1 + 3 + 5 + 7 until break is 16.
* D. 36: Would require summing many more values (e.g., most or all odd numbers up to 11), but again, the break condition stops the loop once output exceeds 10.
So:
The answer: A
JavaScript knowledge / Study Guide references (concept names only, no links):
* for...of loop over arrays
* break statement in loops (terminating a loop early)
* continue statement in loops (skipping to the next iteration)
* Modulo operator % to test even and odd numbers
* Step-by-step execution and control flow in loops
NEW QUESTION # 29
const str = ' Salesforce ' ;
Which two statements result in the word " Sales " ?
Answer: A,D
Explanation:
Comprehensive and Detailed Explanation:
* " Salesforce " indices: S(0) a(1) l(2) e(3) s(4) f(5) ...
A / C (substring(0, 5)):
* substring(start, end) returns characters from start up to but not including end.
* str.substring(0, 5) # characters at indices 0,1,2,3,4 # " Sales " .
D (substr(0, 5)):
* substr(start, length) returns length characters starting at start.
* str.substr(0, 5) # 5 chars from index 0 # " Sales " .
B is invalid because s is not defined; it should be 0. So the two correct statements are A and D.
NEW QUESTION # 30
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